You don't even know how much your videos have saved my hide over the last year. I think sometimes once you get a PHD you forget how to teach normal people concepts. TYVM!
My Professor talks so fast in class that I have no time to even try and understand what is going on. We have a test on Wednesday and I'm pretty sure your videos saved my life. THANK YOU!!!!!
this is a very good approach of the site owner who knows the real value of laplace transform in solving engineering problems thaNX TO THE AUTHOR AND DEMONSTRATOR AND TO THE LECTURER
dear lord thanks for these videos... I'm from ireland and have a russian maths professor... i can't understand her half the time and these vids are gonna help me pass my exam on monday!
thank u sir , i was trying to learn it by books but in the end all i learn nothing but got scared by all those calculus alien signs , your videos really really helped me ...
Does not the existence of the improper integral imply that lim t -> infinity e^(-st)*f(t) = 0? If so, we are safe to assume that [e^(-st)*f(t)](0,infinity) = -f(0).
u = e^-st. So u' would be the derivative of e^-st with t. This would be the derivative of e^-st with respect to (-t), multiplied by the derivatiive of -t with respect to t. The first derivative would be the derivative of e^s(-t) w.r.t (-t), which is se^s(-t) which is se^-st. Standard formula. This is multiplied by derivative of -t w.r.t t, which is -1. So the answer is -se^-st.
Sal I got a question, when my instructor derive the laplace transform of sin(at) and cos(at) (he did it together) he some how got some thing with an i, cuz he said we are supposed to use the e^iat = cos(at)+ isin(at) and he got the laplace transform to be something like this (s/(s^2+a^2))+ (i(a/(s^2+a^2)) wtf?????? wtf?????
You don't even know how much your videos have saved my hide over the last year. I think sometimes once you get a PHD you forget how to teach normal people concepts. TYVM!
I watched all of your ODE videos last year. Now I'm actually taking the course. I have an A+ and I am not a math major. Thank you.
This series is my first exposure to the Khan Academy. These videos on the Laplace Transform are terrific. You guys rock!
i have an incomprehensible Czechoslovakian professor. THANKS SO MUCH! I have a final in 2 days and this has helped me so much!
I learned Laplace over 15 years ago but have not used it since. These lessons are great for review!
My Professor talks so fast in class that I have no time to even try and understand what is going on. We have a test on Wednesday and I'm pretty sure your videos saved my life. THANK YOU!!!!!
this is a very good approach of the site owner who knows the real value of laplace transform in solving engineering problems thaNX TO THE AUTHOR AND DEMONSTRATOR AND TO THE LECTURER
dear lord thanks for these videos... I'm from ireland and have a russian maths professor... i can't understand her half the time and these vids are gonna help me pass my exam on monday!
i never learned anything from my professor, good thing you have this tutorial. thanks
thank u sir , i was trying to learn it by books but in the end all i learn nothing but got scared by all those calculus alien signs , your videos really really helped me ...
I love the way you say "infinity"
wow...you are so awesome!!!!!! Keep up the good work man! You make the world a better place!
Does not the existence of the improper integral imply that lim t -> infinity e^(-st)*f(t) = 0? If so, we are safe to assume that [e^(-st)*f(t)](0,infinity) = -f(0).
widout these videos, i would have DEFINATELY failed my first year uni exams ...... and
chyeahh boii keep up the good work .. (Y)
very useful..thanks a lot sir
thanks man, maths made easy
Thanx a ton!! YOU are just AWESOME!
only done [ e-st f(t)] for infinity, forgot to do it for 0 also. around 8:40
At 8:08 would it be correct to write that e^-st*f(t) goes to 0 iff f(t)
very good, is there a place where you concentrate all your videos?
In laplace space, time does not exist. So you won't be able to visually relate the function in time space to function in laplace space...
great teaching style. I follow along perfectly!
Zeroo to innfinity... and beyond!
nice work professor....... thk u..............
Thank you. Thank you. Thank you.
so helpful. God bless
Please load some example for Picards iteration solving a differential equation
Thanks!
