9 years later, and this is still the most useful video on this topic. So many others focus on how the formula is derived and use a generic function to prove it. That's all well and good, but doesn't come close to helping Calc students understand how to use it and solve HW/test questions. Thank you.
Glad it was helpful! I am so happy to see that my old videos are still going strong. I filmed that video in my room; I had a whiteboard on my wall and a old camcorder set up on a tall armoire.
This was awesome.!! 😃You managed to talk about a topic involving inverse functions without going back and forth between 'original function' and 'inverse function' multiple times and making it head-spinningly confusing. Congratulations!
Holy, what an incredible video thank you so much man. I've been looking at this topic now and scrolling through other videos and yours was so much clearer, hope you keep making more videos this was great, thank you!
Thank you for this video! Though im kind of confused for this type of question: Find (f^-1)'(a), if f(x) = x^3 + 2x + 3, and a = 0. Over here I tried applied the concepts of inverse functions where you can say that if f^-1(0) = a. Then f(a) = 0. However, it got me some decimal answer and I had to do some things that I'm not sure are allowed by the professors.
uhmm... i got confused. we are talking about INVERSE FUNCTION, it means f(x)=y and we should switch y for x then solve for y to have inverse function, then, we will take f' (y), finally, we will place 4 to the function we got. Is that right?
Yes.. But in cases where the function is difficult to separate, we can make use of this formula.. The formula can be proved by applying the Chain Rule to the definition of the inverse function.
The problem is that it s hard to take the inverse of such functions. What you have to do in those cases is to plug numbers until you find h(x)= the x value you re differentiating the function at... Then consider it as a y value for h(x)-1.
No, but it zero is an easy number to try though! Then I try 1, -1, etc. If the numbers get too crazy then you can use a calculator to find out when the function equals a particular value.
Glad it helped! If you want more inverse examples, I have a newer video on this topic: th-cam.com/video/l3lXkveIOjY/w-d-xo.html Thank you for supporting one of my original videos!
what is the explanation/rule of the 'we need' box? the derivative of the inverse of the function of x is the inverse of the derivative of the inverse of function x ?
If you want an explanation of the rule, you need to start with f( f^-1(x)) = x (definition of the inverse function). Take the derivative of both sides (Chain Rule on the left) and then divide to solve for the derivative of the inverse function.
thank u teacher for sharing .. it was very helpfulll. but my question is can we just derivate the inverse function normaly just like any normale functio then plug in the 4 number ?
why don't we use the formula g'(y) = 1/f'(x) If f(x) = y the inverse is g(y) = x eg. g( 2x^3 + 3x^2 +7x +4) = x it follows g(4) = 0 so f'(0) = 7 or g'(4) = 1/7 Cool
Graduated HS and had him as my Algebra teacher. Now in college and I'm still coming back to him for help.
Hope college is going well, Danny! Good luck with calculus!
I watched so many videos to better understand this concept, and yours was the most clear and concise explanation. Thank you so much!
I am happy you found the video helpful! Thank you for the support.
9 years later, and this is still the most useful video on this topic. So many others focus on how the formula is derived and use a generic function to prove it. That's all well and good, but doesn't come close to helping Calc students understand how to use it and solve HW/test questions. Thank you.
Glad it was helpful! I am so happy to see that my old videos are still going strong. I filmed that video in my room; I had a whiteboard on my wall and a old camcorder set up on a tall armoire.
why did it take so long to find you :'( you're my savior
Hey Vin. There aren't as many video tutorials for this topic and your excellent demonstration saves me from tons of struggle. Thanks a lot :D
Glad it helped! Best wishes with the rest of calculus!
This was awesome.!! 😃You managed to talk about a topic involving inverse functions without going back and forth between 'original function' and 'inverse function' multiple times and making it head-spinningly confusing. Congratulations!
Glad it was helpful! How is your calculus class going?
Thank you so much!!Ive been trying so hard to understand this concept and youve explained it so clearly!!
I SPENT 2 HOURS ON THIS ONE QUESTION, AND YOU OPENED MY EYES @ 3:10
But 0 is not the only solution for f-1(4) as it is a cubic equation it should have 3 solution
Thanks ! The only video I can understand about these inverse functions.
Glad it was helpful!
Holy, what an incredible video thank you so much man. I've been looking at this topic now and scrolling through other videos and yours was so much clearer, hope you keep making more videos this was great, thank you!
I appreciate the comment and best wishes with calculus!
Best explanation of this. Best video I could find
Glad it was helpful!
I was desperately searching for this and finally got you....... Cleared my all confusions 😊😊♥️
Glad it was helpful!
Wow I love you. I was stuck on a calc problem and google didn’t help one bit but this video did.
THANK YOU THANK YOU
you my friend, are a LIFESAVER. super easy to follow along and understand. thank you!!
dude you're the goat I have been trying so hard to find a video on how to solve for a number when there are multiple terms, now i understand tysm
This was the best video I could find on this 🙏. Thanks!
Glad it was helpful! I made an updated version of this video, covering a few more examples. Best wishes with calculus and thanks for the sub!
Very clear and straightforward, really appreciate the video! :)
Glad you enjoyed it!
Thank you. My calculus book was so confusing. This really helped. If you have the time, please make another video with just the table.
I have an updated version of this video:
th-cam.com/video/l3lXkveIOjY/w-d-xo.html
I hope this video helps!
You saved my life
best video for derivatives of inverse functions
I am glad this old video is still helpful. Good luck with your calc class!
Got a Calc B.C. test tomorrow, thanks for this video.
Best of luck!
you’re acc a life saver 😭 thank you
I am happy to help! Good luck with your class.
Thank you man this helped me a lot bro
Glad I could help! Good luck with the rest of calculus!
