Routh Hurwitz Stability Criterion Basic Worked Example

[@arujkhandelwal4090]

Number of sign changes equals number of unstable (positive) poles, not the number of poles.

[@carolinasalvador1320]

thx!

[@michaelhiltz7846]

Also shouldn't the total number of poles be equal to the degree of the polynomial.

[@PunmasterSTP]

As others have mentioned, the number of sign changes equals the number of RHS/unstable poles. But otherwise this was a great video, and thanks for making it!

[@davidmuchirahondo8104]

Short and precise. Just what I was looking for. Thank you!!

[@gabrielv8767]

The number of sign changes equals the number of poles IN THE RIGHT HALF PLANE, not the total number of poles of the system

[@briglywebster]

Great beginner example. Thank you.

[@MrSidney9]

Thanks. Very clear and to the point,

[@alexanderquilty5705]

It’s unbelievable to me that neither the textbook nor the professor couldn’t just say/show what was in this video. This is easy…

[@veekee0243]

thank you so much

[@frankenunwah8486]

So helpful

[@chinonsowisdomokwudili7878]

thanks

[@M4TT4TT4CK]

you sound like ewan mcgregor lol. sorry, I just love the accent

[@alexxa5584]

helped a lot

[@samanpaydar4415]

Excellent 😍

[@Zouzack]

brilliant

[@sakethravuri3023]

Thanks 😊

[@ABCEE1000]

but you did not talk about stability at all !

[@hassenahmed8525]

Hello s³ + s² + 2s + 24 🙂

[@PunmasterSTP]

Did you have to do that for homework? What did you think the answer was?

[@alexanderquilty5705]

It’s unbelievable to me that neither the textbook nor the professor couldn’t just say/show what was in this video. This is easy…

[@portobellemushroom6139]

thanks