Is this video failing to come up for anyone else? The rest is Khan Academy's videos show just fine but for this one.
you're not alone it's failing for me too
Aaron Muir here aswell
Had the same problem. Try skipping ahead in the video, then go back to the beginning. That got it working for me for some reason.
Ubu this worked. thank you
Still failing 5 months after... How to report this bug to Google?
should u'= (-1/s)e^-st ? because e^(-st)= 1/e^st and then the derivative would actually be what I just said? Is that correct?
me 2 it was strange for me that he did it like that... i think u r right
u = e^-st. So u' would be the derivative of e^-st with t. This would be the derivative of e^-st with respect to (-t), multiplied by the derivatiive of -t with respect to t. The first derivative would be the derivative of e^s(-t) w.r.t (-t), which is se^s(-t) which is se^-st. Standard formula. This is multiplied by derivative of -t w.r.t t, which is -1. So the answer is -se^-st.
Oh crap I'm a year late lol. You probably figured it out anyway, but still... it's out here.
請問有人可以幫忙翻譯成中文字幕嗎? He may not do very well but we can recover our memory via his vedio. He calcuate very detail. I like it.
no earlier, it was the integral of e^-st now it's the differentiation. so hence s and not 1/s
What is the program u r using to present your lessons? Please
great videos
Did I mention your enthusiasm was infectious?
For those who are having problem with the video, try to skip akead, it should work. Tip by an user called Ubu, thanks bud.
Good❤
u r just awesome
But the question still remains though, would the exponent teem ALWAYS reach zero faster than the function f 🤔 ?
Sal I got a question, when my instructor derive the laplace transform of sin(at) and cos(at) (he did it together) he some how got some thing with an i, cuz he said we are supposed to use the e^iat = cos(at)+ isin(at)
and he got the laplace transform to be something like this
(s/(s^2+a^2))+ (i(a/(s^2+a^2))
wtf?????? wtf?????
dese vids r gud...
Great lesson!! however I was n bit disappointed that the ".......to infinity and beyond" joke didn't come up!
ummm what is the L {f'''(t)} by chance? I got s^3 L{ft} - s^2f(0) - sf'(0)- f''(0) . is this correct?
It should be.
yes that's almost correct but he did the derivative of e^-st wrong, it's -1/s*e^-st , so you're correct only the powers on your s's should be negative
The derivative isn't wrong. Use the first principle of differentiation, you can verify it.
why did you take particularly e^-st as U why not f'(t)
this is my exact same situation RIGHT now, November 7th, 2012. Wednesday 0.o
great
Sal is the best !
You are a great help...Thank you sir
why is u' = -Se^-st instead of u' = -1/s* e^-st ?
u'= - 1/s e^(-st) not -s e^(-st) so this is a mistake brother
I LOVE YOU
Does not play on Chrome.
Plays with Explorer or any Android Mobile Device.
hay why don't it play i wait a lot
Well I'm now done with the class, but my professors name was John Collins
that looks like something binomial-ish
if thats a word
Good vid, but he (to me) skips some steps. I'll look at this one and others from non-Khan Acad vids.
12 years
dear god is this what a taylor series is?
no
請問有人可以幫忙翻譯成中文字幕嗎?
Sometimes he sounds a lot like Obama for some reason lol
The guy under my comment, always says something rediculus, in every video..
Maybe because of his face... Anyway :D
@maneki9neko I think it's only one dude. =)
so basically everything that was s in this video just has to be converted into 1/s, right? :D :D
@32103940 I see, thanks you so much!!!!!!
Well actually you won't see me in the next video and I won't see you either. I will hear you though. lol
Oops! I watched the video, read your comment, laughed, and then also accidentally clicked 4 stars in stead of 5. Epic fail. xD
sorry but you're* i just can't resist
I unpause my adblock just for you
this video does not work
how do u manage to have the shitiest quality in recording ??
This video is nearly 11 years old ...
man look at the date