You should expand on this problem and solve for the FS against overturning as well. If you were to solve for the overturning FS, would the 25 degree friction angle affect it?
The CERM states that Ra=(1/2)*ka*gamma*H^2 not Ra,h. Why can you use that formula for Ra,h? It seems like we need to use that equation to find Ra and find the component of Ra,h. Also the CERM states that the equation for Rsl is Rsl=(sum of the weights + Ra,v)*tan(phi). You somehow took a shortcut that just multiplied the weight by the tangent of delta. I don't see the equation anywhere. How did you derive that? Thanks.
Because there is an angle of external friction should the Coulomb equation be used to find Ka? I thought tan^2(45-X/2) was a Rankine equation that disregards friction.
150 pcf is the typical weight used for reinforced concrete. Plain concrete is 145. Typically, both numbers are used. This is the difference. Annoyed me for years to see both without explanation. Just fyi for other viewers.
+Akshay Shrestha if it isn't given then they should give you what you need to either solve for what you need or it wouldn't be needed as part of the problem.
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You should expand on this problem and solve for the FS against overturning as well. If you were to solve for the overturning FS, would the 25 degree friction angle affect it?
Since we have an angle of external friction, shouldn't we have used the Coulomb equation 37.5 to find Ka? Can someone explain?
The CERM states that Ra=(1/2)*ka*gamma*H^2 not Ra,h. Why can you use that formula for Ra,h? It seems like we need to use that equation to find Ra and find the component of Ra,h. Also the CERM states that the equation for Rsl is Rsl=(sum of the weights + Ra,v)*tan(phi). You somehow took a shortcut that just multiplied the weight by the tangent of delta. I don't see the equation anywhere. How did you derive that? Thanks.
Because there is an angle of external friction should the Coulomb equation be used to find Ka? I thought tan^2(45-X/2) was a Rankine equation that disregards friction.
great job. simple and straight to the point. please upload more videos.
beautiful example, thank you Isaac
150 pcf is the typical weight used for reinforced concrete. Plain concrete is 145. Typically, both numbers are used. This is the difference. Annoyed me for years to see both without explanation. Just fyi for other viewers.
KnowJesusKnowPeace Thanks for the great explanation I'm sure others appreciate it too!
Great job on the video. Keep them up please!
shouldn't Ra be in lb/ft, since gamma is pcf thats (ft^3) *(ft^2) which leaves you with ft
I believe we have to assume to be looking a 1 foot section of the wall
What about the weight of soil on the other wall side??
+Ahmed AlBayati There isn't any soil on the other side.
good exercise, keep going
what if delta is not given in the question?
+Akshay Shrestha if it isn't given then they should give you what you need to either solve for what you need or it wouldn't be needed as part of the problem.
Thank you!
Ka=(1-sin25)/(1+sin25) =tan^2(45-12.5)= 0.4058, I do not know .Am I wrong?
sin34 right?
I also got .4059 at this step
You should use angle=34, not 25
sir please upload strength o material video
You mean it's not b) ?