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I don't foresee needing this formula, but if I do need it, I know where to find it.Thanks
Thanks for this, I find the internet is getting more and more cluttered. Hard to find good information.
Good stuff, as always!
nice work
Id go through the integration to calculate it but nice to have the answer handy
Painting corrugated area resonates.
VERY GOOD!
A better example would be figuring the Road Distance on a Road Map or Topo Map which is what I thought this video was about.
is this formula exact or a close enough approximation? if it's exact, it's interesting that it's simply a function of amplitude/wavelength ratio.
How did you find it? Is it used for light distance within a toslink cable?
for y=f(x): L = integral[x=x0..x1](sqrt((dx)^2+(dy)^2)= integral[x=x0..x1]( sqrt(1+f'(x)^2) * dx ).
ANd for your next number: Invent CALCULUS!
I don't foresee needing this formula, but if I do need it, I know where to find it.
Thanks
Thanks for this, I find the internet is getting more and more cluttered. Hard to find good information.
Good stuff, as always!
nice work
Id go through the integration to calculate it but nice to have the answer handy
Painting corrugated area resonates.
VERY GOOD!
A better example would be figuring the Road Distance on a Road Map or Topo Map which is what I thought this video was about.
is this formula exact or a close enough approximation? if it's exact, it's interesting that it's simply a function of amplitude/wavelength ratio.
How did you find it? Is it used for light distance within a toslink cable?
for y=f(x): L = integral[x=x0..x1](sqrt((dx)^2+(dy)^2)
= integral[x=x0..x1]( sqrt(1+f'(x)^2) * dx ).
ANd for your next number: Invent CALCULUS!