Thank you sir!! I am very bad in physics from my school days and I am a school teacher and gets tensed with the thought that some day I have to teach physics then what!! Your video will definately help me.. God bless you!!
Please forgive me Monisha for replying late. Thank you so much for all your kind words of appreciation. It means a lot to me. God bless you and your family 🙏
Thank you so much for all your kind words of appreciation. It means a lot to me. Say a heartily thanks to your teacher for this recommendation. God bless you and your family 🙏
Don't worry, this experiment is very important, so it will definitely come in your next term exam. Don't hesitate to ask if you have any more queries. Regards
nice ! very helpful 4 science students .sir plz make some videos on generater,motor & solenoid .or experiments on magnetic effects of electric current.
Awesome! Thank you for taking the time to produce this episode. I must say background music that accompanies such teaching moments of your coinage series aids the brain in ‘think fast’ mode and calms the restless beast in me. Hey! Perhaps this may be helpful in the conundrum faced by neo-physicists relevant to matter/anti-matter = 0 + You&I. A good day to thee, Sir Science. 🌺
In this experiment our objective is to find the value of "meu" by using the ratio of "sin i" and "sin r". To do that after getting the lines (incident ray and refracted ray), we will draw a circle at the point of interface. After that we will draw perpendiculars from the point of intersection where the circle cut the incident and the refracted ray. The ratio of the length of the perpendiculars will give us the value of the refractive index. Hope this will help.
Very well captured . It's very helpful specially when students can't do experiments physically. Sir,do u have videos made on other science experiments also that are syllabus (9 and 10) based?
Thank u so much for your query. The St. line NOM is the normal about which we'll start measuring the angle of incidence & the angle of refraction, So without NOM ( the reference line) measurement can't be possible. Hope this will help. Regards
Thank you so much for your appreciation. I wrote every possible things that are necessary for this experiment, so just thought to keep myself quite, may be I should put some sound in it..anyway thanks again for all your feedback and appreciation. Best regards
... Would explain how we get a refracted view of the night sky... But the results of such could make people feel uneasy, or scoff and laugh. Depending on whether they had an overabundance of school and homework, but it would depend even more upon whether they actually DID the homework. However absence of mind doesn't account for the multiple people who go missing when they talk about such things.
To find the lateral displacement, we need to draw a perpendicular from the point of emergence to the dotted line drawn from the indecent ray. This perpendicular shift is the measure of the lateral displacement. Hope this will help.
Angle of I should be equal to angle of e (as the incident ray always parallel to the imergent ray). So try to draw an incident ray using given angle of incidence I (as it has give in the book). Then accordingly try to draw and complete the rest of the part. Now from the figure try to calculate the ratio of sin I and sin r. Hope this will help. All the best for your exams. Regards
Sir angle of I mera 30 aya hain or angle of r angle of e bhi 30 aya hai to sin I or sin r ki value nikalni hai to me kya karu matlab explained karo na kese nikalni hoti hain
Every values u got seems perfect. Now try to observe the value of angle of refraction using a protractor. Then using that (r) and (I) , try to calculate the ratio.
+Science Sir apne ek incident ray ke liye ye experiment ki hein. agar hum 5 incident ray k liye karte toh keise. only incident angle change kar de kya sir?
+Muhammad ayub Rajput angle 30 deg is easy to calculate without using scientific calculator. So for our convince we have taken this angle. U can take any other angle if u like. The result will be same at the end. Regards
In case refraction takes place in a glass slab, incident ray always parallel to the emergent ray, as they are parallel and the refracted ray can be considered as a transversal, the angle of incidence make equal angle with the angle of emergence. Hope this will clear your doubt. Regards
To all who are watching this before their physics practical exam
Tommarow my practicle 10th class thanX
Lol
@@rahulnavale8683 lol i have an exam about this practicle tomorrow too but I'm in class 7th...
Mee ughh
In 3 hours time 🙂🙏
Thank you sir!!
I am very bad in physics from my school days and I am a school teacher and gets tensed with the thought that some day I have to teach physics then what!!
Your video will definately help me..
God bless you!!
You're welcome and wishing you all the best. God bless 🙏
My ears feel lonely.
Poda pun.....
I got rest😂😂
😂😂
3:59 got scared cuz the audio suddenly came in 😂 ps this really helps thank you so much!!
Really sorry about the scary part; have no such intension :) . Anyway thanks for all your appreciation. It means a lot to me
Haha
The talent to explain so nicely without saying a word lies in you sir.... consider yourself unique
Thank you so much for your kind words of appreciation. It means a lot. God bless 🙏
@@science_sir i never expected that I wil get a reply on a 5 year old video
You're welcome 🙏
Tomorrow is my practicle exam n this video help me lot.... 🙂🙂
i finally understood this experiment ! this is so helpfull,, thank you
Ur most welcome and thanks for all your appreciations. Regards
I would like to thank you for this very professional and helpful video🌹
Ur most welcome & thank you so much for all your appreciations. Regards
Such a Helpfull video
Plz upload such many video
Hello, does the same rules aply if I am making this with trapeze shaped glass? Sorry for such a dumb question :D
Thank you so much for your query, the question is completely fine. Ya, definitely the basic rules are same for trapezium. Regards
Very well done Sir
And sir what should be the precautions.
