The hardest part of this question was the mole calculation of 1.0 x (50x10^-3), definitely need a calculator for this part!! Also, for those of you wondering why I didn't go through the examiner's report, this was a 2020 paper so doesn't have one :(
this was so helpful!! but for the last bullet point i dont really understand. is this something i should just learn and know when to use in a question?
The last bullet point is not something you have to memorise, but you do need to memorise the equation for E = E(red) - E(ox). Sorry if I explained this poorly, but since the question is asking you to show how the student knows the Electrode potential of the TiO2+/Ti cell is -0.88v, you have to use the equation I just mentioned, rearrange it and prove that everything adds up correctly (I hope that makes sense! It's hard to explain by text). Remember that the NOPR rule (or NOPRoblem rule you might hear it called) states that the more negative half cell is oxidised, and the more positive half cell is reduced, so if we use the E = E(red) - E(ox) equation to find out E, plugging in the E(red) of +0.34v, and the E(ox) of -0.88v, this gives a total E for the cell of 1.22v. If you measure the E of the cell, and it is indeed 1.22v, then you know for a fact that the TiO2+/Ti half cell is indeed -0.88v. let me know if that helps at all 😅
I think it's because TiOSO4 is a solid we assume the volume of solution remains constant. Bit silly I know, but I always just learned it this way. Sorry I couldn't be more helpful.
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The hardest part of this question was the mole calculation of 1.0 x (50x10^-3), definitely need a calculator for this part!!
Also, for those of you wondering why I didn't go through the examiner's report, this was a 2020 paper so doesn't have one :(
you deserve the world by helping students xx
this is so useful, thank you!
Second bullet point.. why 50 mol dm^-3 of sulfuric acid?
this was so helpful!! but for the last bullet point i dont really understand. is this something i should just learn and know when to use in a question?
The last bullet point is not something you have to memorise, but you do need to memorise the equation for E = E(red) - E(ox). Sorry if I explained this poorly, but since the question is asking you to show how the student knows the Electrode potential of the TiO2+/Ti cell is -0.88v, you have to use the equation I just mentioned, rearrange it and prove that everything adds up correctly (I hope that makes sense! It's hard to explain by text).
Remember that the NOPR rule (or NOPRoblem rule you might hear it called) states that the more negative half cell is oxidised, and the more positive half cell is reduced, so if we use the E = E(red) - E(ox) equation to find out E, plugging in the E(red) of +0.34v, and the E(ox) of -0.88v, this gives a total E for the cell of 1.22v.
If you measure the E of the cell, and it is indeed 1.22v, then you know for a fact that the TiO2+/Ti half cell is indeed -0.88v. let me know if that helps at all 😅
Wouldnt adding TiOSO4 to the 50cm solution increase the volume? therefore the conc wont be 1 mol dm-3?
I think it's because TiOSO4 is a solid we assume the volume of solution remains constant. Bit silly I know, but I always just learned it this way. Sorry I couldn't be more helpful.
thanks boss
no worries haha
This question is very hard...
If a question like this comes up this year I will be lucky to get 1 mark
You've got this 😁Believe in yourself!
@@easymodeexams33 Thanks sir, I'm going to watch all the vids because they are really good