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Sir i spotted a mistake at 3:48 It's (d/dz) ^2 = -(gama)^2 Otherwice we ain't be able to substitute as h^2 = w^2uE - gama^2 As square root of - sign is j(complex) And in single derivative -sign comesf from e^-w^2uE Am I correct sir?
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Detailly derive the result and conclude the topic. Thanks very much.
Your positive comments motivates me.
Teachers like me just wants positive comment from student.
Love from you guys means a lot to me.
My goal is to create largest community of engineers in entire globe. Please help me by sharing this playlist with your friends.
Sir i spotted a mistake at 3:48
It's (d/dz) ^2 = -(gama)^2
Otherwice we ain't be able to substitute as
h^2 = w^2uE - gama^2
As square root of - sign is j(complex)
And in single derivative -sign comesf from e^-w^2uE
Am I correct sir?
It is perfectly correct here
yeah this is where my dbt is also
Sir please make videos on analog electronics and satellite communication
It will take time
@@EngineeringFunda thank you so much sir
Thank you sir I really understood 🤩
Your positive comments motivates me.
Teachers like me just wants positive comment from student.
Love from you guys means a lot to me.
My goal is to create largest community of engineers in entire globe. Please help me by sharing this playlist with your friends.
@@EngineeringFunda I'll share to all my network sir, U r really my saviour I don know y I pay my tuition fee for my institue....I'd love to pay for Engg. funda instead....like my whole engg. semesters are filled with ur playlists sir.
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16:00 nothing can propagate in z direction in the case of TEM mode ###
This falls apart in the end because you divide by zero... because gamma = omega*sqrt(eps*mu) for TEM.
If I don't fully derive in exam and do only specified in the video , will I get complete marks
You can try it, but it's best to practice fully deriving it.
Sir your app is not working
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