Very clear illustration! Thank you!
literally watching this 2 hours before my midterm and I finally understand now, Thank you!
Glad it helped! Hope your midterm goes well.
Forever grateful🤙
Math bless you man, great explanation. Thank you for doing this.
thank you! this was so helpful
Glad it was helpful!
What an explanation 👍👍👍
Glad it was helpful! I hope calculus is going well!
@@vinteachesmath yep
Thank you for this video! Though im kind of confused for this type of question:
Find (f^-1)'(a), if f(x) = x^3 + 2x + 3, and a = 0. Over here I tried applied the concepts of inverse functions where you can say that if f^-1(0) = a. Then f(a) = 0. However, it got me some decimal answer and I had to do some things that I'm not sure are allowed by the professors.
Honestly you could just guess and check because i got (-1,0) on f(x) therefore (f^-1)(0) = -1 and plug that into 1/f’(f^-1(x))
Great explanation sir, good job! you could not be any clearer litteraly!
OMG this video helped me so much. THANK YOU !
best explanation.
Glad you think so! I updated this video somewhat recently: th-cam.com/video/l3lXkveIOjY/w-d-xo.html
I finally understand this topic thanks a lot(:
Glad it helped!
THANK YOU SOOO MUCH!!!!!!
Happy to help! I am glad my older videos are still going strong!
Thanks a ton Bruh!
Best explanation. Thank you.
Glad it was helpful!
This was extremely helpful
thank you. Very very simply for me
I am glad it helped! Good luck with your class.
The best
Thank you!
Welcome! Best wishes with the rest of your semester!
best explanation son. thanks a lot!
Thank you for the vote of confidence! Best wishes with calculus!
Very helpful
Great video. Thanks for the help
Happy to help! Best wishes with calculus!
Good 🌷
thnx
that’s amazing
You're welcome!
What if there is a trig property in it and an argument like (pi x /2)?
You should not ask rather you should try it on your own...
Thank you sir ❤❤
Most welcome!
So helpful thankyou!
Thank you I love you
Great video, thank you for sharing it.
Thank you Sir
I am happy to help! Thanks for watching!
THANKS!
Brilliant👏
Thanks!
best explanation sir👍👍👍👍
I am glad the video helped!
uhmm... i got confused. we are talking about INVERSE FUNCTION, it means f(x)=y and we should switch y for x then solve for y to have inverse function, then, we will take f' (y), finally, we will place 4 to the function we got. Is that right?
Yes.. But in cases where the function is difficult to separate, we can make use of this formula.. The formula can be proved by applying the Chain Rule to the definition of the inverse function.
vinteachesmath I see. Thank you very much!
The problem is that it s hard to take the inverse of such functions. What you have to do in those cases is to plug numbers until you find h(x)= the x value you re differentiating the function at... Then consider it as a y value for h(x)-1.
Very helpful.Thanks a lot.
Helpful Thanks
Thanks for watching!
you got that dog in you fr
Ihank you so much👍👍
Love from INDIA
I am happy my videos are reaching people around the world! One of my favorite parts of being a youtuber!
Very helpful👍
wait, but is is not 1to1 function. It fails horizontal test, right?
It should be 1:1 since the derivative of f is always positive. Since f' is always positive, f is always increasing and therefore, 1:1.
Correct me please: x² is parabolic function, therefore it cannot pass horizontal test, because there are 2 interceptions
Do you always have to plug in a zero?
No, but it zero is an easy number to try though! Then I try 1, -1, etc. If the numbers get too crazy then you can use a calculator to find out when the function equals a particular value.
I love you.
perfecttttt
Glad it helped! If you want more inverse examples, I have a newer video on this topic:
th-cam.com/video/l3lXkveIOjY/w-d-xo.html
Thank you for supporting one of my original videos!
Namaste🙏 sirji💐.
Happy to help!
والعباس حجيك معدل زلمه كلف
would it not be easier to understand if you just used dy/dx for f prime of x
what is the explanation/rule of the 'we need' box? the derivative of the inverse of the function of x is the inverse of the derivative of the inverse of function x ?
If you want an explanation of the rule, you need to start with f( f^-1(x)) = x (definition of the inverse function). Take the derivative of both sides (Chain Rule on the left) and then divide to solve for the derivative of the inverse function.
thank youuuuuuuuu
I am happy to help and good luck with calculus!
But there are 3 values of f-1(4) as it is a cubic equation??
what if the derivative is decreasing? can I still use the formula you used?
As long as it passes the horizontal line test
thank u teacher for sharing .. it was very helpfulll. but my question is can we just derivate the inverse function normaly just like any normale functio then plug in the 4 number ?
Yes that is an option. However, for many examples they will give you a function where you cannot find the inverse function algebraically.
+vinteachesmath Oh that's what i was looking for . thank 's teacher .
i wish u will do more for us
👌👍
nice
why don't we use the formula g'(y) = 1/f'(x) If f(x) = y the inverse is g(y) = x eg. g( 2x^3 + 3x^2 +7x +4) = x it follows g(4) = 0 so f'(0) = 7 or
g'(4) = 1/7 Cool
i bet your name is mr D you handsome boyy
How did you know to use zero?
Trying out 0, 1, -1 are good numbers to try first because they are easy to plug in. Good luck with your class!
god bless
this is infinite math. to get any accolades from me you have to show this in finite math. F[x]
So nice there s no music
I do not have any cool intros to my videos!
help
LmaooooooooooooooooooOOo
💕🥺🥺🥺
very informative vid but youre like distractingly good looking
no homo
Thank you!!
You're welcome!
Thanks so much, this has really helped.
I am glad it helped! I wish you the best with calculus!
god bless