Sir keep making such videos it helped me alot 4 2day bcose today my practicals are there
+SHRUTIKA GOSAVI sure. All the best
is the block more dense?
ඔක්කොම physics practical ටික complete ද playlist එකේ?
Why is the refractive index the ratio of the sinus and not directly the ratio of the angles?
Thank you for you video.
Good experience.
How about graph plotting for this experiment
Osm sir it was really helpful to me... Thanks a lot 👍👍☺
Please forgive me Monisha for replying late. Thank you so much for all your kind words of appreciation. It means a lot to me. God bless you and your family 🙏
My sir had recommended me this video.
It's a lot helpful. I at last understood it!!👍🏻😁
Thank you so much for all your kind words of appreciation. It means a lot to me. Say a heartily thanks to your teacher for this recommendation. God bless you and your family 🙏
Thanks Soo much for this video, it really helped me with my physics homework.
You're welcome 🙏
Really appreciable well explained 😘😘😘😘😊😊
Thank you so much for all your appreciations. It really means a lot
Science Sir where do you live
can we use this method to find the refractive index of water
Yes
Is the point O on the middle of line PQ or near the middle ?? Please my exam is in a few hours I really need an answer
I should have watched this before my exam :(
Don't worry, this experiment is very important, so it will definitely come in your next term exam. Don't hesitate to ask if you have any more queries. Regards
nice ! very helpful 4 science students .sir plz make some videos on generater,motor & solenoid .or experiments on magnetic effects of electric current.
Thanks for showing your interest on this field.. I will definitely try to make vid on these :)
Tasty Twist
Yes really I also want more vedios
Such a great video sir. Thank you so much
You're welcome 🙏
Such a fluent explaination I liked it I appreciate you
well done thank you very much 🙏❤️👍
You're welcome. God bless 🙏
Awesome! Thank you for taking the time to produce this episode. I must say background music that accompanies such teaching moments of your coinage series aids the brain in ‘think fast’ mode and calms the restless beast in me. Hey! Perhaps this may be helpful in the conundrum faced by neo-physicists relevant to matter/anti-matter = 0 + You&I. A good day to thee, Sir Science. 🌺
What are the limitations and sources of error for this lab?
sir kiya aap muje calculation bata sakti he is xprmnt ki......aur is xprmnt me jo grph banana prta he, wo kiya stright line hota he.....plz bataye sir
In this experiment our objective is to find the value of "meu" by using the ratio of "sin i" and "sin r". To do that after getting the lines (incident ray and refracted ray), we will draw a circle at the point of interface. After that we will draw perpendiculars from the point of intersection where the circle cut the incident and the refracted ray. The ratio of the length of the perpendiculars will give us the value of the refractive index. Hope this will help.
thank you sir
Very helpful 👍👍🙂...thank you
You're welcome and thank you so much for your appreciation. It means a lot. God bless 🙏
What an amazing video..
Very helpful indeed❤❤❤
You're extremely welcome and thank you so much for all your kind words of appreciation. It really means a lot to me. God bless you and your family 🙏
Very well captured . It's very helpful specially when students can't do experiments physically.
Sir,do u have videos made on other science experiments also that are syllabus (9 and 10) based?
Thank you so much for your appreciation. It means a lot to me 🙏
Please go through the channel for few other experiments.
Is it compulsury to take line NOM at centre ?
Thank u so much for your query. The St. line NOM is the normal about which we'll start measuring the angle of incidence & the angle of refraction, So without NOM ( the reference line) measurement can't be possible. Hope this will help. Regards
A good simple way, to explain refractive index
Thank you so much Mr. Feldman for all your kind words of appreciation. It really means a lot to me. God bless you and your family 🙏
Sir I have one question and the question is why the base of the all the four pin should appear to be in a straight line when seen through the block
isnt it bcs line of sight travel in a straight line?
It's because light travels in a straight line ...
Fantastic 👍👍👍👍👍👏👏🙌🙌
🙏
Sir how to observe the pins with one eye close or both eye opened
With both eyes closed
One eye closed
@@SabrinaXe lol
Good explanation. But there is no audio
Beautiful; this is a great and very helpful for me thanks to you for make this vidio Allah bless you a lot
Sir whoever you are wherever you are you helped me a lot thankyou so much for your kind favour on us
Thank you so much for all your appreciations. Regards
I feel physics experiments are just fun to learn.
thanks man, especially cause you didn't add a voice and kept the video silent
Thank you so much for your appreciation.
Thanks Sir this video is very helpful nice explaination
You're welcome 🙏
Superb camera work and Explanation Throughout the video
thanks for your appreciation
You have to use protector at the time of draw perpendicular.
This is how exactly my physics teacher thought
Good
thank you so much. It helped me to study for my exam and understand the topic better.
You're welcome Keerthi andthank you so much for your appreciation. It really means a lot. God bless 🙏
Today i have practical exam of class 10 😊
This video was really good..... The only error is that your normal isn't 90 degrees to the block, but i like how you made it work
Good Job mate!!!
