How did you determine triangle 📐 BXG is a right triangle? When you split angle B down the center to create triangle 📐 BXG, angle B becomes 45deg, making the triangle a non right triangle
Ive been scratching my head why I'm wrong Fgf I got was in tension and in your notes it says Compression. I got the same value as well and I double checked and I'm pretty sure its right idk. I used the right side of the diaram.
GF in in tension, not compression. -24cos30 + 13.85cos60 + GF = 0
-20.785 + 6.925 + GF = 0
-13.85 + GF = 0
GF = 13.85 Tension
Thank you it help me alot God bless you🥰
Welcome dear. God bless you too
How did you determine triangle 📐 BXG is a right triangle? When you split angle B down the center to create triangle 📐 BXG, angle B becomes 45deg, making the triangle a non right triangle
Ive been scratching my head why I'm wrong Fgf I got was in tension and in your notes it says Compression. I got the same value as well and I double checked and I'm pretty sure its right idk.
I used the right side of the diaram.
I checked your diagram and the forces in the x dont sum to 0.
If you need any help. Kindly ask
Thank you very much
You are welcome dear
Fgc= - 27.7
Fgf=+ 20.8. book me answer ye bta rha please check and response
Fbc = - 24 ye sahi h..
.
thanks alot for the answer , i wasted whole 4 hrs on it
God bless you
Hajur GF would be tension hoi
If the section cut 2 member of a truss,, is it ok??
Yes
Thanks sir best sol
God bless you dear
Hi, would I be able to contact to privately
Hello dear. My email id is kashmirsinghghatorha@gmail.com
You can ask your doubts here.