Combined Loading Example 1 (Part 1/2) - Mechanics of Materials

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  • เผยแพร่เมื่อ 23 ธ.ค. 2024

ความคิดเห็น • 56

  • @bergottersa9436
    @bergottersa9436 8 ปีที่แล้ว +33

    Can i just say.....YOU ROCK!!!Im busy with Civil engineering at the University of Pretoria (SA) and everytime my friend and I have no idea what our lecturer said we both just say
    "StructURE FREEEEE
    LEEEEEEEEEEEEAAAAAARNING"

    • @structurefree
      @structurefree  8 ปีที่แล้ว +7

      +eckard degoede Ha, Ha! Ahhhh--yeahhhh! "X gon' give it to ya!"

    • @ephraimmoye4772
      @ephraimmoye4772 6 ปีที่แล้ว

      From University Of Johannesburg South Africa... Thanks a million times... Was really confused in class but this...

  • @cdewes1
    @cdewes1 7 ปีที่แล้ว +2

    so much better of an explanation than most of the professors out there explaining this stuff - i'm trying to grasp combined loads for the P.E. and I think this is one of the first times it made sense to me so thanks!

  • @llamaguy5
    @llamaguy5 10 ปีที่แล้ว +1

    such a boss! Aced my solid mechanics exam because of you! Keep doing what you do!

  • @mertyigit4093
    @mertyigit4093 5 ปีที่แล้ว +1

    Hey, maaan! I was just thinking that why all the professors confuse students minds but most of the youtubers explain this topics better than they do. How can it be possiblee ?
    whateverr!
    BAAMM! STRUCTREFFFFFRREH lööninnggg! You da best!

  • @ShrektD
    @ShrektD 7 ปีที่แล้ว +1

    Dude you fucking saved my sorry ass. In my final year of engineering and my uni don't explain shit. THANK YOU

  • @laurahernandez6595
    @laurahernandez6595 9 ปีที่แล้ว +3

    THANK YOU!!!!!!! Learned more from this video than the lecture notes :/

  • @CODERED597221
    @CODERED597221 7 ปีที่แล้ว

    At 8:20, you decide to take the first moment wrt the bottom area. My question is how would you find Q with the upper area?

  • @stevecooke4974
    @stevecooke4974 7 ปีที่แล้ว

    What about if you placed A on the other side? (At 1:15, A is on the right side of the rectangular beam). Im doing similar problem with a circular cross section and shear stress opposite sign on each side, not sure why

  • @andyfma123
    @andyfma123 9 ปีที่แล้ว +25

    Okay man, if I get an A on my final, you are getting a donation of 21$. You have my word.

    • @mahutin2
      @mahutin2 7 ปีที่แล้ว +2

      Did you get an A on your final?

    • @narang__2309
      @narang__2309 7 ปีที่แล้ว +2

      Mahutin Ligan haha. +1

    • @mahutin2
      @mahutin2 7 ปีที่แล้ว +1

      RADHIKA NARANG Uh...not sure if that's happy laughter or nervous laughter lol

    • @SandipHodkhasa
      @SandipHodkhasa 7 ปีที่แล้ว +3

      Lol I like how you specifically donates . 21.

    • @AdaamTube
      @AdaamTube 6 ปีที่แล้ว

      mind of an engineer

  • @entréeaj
    @entréeaj 6 ปีที่แล้ว +3

    Thank you for making this subject way more understandable. I'd say "I wish you were my professor," but at this point you practically are :'(

    • @structurefree
      @structurefree  6 ปีที่แล้ว +1

      Awwww djyeaaaah, Professor Structurefree!

  • @franciscoaguero9028
    @franciscoaguero9028 4 ปีที่แล้ว

    Should it be -2knm for the internal torque at A, and the normal strees be positive (tension)

  • @ItrimUrArmor
    @ItrimUrArmor 8 ปีที่แล้ว +3

    These videos are great, and they've helped me pass my CE 204 class. I do have a slightly unrelated question though
    Do you think you could upload your work sheets in the discription of the video? I try to follow along, but sometimes you pull back values or equations from previous pages and I have to backtrack in the video to find what you're talking about. It would be easier to work alongside the PDF.
    Idk if others get this too, its just a helpful thought:)

  • @irfaankathrada499
    @irfaankathrada499 6 ปีที่แล้ว

    Does V always have to be stated as pointing UP on the negative side of the cut face. I was taught V points down, which would make -V - 2 = 0. So V = -2 (downwards)

  • @fratozerden3024
    @fratozerden3024 6 ปีที่แล้ว

    Amazing video.. in the end; when computing the direction of the stress by moment, did he take the direction of moment wrong,isnt it down to up ? Shouldn't the stress be tension because of the direction of moment?

