Hi Brian, almost 100k views on this one! Just shared it with a student of mine! You have videos on almost everything I've taught for the last 2 years! Thanks bud!
Most underrated teacher on youtube. I never thought I'd have to do long division again my whole life though haha. Guess I was wrong about that. Its back
@3:25 I got cleared up some confusion that I got from the channel named: "The Organic Chemistry Tutor" I'm very impressed that you did this better than he did. This is exactly what I was hoping for, and why I'm here. 👍👍
Jesus i must be extra stupid if I cant even understand with you explaining like this 😔 rewatched it 3 times and that long division part still took me out
f(x) = a(b)^x + c....... Horizontal asymptote is y=4........ 2 points of the function are(1, 0) and (2, -12)..... The function is decaying.... Find a, b and c Pls help with this one sir
Hi there, I am hoping that someone will read this and help me!! lol ... I am taking the math cset next week and there is a practice problem that states which of the following is an equation for the slant asymptote of f(x)= x^3 -1 /(divided by) x^2 and the answer is y=x BUT I CANNOT FIGURE OUT WHY!!!! HEEEEEELP
do long division with the given rational function. You will get the answer x+1/x^2. As he said in the video, don't worry about the remainder just the divisor without it, which is x. Therefore the answer is y=x
its because there was nothing but x cubed at the top, so (if you'll imagine a number line, that might help) when the x cubed was subtracted from the x cubed, you got 0. However, you still had the -1x, so it was effectively 0 - (-1x).
There's no asymptote because an asymptote must be linear by definition. But, the graph will always approach the function that is the quotient of the two polynomials (without the remainder). So, if the quotient is x^2, then the graph will approach the parabola x^2, but again, it's not an asymptote, because it's not linear.
Why don’t you use standard terminology for numerator, denominator, dividend, etc.? I find that using standard terminology and pronunciation increases student understanding?
hi thank you so much i understood but i have realized something weird like Americans and europeans have very strange last name i mean what is McLogan oh my god
Like all bald characters, this dude is also overpowered.
thanos, one punch man, *Brian McLogan*
😂 The internet remains undefeated...
😂
All Wraiths with the bald skin in Apex Legends.
Don't forget Johnny Sins, a man of many talents.
turn on subtitles at 1:37
lol
I mean thats what it sounds like he said so
"those are two assholes that my crap is never going to touch" - Brian McLogan 2011
Thank you for this 😂😂
😂😂😂😂😂😂
this 5 min vid is better for me than my whole hr long classes 😭
No disrespect to my teacher but this is factual
@@diegonunez3492 Real
@@Breqdy REALLY real
8 years later, wonder if he's still looking good.
hopefully
still makes videos!! lol
its 9 now ➿
@@h3x4ry55 10 now !
@@michellewong3392 15 now!
I would not understand half of what I do now without people like you who make videos like this. Thank you
Hi Brian, almost 100k views on this one! Just shared it with a student of mine! You have videos on almost everything I've taught for the last 2 years! Thanks bud!
Absolutely! What you teaching these days
Thanks for all the videos! They are excellent and outstanding, please keep up the amazing content. 👍
This really helps in quarantine times. Thank you!
Man I remember you saving my ass back in highschool.
saved me during highscool, and still saving me in college
12 years later and his vid is still alive , i have a test in couple of days and i really appreciate his work as it helped so much .
1:51
Mr. McLogan: "I'll try to say them as slowly as possible"
Me watching on 1.5x speed:
Thank you! the only person who I could find who explained this in a way I really could understand🙏🏽
Gosh why can't all teachers explain it like this? Thank you 🙏
Most underrated teacher on youtube. I never thought I'd have to do long division again my whole life though haha. Guess I was wrong about that. Its back
Thank you for helping me with pre calc
I’m studying for a test I have tomorrow, and this really helped me. Your awesome!
You’re*
Legit same
I love this channel, I got a test tomorrow and this is very useful because I missed one day that went over this.
So happy to help you out!!0
me too!
