I think it's made like that because it's assumed everything is in tension, which is why when you plug in your answers depending weather the answer is positive or negative will tell you If it's in tension or compression.
Yeah i think it is negative and I change the final answer on his example. Maybe he mistakably thinks that it is Fy so he make it positive instead of Fx which is negative.
Thankyou for your reply...that was my doubt a month bfr..now It is clear.. Force in ED is an internal member force and need not consider when solving for other member forces...😅..
@@ertugrulcam5142 Just relax... A 3 stepped cantilever beam with 2 parallel loads at each step with same magnitude and an axial load at free end (3rd step) would be a great example for understanding the internal member forces..Assume a cut made in any of the section...for that section to be in equilibrium it must develope internal forces(= left or right side external force)..this internal force divided by area is the stress developed by that section due to external load..similarly every section of the beam will develope this internal member force depending on the external force it need to balance... And for calculating this internal force at a section we are considering only the external forces it have to balance so that it will be in equilibrium not the other internal member forces...(since every member is stressed all section must have developed internal forces) The same equilibrium concept is used in truss...while considering the members at the cut section..we have to worried only about the external forces not the other member force...Hope it is clear..
ENGISSOL 2D Truss Analysis software features a powerful finite element solver to analyze trusses consisting of elements with rotational releases at their both ends. The deformed configuration under external loads is calculated and the axial force diagram of the structure provided by the user is represented. The creation of the model is an easy and quick task as the user can take advantage of the intelligent user interface of the software. Its versatile graphical user interface, the predifend libraries and many other available features can save you time and effort. Moreover, the program also supportes non-linear static analysis (second order analysis) for the consideration of P-Delta effects.
Great example, really clear reasoning
Thanks a lot many had confused me but finally you made everything clear for me.........!!!!
What is the name of the textbook he is using
thanks bro very good and very clear well done 👍
never thought of using both method simultaneously ..thanks a lot ...subscribed
Name of textbook he is using
Very informative an intuitive coming from an architecture student...
Very much appreciated!!!!!!!
thank u so much sir these become very helpful
This helped Thank you
why you didn't put negative at FCB since its going negative axis
the guy kept on explaning for us even ignored his wife's call 😮👏👏
what a chad
So there's no need to calculate the support reactions at A
thank you very much sir.
Great
thanks i need it for exam :D
At 10:18 it says “...plus the force C to B in the negative X direction”, yet FCB remains positive. Please explain how so. Thanks.
I think it's made like that because it's assumed everything is in tension, which is why when you plug in your answers depending weather the answer is positive or negative will tell you If it's in tension or compression.
Yeah i think it is negative and I change the final answer on his example. Maybe he mistakably thinks that it is Fy so he make it positive instead of Fx which is negative.
Why need to keep use negative value of Fef instead just use the one that has been change to the positive value to Fcb
Thank you very much sir
Thank you so much sir!
What if put the force Dy downward? FEF would be positive and that indicates it's in tension which is wrong !
the rollers are always directed towards it not away from it. that's why it is upward force
the rollers are always directed towards it not away from it. that's why it is upward force
Not getting square root of 2
Please name of textbook
Live long
Why the Member ED was not taken into consideration for Fy= 0!
Roller support at D?
Thankyou for your reply...that was my doubt a month bfr..now It is clear.. Force in ED is an internal member force and need not consider when solving for other member forces...😅..
@@ertugrulcam5142 Just relax...
A 3 stepped cantilever beam with 2 parallel loads at each step with same magnitude and an axial load at free end (3rd step) would be a great example for understanding the internal member forces..Assume a cut made in any of the section...for that section to be in equilibrium it must develope internal forces(= left or right side external force)..this internal force divided by area is the stress developed by that section due to external load..similarly every section of the beam will develope this internal member force depending on the external force it need to balance...
And for calculating this internal force at a section we are considering only the external forces it have to balance so that it will be in equilibrium not the other internal member forces...(since every member is stressed all section must have developed internal forces)
The same equilibrium concept is used in truss...while considering the members at the cut section..we have to worried only about the external forces not the other member force...Hope it is clear..
why did you use sqr root of 2
apply pythagoras rule and you will end up with >>> 3 and 3 and (3 sqr 2) ...... if you divide 'em all by 3 you will end up with 1 and 1 and (sqr2)
c square =a square plus b square there fore if you have 1 for adjacent and 1 for opposite , hypotenuse will be square root of 2
@@TheGoblenx how to get 1?
ENGISSOL 2D Truss Analysis software features a powerful finite element solver to analyze trusses consisting of elements with rotational releases at their both ends. The deformed configuration under external loads is calculated and the axial force diagram of the structure provided by the user is represented. The creation of the model is an easy and quick task as the user can take advantage of the intelligent user interface of the software. Its versatile graphical user interface, the predifend libraries and many other available features can save you time and effort. Moreover, the program also supportes non-linear static analysis (second order analysis) for the consideration of P-Delta effects.