Great video, and the trick at the end, transforming cartesian to polar coordinates to have one less variable to worry about and approach (0,0) “from all directions”, is really cool!
Nice presentation. First commendation is the figure at the beginning that shows a discontinuity in a surface over the domain R^2, which really brings home the bivalent situation at the discontinuity. You cover the topic (which is a standard one) and include all the usual points, including the transformation to polar coordinates. When you mention applying L'Hôpital's rule, valid on domain R, the series expansion of the function is (at least) implied, and this is also valid in domains beyond R. With the function you chose, the linear term is sufficient to show the limit exists, unless I'm forgetting something important.
Thank you so much, this really made helped understand how to solve basically any kind of problem like this and also how to make functions continuous in certain points!
Great video, and the trick at the end, transforming cartesian to polar coordinates to have one less variable to worry about and approach (0,0) “from all directions”, is really cool!
Great video! Very underated channel with amazing quality. Love from Portugal
Thank you, Miguel! So glad you have been enjoying this content :)
Beautiful video, loved the visuals(graphs,3d), they help me understand faster... thank you suur!
Nice presentation. First commendation is the figure at the beginning that shows a discontinuity in a surface over the domain R^2, which really brings home the bivalent situation at the discontinuity. You cover the topic (which is a standard one) and include all the usual points, including the transformation to polar coordinates. When you mention applying L'Hôpital's rule, valid on domain R, the series expansion of the function is (at least) implied, and this is also valid in domains beyond R. With the function you chose, the linear term is sufficient to show the limit exists, unless I'm forgetting something important.
Thank you so much, this really made helped understand how to solve basically any kind of problem like this and also how to make functions continuous in certain points!
honestly the goat
you're really good at explaining, thank you for all your help!
Arigato gozaimuch for the wonderful explanations
Very helpful video with a very good explanation thank you so much
really good explanation! thanks
Last example: would it be legal to make a substitution z=x^2+y^2, without transforming to polar coordinates?
Yes, that's fine. This works because (x,y)->(0,0) if and only if x^2+y^2 -> 0. Effectively, this is the same as transforming to polar coordinates.
you are so good
Thank you🎉
Awesome ❤
How do we know the best paths to take?
same qst
Thank you so much
Hey i checked your video before this but I couldn't see anything about x^2 + y^2 = p^2? where do I find these cartesian to polar conversions?
The conversion between Cartesian and polar coordinates are discussed here: th-cam.com/video/_MXTd_ZUKFg/w-d-xo.html
@@mathemation Thanks for the quick reply! You're awesome! Subbed
love you
💛
Tristan tate made a math vid