@3:25 I got cleared up some confusion that I got from the channel named: "The Organic Chemistry Tutor" I'm very impressed that you did this better than he did. This is exactly what I was hoping for, and why I'm here. 👍👍
I got mathematics board exam tomorrow and I found this video to be very helpful for curve sketching. Thank You Sir ❤❤
This is so helpful.
Jesus i must be extra stupid if I cant even understand with you explaining like this 😔 rewatched it 3 times and that long division part still took me out
try finding his long division videos. I had to go back and practice long division too.
3:55 got me a stroke
Good refresher for what I have forgotten, thank you!
9 years later, wondering if he's still looking good.
you literally are our school saviour
Thank you! I have this problem for calc hw tonight, thank you for clarification! Love the vids
Weird flex but ok
Watching this 15 mins before my pre cal test
I understand everything that you say thank you very much you are the best teacher in the world 💙💙💙💙
f(x) = a(b)^x + c....... Horizontal asymptote is y=4........ 2 points of the function are(1, 0) and (2, -12)..... The function is decaying.... Find a, b and c
Pls help with this one sir
No
thank you sir
bro i love you
You draw impressively straight line
1:35 empty garbage task done
Among us?
This guy is doing our teacher's job for free
Wow great video
You are very helpful, but dude, you must make your videos louder. I often times have to raise my computer volume all the way up just for your videos
You’re a saint, thank you :)
bro the Johnny sins of math
what irrational thing would happen if the graph touched the slant asymptote?
Thank you for the help.
Thank you soooo much, ur videos help me alottt
IF YOU ARE READING THIS, YOUR ATTENTION SPAN IS WAYYY TOO SHORT. GO BACK TO WATCHING MR. MCLOGAN 😀
haha
Watching this exactly a decade later.
Hi there, I am hoping that someone will read this and help me!! lol ... I am taking the math cset next week and there is a practice problem that states which of the following is an equation for the slant asymptote of f(x)= x^3 -1 /(divided by) x^2 and the answer is y=x BUT I CANNOT FIGURE OUT WHY!!!! HEEEEEELP
do long division with the given rational function. You will get the answer x+1/x^2. As he said in the video, don't worry about the remainder just the divisor without it, which is x. Therefore the answer is y=x
My teacher barley explained this and expected us to know
Happy to help
Why did he add the 0 on top of the -1x during the Long division part
its because there was nothing but x cubed at the top, so (if you'll imagine a number line, that might help) when the x cubed was subtracted from the x cubed, you got 0. However, you still had the -1x, so it was effectively 0 - (-1x).
0 minus negative 1 is positive x???
subtracting a negative creates a positive
AJ Kanakry yes!! haha, man thats basic division. this is why i got F in this lesson
Thanks but that horizontal line was something else
So the slant is x?
Beautiful ❤️
Thank you Mr brian sir, teaching me my stuff better than my teachers 🫡
I did the limit method of f(x) - x and f(x) /x I got the wrong answer why?
cause u trash boi
@@attackdamage7105 lol
This video is 12 years old today
How is a slant asymptote possible
Thank you Tyson Fury
I don't understand the slant at all. You should do more examples instead of one.
10 years later me struggling in pre calculus hmmm help?
so like math
who else is here cuz they cant do their history homework?
Lol forgot how to do long division 😂
Ignacio Varga?
What if degree difference is 2....?
I'm pretty sure you still do the same thing
There won't be an asymptote.
There’s probably a hole
There's no asymptote because an asymptote must be linear by definition. But, the graph will always approach the function that is the quotient of the two polynomials (without the remainder). So, if the quotient is x^2, then the graph will approach the parabola x^2, but again, it's not an asymptote, because it's not linear.
my prof took 4 hours to explain thing topic
Why don’t you use standard terminology for numerator, denominator, dividend, etc.? I find that using standard terminology and pronunciation increases student understanding?
does anyone else hear him say asympTOPE instead of asympTOTE
Brain playing tricks on you! 🤣
I thought that it was 1x and not 0x I’ve never seen 0x Oml I’m terrible at math
hi thank you so much i understood but i have realized something weird like Americans and europeans have very strange last name i mean what is McLogan oh my god
Haha not sure
Why is the residual not important?
this make no sense the stutter is real
10 years later, wonder if he's still looking good.