Calculate the boiler feed pump and motor size required for a boiler of capacity 90 TPH has steam drum working pressure 88 kg/cm2. The height of the drum is 35 meter from boiler feed pump Centre. And the suction water to pump is taken from Deaerator which is situated 15 meter above the pump centre. Given that, Boiler capacity: 90 TPH = 90 M3/hr Steam drum operating pressure = 88 kg/cm2 Steam drum height from pump centre = 35 meter Height of Deaerator tank from pump centre =15 meter Assumption: Boiler blow down 1% Deaerator operating level from floor: 2.5 meter Pressure drop in Boiler economizer: 2.5 kg/cm2 Pressure drop in feed water control station: 5 kg/cm2 Pressure drop in line, gate and globe valves and bends of feed water line: 5 Kg/cm2 Pump operating temperature: 110 °C Economizer out let feed water temperature: 275 °C Pump and motor efficiency: 65% and 95% respectively. Total required discharge head for pump = (Drum operating pressure + Drum height (m) + Economiser pressure drop + Control valve pressure drop + Pressure drop in line, gate and globe valves and bends) X 1.10 (Take 10-15% extra margin) = (88 kg/cm2 + 35 meter + 2.5 kg/cm2 + 5 kg/cm2 + 5 kg/cm2) X 1.1 Convert all the pressure head into gravity head in meter from formula P = Density X g X H…by taking the densities of fluids (water) at operating temperatures. P = Desnity X g X H Then, we have, Total discharge head = (1248 m + 35 m + 33 m + 52.5 m + 52.5 m) X 1.1 = 1563 meter Pump rated flow = (Boiler MCR + Blow down %) X 1.25 (Take 25-30% extra margin) = (90 + (90 X 1/100)) X 1.25 = 113.625= 115 M3/hr The Capacity of flow seems more, it is better to consider 3 pumps 2 running & 1 stand by Pls explain how he got 88kg/cm2 to 1248 m by using p= density *g*h formula Sir, Pls explain this formula is giving here , kg/cm2 to meter conversation
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Calculate the boiler feed pump and motor size required for a boiler of capacity 90 TPH has steam drum working pressure 88 kg/cm2. The height of the drum is 35 meter from boiler feed pump Centre. And the suction water to pump is taken from Deaerator which is situated 15 meter above the pump centre.
Given that,
Boiler capacity: 90 TPH = 90 M3/hr
Steam drum operating pressure = 88 kg/cm2
Steam drum height from pump centre = 35 meter
Height of Deaerator tank from pump centre =15 meter
Assumption:
Boiler blow down 1%
Deaerator operating level from floor: 2.5 meter
Pressure drop in Boiler economizer: 2.5 kg/cm2
Pressure drop in feed water control station: 5 kg/cm2
Pressure drop in line, gate and globe valves and bends of feed water line: 5 Kg/cm2
Pump operating temperature: 110 °C
Economizer out let feed water temperature: 275 °C
Pump and motor efficiency: 65% and 95% respectively.
Total required discharge head for pump = (Drum operating pressure + Drum height (m) + Economiser pressure drop + Control valve pressure drop + Pressure drop in line, gate and globe valves and bends) X 1.10 (Take 10-15% extra margin)
= (88 kg/cm2 + 35 meter + 2.5 kg/cm2 + 5 kg/cm2 + 5 kg/cm2) X 1.1
Convert all the pressure head into gravity head in meter from formula P = Density X g X H…by taking the densities of fluids (water) at operating temperatures.
P = Desnity X g X H
Then, we have,
Total discharge head = (1248 m + 35 m + 33 m + 52.5 m + 52.5 m) X 1.1 = 1563 meter
Pump rated flow = (Boiler MCR + Blow down %) X 1.25 (Take 25-30% extra margin)
= (90 + (90 X 1/100)) X 1.25
= 113.625= 115 M3/hr
The Capacity of flow seems more, it is better to consider 3 pumps 2 running & 1 stand by
Pls explain how he got 88kg/cm2 to 1248 m by using p= density *g*h formula
Sir, Pls explain this formula is giving here , kg/cm2 to meter conversation
Dear I have already uploaded,
Please watch my video on NPSH to fully understand
@@PowerPlantDiscussion sir I checked that video carefully but value not matched 1248m
Approx 10m = 1kg/cm2
88kg/cm2= 880m
@@PowerPlantDiscussion thank you sir
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