  • @aliannab1467
    @aliannab1467 10 ปีที่แล้ว +2

    Thanks your lesson is very helpful

  • @lillianzhou3762
    @lillianzhou3762 8 ปีที่แล้ว

    Hi, how to determine the sign of convention of torsion

  • @sannishacastillo156
    @sannishacastillo156 9 ปีที่แล้ว

    Should the cross sectional area be equal to 500 mm * 150 mm (.5 meters = 500 mm) ?

    • @structurefree
      @structurefree  9 ปีที่แล้ว

      Sannisha Castillo i had it set up as 50 mm * 150 mm. (50 mm = 0.05 m).

  • @elizabethsamura5590
    @elizabethsamura5590 6 ปีที่แล้ว

    how do you calculate the stress on the y? I mean sigma yy

  • @milkcreightronny
    @milkcreightronny 4 ปีที่แล้ว +1

    You said internal shear is positive upward on the right. I realize it's arbitrary but according to your FBD I think you meant positive upward on the left?!

  • @JohnoBucko
    @JohnoBucko 8 ปีที่แล้ว +1

    Really, really good videos.

  • @duaatm7250
    @duaatm7250 8 ปีที่แล้ว +1

    hi... it really great video ... i have a question what if the cross section was ( I ) shape ?

    • @structurefree
      @structurefree  8 ปีที่แล้ว

      Thanks. It would change all the area properties.

  • @sajasaja9236
    @sajasaja9236 6 ปีที่แล้ว +1

    Man god bless you

  • @notSavant
    @notSavant 8 ปีที่แล้ว

    Why dont we have to calculate the reactions?

  • @Titan.Uranus
    @Titan.Uranus 8 ปีที่แล้ว +1

    Finally...Structurefree has come back to TH-cam...In front of the millions and millions. So if u can sammelllalalalalalala, what structurefree is cooking!
    [Interview Scenario]
    Structure: So, what did ur candy-ass learn today?
    Me: Well..ummm, I kinda....
    Structure: It doesn't matter what u learnt!!

    • @structurefree
      @structurefree  2 ปีที่แล้ว

      I can't believe it took me 5 years to see this comment. Soooo funny!!! I'm starting my classes like this from now on.

  • @JasonMiller-cu9rr
    @JasonMiller-cu9rr 7 ปีที่แล้ว

    why did you not calculate the moment of inertia at point A?

    • @JasonMiller-cu9rr
      @JasonMiller-cu9rr 7 ปีที่แล้ว

      when finding the transverse shear stress

  • @arieladael3733
    @arieladael3733 9 ปีที่แล้ว +1

    Where are the subtitles?

    • @structurefree
      @structurefree  9 ปีที่แล้ว +2

      ARIEL ADAEL not sure. I thought youtube auto generated them? Hmmmmm.

  • @raminmollik498
    @raminmollik498 5 ปีที่แล้ว +7

    i always say with him "stricture free L E A R N I N G"..:

  • @tuanohuu3996
    @tuanohuu3996 5 ปีที่แล้ว

    Thanks. But why did you use M = +2kN.m instead M = -2kN.m

    • @lazarx804
      @lazarx804 4 ปีที่แล้ว

      The sign is there to denote the direction. You could ignore the sign in the calculations as long as you address the direction in the graph or in the final result.

  • @broses
    @broses 9 ปีที่แล้ว +1

    Good video!

  • @BaselNajdawi
    @BaselNajdawi 6 ปีที่แล้ว +4

    this 12 minute video taught me the same amount of 10 useless 1 hour long lectures.

  • @fera5165
    @fera5165 6 ปีที่แล้ว +2

    You got me at hello.

  • @PL3690
    @PL3690 8 ปีที่แล้ว +6

    Lmfao at the beginning

  • @notSavant
    @notSavant 7 ปีที่แล้ว

    You should add videos explaining the thought process instead of just examples...

  • @nickpersaud238
    @nickpersaud238 10 ปีที่แล้ว +1

    Yeah now it's correct Man U had V equals 4 last time

  • @fadoobaba
    @fadoobaba 8 ปีที่แล้ว

    SolidWorks tutorial for the same problem, here th-cam.com/video/ArTRJhA9dJ0/w-d-xo.html

  • @kaanyldrm7804
    @kaanyldrm7804 7 ปีที่แล้ว +1

    moment is calculated false, true is 2*1+4*0.45=3.8knm

    • @lazarx804
      @lazarx804 4 ปีที่แล้ว +1

      No he assumed the 4KN force was going right through the the centre so it's 2K *1 + 4K * 0= 2K N.m