I can’t believe that you still make videos man. You have helped me so much through university. It’s my first year at mcgill and i watch all your videos for literally every class, they always make sense when teach them. Thanks for everything.
This Guy is amazing, not only super intelligent, but he also has the ability to never overcomplicate things and gets directly to the point, you guys should feel lucky hes on youtube!!
When applying newtons theory of symmetrical motion, the time it takes to get from C to D should be equal to the amount of time to get from B to C. When calculating it, it does not come out as being equal, but the accurate flight time when applying this principle is different.
I have a question, why the acceleration which is the gravitational force in that case is negative? because i think the gravitational force is positive when the object is moving downward.
rockets direction is positive up on y axis in the first half, g force is pulling rocket down(opposite of rockets direction) that's why is shown as negative.
hey man just asking, why don't we take into account gravity from the first place? a rocket is accelerating 15m/s^2 towards the ground, but isn't it not affected by gravity just yet? or do we just assume that the rocket is being observed from someone on the ground, and accelerating 15m/s^2 thus it is already accounting for gravity?
In my day it was V=U + at , S=Ut + 1/2atsquared, V squared = U squared + 2aS……then it became V= U +ft and now its Vf = Vo + at. Oh well. Does dV/dt still equal a, or is it f ? Still it looks an interesting video 😊
awesome bro you are great my question is : if an aircraft goes verticaly upward with constant velocity how much G acceleration pilot feels? what about G acceleration when velocity in not constant? what about the situation when aircraft climbs or decends with 45 degree flight path angle?
I don't think it's possible to fly vertically upward with a constant velocity. Since you're always under the influence of gravity, thus, you will constantly feel an acceleration downward.
Can you help me out in this question the rocket is accelerating 15m/s^2 but it’s only accelerating 5.2m/s^2 because of retardation force acting on the rocket so the velocity at B would be 52m/s right?
@@vinayaksingh5680 I don't know the answer I have just started to study about rocket science in my free time and I've been busy with other stuff I just know the main parts of a rocket and how they work I know how to build a rocket engine and flight computer but I am not that good with math
I know it’s been a while but T ascent includes the time the rocket was still accelerating at a speed of 15 so therefore it is not equal to time of descent.
Hey can someone help me? Completely unrelated but how do u find thickness from gsm, density and the mass of the object. For example i have a screen with the mass of 100 mg, gsm for the screen is 500 g/m2 and density is 0.2 g/m3. Thx
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Physics PDF Worksheets: www.video-tutor.net/physics-basic-introduction.html
I can’t believe that you still make videos man. You have helped me so much through university. It’s my first year at mcgill and i watch all your videos for literally every class, they always make sense when teach them. Thanks for everything.
Thanks!
@@TheOrganicChemistryTutor please I want to know how you make the videos
@@Yeurtt_x1 He has a video on that. Please do some research before commenting.
@@jamesjudd1326 i cant find the video.. what is the video name
@@silversoul2785 Search my youtube equipment
This Guy is amazing, not only super intelligent, but he also has the ability to never overcomplicate things and gets directly to the point, you guys should feel lucky hes on youtube!!
wow this dude literally does everything, from precalculus to complex physics stuff, great vid man
This is complex? 9th grade questions..
This saved my life and made me understand physics THANK YOU
Sussy rocket..
Great vid as always
Oh fuck no
When applying newtons theory of symmetrical motion, the time it takes to get from C to D should be equal to the amount of time to get from B to C. When calculating it, it does not come out as being equal, but the accurate flight time when applying this principle is different.
Thanks. From Ethiopia
Sir, kindly make a video discussing the Fajans' rules.
Thank you so much 😊 you’re helping me in physics
Thank you Sir!
Thank you so much , l was waiting for a physics video!
I may be late but thank you still, mr. genius sir!
You're welcome, Mr commentor Sir
I love you, love the video. But the thumbnail kinda sus, just sayin'
“uhhh the thumbnail is pretty sus ☝🏻🤓”
Also bro make a video on how to study and do exam prep for maths and science, how do you remember and answer these difficult concepts in exams
My e-book discusses that already: www.video-tutor.net/
I have a question, why the acceleration which is the gravitational force in that case is negative? because i think the gravitational force is positive when the object is moving downward.
rockets direction is positive up on y axis in the first half, g force is pulling rocket down(opposite of rockets direction) that's why is shown as negative.
That rocket looking sus 👀
lmaoooo
You clicked because of the thumbnail
What software do you use to write the questions in form of a sentences?
Mass of a rocket is changing while engine is expelling gas and it’s very hard even with lpre to make it constant a
hey man just asking, why don't we take into account gravity from the first place? a rocket is accelerating 15m/s^2 towards the ground, but isn't it not affected by gravity just yet? or do we just assume that the rocket is being observed from someone on the ground, and accelerating 15m/s^2 thus it is already accounting for gravity?
i assume it is accelerating at 15 m/s² taking gravity into account, the problem should have mentioned that, if so
In my day it was V=U + at , S=Ut + 1/2atsquared, V squared = U squared + 2aS……then it became V= U +ft and now its Vf = Vo + at. Oh well.
Does dV/dt still equal a, or is it f ?
Still it looks an interesting video 😊
I recently started doing projectiles in physics and so far we've only been doing v=u+at, s=ut+1/2at^2, only the standard equations as well
@@chaosforever Can you prove them ? It’s fun.
awesome bro you are great
my question is : if an aircraft goes verticaly upward with constant velocity how much G acceleration pilot feels? what about G acceleration when velocity in not constant? what about the situation when aircraft climbs or decends with 45 degree flight path angle?
I don't think it's possible to fly vertically upward with a constant velocity. Since you're always under the influence of gravity, thus, you will constantly feel an acceleration downward.
Thanks for this
Hi. How do you record your animations… is is a screen recording of your ipad or how does it work?
Thanks 🙏 alot .man
💀
Don't need it right now but might in the future
You are my god
I am australian and I am in year 10 and I find rocket science easy
Can you help me out in this question the rocket is accelerating 15m/s^2 but it’s only accelerating 5.2m/s^2 because of retardation force acting on the rocket so the velocity at B would be 52m/s right?
@@vinayaksingh5680 I don't know the answer I have just started to study about rocket science in my free time and I've been busy with other stuff I just know the main parts of a rocket and how they work I know how to build a rocket engine and flight computer but I am not that good with math
sir I've a dbt , why can't we take T ascent = T descent and Add up to get total time of flight
I know it’s been a while but T ascent includes the time the rocket was still accelerating at a speed of 15 so therefore it is not equal to time of descent.
Hey can someone help me? Completely unrelated but how do u find thickness from gsm, density and the mass of the object. For example i have a screen with the mass of 100 mg, gsm for the screen is 500 g/m2 and density is 0.2 g/m3. Thx
Wow thanks
Bro do a face reveal
Please can anyone tell me how he make the videos ?
what if the rocket is at an angle?
Mujhe kyu aisa lag rha hai yeh adv mai aa sakta hai..
BRO i need help on somthing, reply on ig
Don't need it right now but might in the future