Your dedication to help students is priceless. I wish that every lecturer could be like you.For the solids series, lesson 22 is not available. Please resolve this issue.
I'm a sophomore at Cornell. Prospective MechE. One of my classmates told me to look this dude up. I feel like I've just found the ultra southern Professor Leonard of Engineering, and I'm fucking HERE for it. I'm going to survive statics if it kills me
this pandemic makes me have to study alone and im a first year so i havent attended offline class since i got into college and this channel helps me a lot 😭 thank u so much
Professor, when you take 8kNs for the calculation of elongation in A isn't there a (4+4) compression also acting there? total of forces going to the right (tension) is 10kNs and the total of forces going to the left (compression) is 10kNs. Is this how to calculate the total forces P in the points or am I wrong somewhere?
Hey Jeff, Ive been watching your solids lactures in preparation of the fall semester but I'm not able to view lectures 9, 10, or 12. I'm hoping you can sort that out so I don't miss anything, your videos have been very helpful
Hi, you can use axial load diagram to solve this even faster. You can take load at A as 8kn, load at B as 4kn, load at C as 6 kn and load at D as 2kn. Assume load going left as positive and loads moving right as negative. Axial load diagram would be as follows: +8kn. 8-4=4kn. 4-6=-2kn A. B. C. D When the -2kn reaches point D, it meets the left side moving load of 2kn. -2+2=0 Since there is no load as I explained above after point D, you do not need to calculate anything. If you still did not understand, let me know you email and o will send you a solution of this problem.
@@ahmaranees hey firstly thank you for responding my question. I still don’t get it. If it is no problem to send solution of question, you could send to erayerkul7@gmail.com Kind regards :)
Hi. He looks at one side of each section as we know it is in equilibrium. Forces will be equal on both sides of the imaginary midpoint squiggle he drew. On his first section he looked at (8kN) he looked at the left side as it was more simple. He then showed adding the right side did also equal 8kN to show this. I was confused at first also.
Your dedication to help students is priceless. I wish that every lecturer could be like you.For the solids series, lesson 22 is not available. Please resolve this issue.
watch more th-cam.com/video/nb2GNI9HqWc/w-d-xo.html
I'm a sophomore at Cornell. Prospective MechE. One of my classmates told me to look this dude up.
I feel like I've just found the ultra southern Professor Leonard of Engineering, and I'm fucking HERE for it.
I'm going to survive statics if it kills me
You explained this better than any lectures I was given. Thank you
Your videos are just lifesaver, theank you from the bottom of my heart
Best teacher i have ever seen
this pandemic makes me have to study alone and im a first year so i havent attended offline class since i got into college and this channel helps me a lot 😭 thank u so much
Thanks for all the great videos Professor Hanson
so do the two 2kN forces on section AB not matter? I'm confused why we didn't account for them anywhere
First comment! Thank you for all your videos! They've been so helpful getting through poor professors!
Dr. Hanson, you are fantastic. Thank you!!
Thank you for these videos you are saving me!
Jeff Hanson is the GOAT
Professor, when you take 8kNs for the calculation of elongation in A isn't there a (4+4) compression also acting there? total of forces going to the right (tension) is 10kNs and the total of forces going to the left (compression) is 10kNs. Is this how to calculate the total forces P in the points or am I wrong somewhere?
I was wondering this
That confused me too lol
youre the best. thank you🥰🥺🥺🙏🙏
This is Tutor Jeff who went to private school. Hanson waku lekafye 🙏🏼
Wonderful Lectures ! Thanks.
Thank you very mutch!! You have helped me so much!!
Any chance we can get a video dedicated to Bearing Stress?😁
Incredibly helpful
Hey Jeff, Ive been watching your solids lactures in preparation of the fall semester but I'm not able to view lectures 9, 10, or 12. I'm hoping you can sort that out so I don't miss anything, your videos have been very helpful
For sections AC and AD why didnt we add up the lengths of each section? Shouldnt length for section AC 6m and length for AD 8m?
Why we did not take these 2kN's for calculation? I am confused. If anyone knows the answer, pls reply it.Thank you!!
Hi, you can use axial load diagram to solve this even faster. You can take load at A as 8kn, load at B as 4kn, load at C as 6 kn and load at D as 2kn.
Assume load going left as positive and loads moving right as negative. Axial load diagram would be as follows:
+8kn. 8-4=4kn. 4-6=-2kn
A. B. C. D
When the -2kn reaches point D, it meets the left side moving load of 2kn. -2+2=0
Since there is no load as I explained above after point D, you do not need to calculate anything. If you still did not understand, let me know you email and o will send you a solution of this problem.
@@ahmaranees hey firstly thank you for responding my question. I still don’t get it. If it is no problem to send solution of question, you could send to erayerkul7@gmail.com
Kind regards :)
Hi. He looks at one side of each section as we know it is in equilibrium. Forces will be equal on both sides of the imaginary midpoint squiggle he drew. On his first section he looked at (8kN) he looked at the left side as it was more simple. He then showed adding the right side did also equal 8kN to show this. I was confused at first also.
@@ahmaranees I didnt understand, would you be happy to help me?
Wouldn't E=73100 Pa where did the mega come from. Shouldn't we divide by 1000^2
Do you mind making a video explaining the St Venats Principle
Will do!
How do u know which sections to cut
Galing mo talaga tanda
Dear professor, why you know which force is in tension and which force is in compression ? Thank you
if its going away from the cut, its in tension. if its going towards, then compression
Assume loads moving left as positive (tension) and loads moving right as negative ( compression )
What's the name of the book you're using? :)
thank you Jeff
thanks soo much for this
Why use 25 when the diameter of that section is 50mm?
radius is 25
Great!
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