if you add the next logical term to make it symmetric, you get 1/2+that thing, and since the 5th roots of unity are algebraically identical, we really can just plug in 1 to get 5/2 then subtract 1/2 to get 2
Instead use sum of all the roots as 0 and evaluate it gater as x/1+x² = x⁴/1+x And same for the other two and solved it in less than 30 sec thought for about like 1 min
love your content man! from Tunisia!!!
Thanks so much ❤️ ❤️. Please subscribe
very resourceful.
Thanks so much ❤️
if you add the next logical term to make it symmetric, you get 1/2+that thing, and since the 5th roots of unity are algebraically identical, we really can just plug in 1 to get 5/2 then subtract 1/2 to get 2
Yes
Plug 1 .
but x ≠ 1
@ChidexMath2-w4h you could put x=1 and it will work Same answer
Did anyone try to solve this using nth root of unity (complex numbers)
Find all solutions for x^5 = 1, then substitute, it will give you 2
Instead use sum of all the roots as 0 and evaluate it gater as x/1+x² = x⁴/1+x
And same for the other two and solved it in less than 30 sec thought for about like 1 min
@@ChidexMath2-w4hIf x=/=1 how do we know which complex root it's talking about
So X is indeed equal to 1 😅
You mean the answer which was later 2 ? 😂