It isnt 90?
Great work Science Sir....But missing the sound....
Thank you so much for your appreciation. I wrote every possible things that are necessary for this experiment, so just thought to keep myself quite, may be I should put some sound in it..anyway thanks again for all your feedback and appreciation. Best regards
Yess no doubt the video is complete...without sound or background music also.....
Waiting for your next videos....😊 Sir
My physics exam starts in an hour and here I am
How do I plot the graph
Exams tomorrow 👁️👁️
Wishing u all the best, feel free if u have any queries regarding this experiment. Best regards
Laws of reflection
super sir
leela Tiwari same
Same to u
... Would explain how we get a refracted view of the night sky... But the results of such could make people feel uneasy, or scoff and laugh. Depending on whether they had an overabundance of school and homework, but it would depend even more upon whether they actually DID the homework.
However absence of mind doesn't account for the multiple people who go missing when they talk about such things.
Thank you sir for this beautiful explanation ❤
excellent video sir, keep continuing your service for mankind.
Thank you so much for all your appreciations. Best regards
My exam starts tomorrow and I'm studying and practising now.
Btw this video was very helpful.👍
Thank you so much Mr. Alex for all your kind words of appreciation. It means a lot to me. Wishing you all the best for your exam. God bless.
@@science_sir thank you🙏
You're extremely welcome 🙏
Sir there are no sound
Thank you so much,😊😊May God bless you for this
You're welcome and thank you so much for your blessing. It means a lot. God bless 🙏
Great job! Keep it up sir
Thank you so much for your appreciation. Regards
This work is so clean and neat!!👍👍
Thank you so much for your appreciation. Regards
Where is sound sir
no sound
Its a great one video
Please make videos on ohms law experiment
Thank you so much for showing your interest. I will definitely try. Best regards
@@science_sir thank you sir
Ur most welcome.
Wish we could have these apparatus tools...or wish we would hv gained the knowledge as in time...bt
the silence really killed me
MUSIC 🎶
same
cartoon mania was alone with ma thoughts ......... deadly
For real... I actually pulled up some Ghostemane while watching this guy xD
Great video..🤗🤗
Thank you so much for your appreciation. Regards
Thanks a lot for making this video 🙏🙏🙏👍
You're welcome and thank you so much for your appreciation. It really means a lot to me. God bless 🙏
Nice one I really appreciate
Thank you so much for your appreciation. It means a lot. God bless 🙏
Thank u
How to find later displacement
To find the lateral displacement, we need to draw a perpendicular from the point of emergence to the dotted line drawn from the indecent ray. This perpendicular shift is the measure of the lateral displacement. Hope this will help.
Why 30°?
Lovely and gr8888 experiment...
Thank you so much for all your appreciations. Regards
Mathematically sir how we will prove that angle i =angle r
Thank you so much for your query. Are you saying about angle of incidence = angle of emergence? If yes, then that prove is given in the text book.
Determine width of grass block
Good job,Thank you sir.
You're welcome and thanks for all your appreciations. It means a lot to me
The video is understandable but it could have been better if an audio was attached to it
Thanks so much 😊
Thank you
Tomorrow is my practical
Because of you i Can now score out of
Thank you so much for your appreciation. All the best for your exams. Regards
Same here
Thirumalai nambi 🎈 Happy Birthday!
🔥 🔥 🔥
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Sir hamare book me angle of I angle of r angle of e diya hain or sin I or sin r ki value nikalni hai to me kya karu
Angle of I should be equal to angle of e (as the incident ray always parallel to the imergent ray). So try to draw an incident ray using given angle of incidence I (as it has give in the book). Then accordingly try to draw and complete the rest of the part. Now from the figure try to calculate the ratio of sin I and sin r. Hope this will help. All the best for your exams. Regards
Sir angle of I mera 30 aya hain or angle of r angle of e bhi 30 aya hai to sin I or sin r ki value nikalni hai to me kya karu matlab explained karo na kese nikalni hoti hain
Every values u got seems perfect. Now try to observe the value of angle of refraction using a protractor. Then using that (r) and (I) , try to calculate the ratio.
POV it’s your science practical tomorrow
Nice and easy explanation
Thank you so much for all your kind words of appreciation. It really means a lot. God bless you and your family 🙏
sir how can we calculate for few incident ray
+Jintu Kalita can't get your point
+Science Sir apne ek incident ray ke liye ye experiment ki hein. agar hum 5 incident ray k liye karte toh keise. only incident angle change kar de kya sir?
Jintu Kalita ya just change the angle of incidence, the corresponding all angles will automatically change
+Science Sir thank you sir😊
Thanks very much. It helped a lot.
Thank you so much for your appreciation. Regards
This video is really very helpful
🙏
So helpful answer
Thank you so much for your appreciation. It really means a lot to me. Wishing you all the best for your exam. God bless
Why we have chosen incident angle as 30
+Muhammad ayub Rajput angle 30 deg is easy to calculate without using scientific calculator. So for our convince we have taken this angle. U can take any other angle if u like. The result will be same at the end. Regards
Bro cool now I miss getting 20/20 on my physics practical tomorrow!
All the best for tomorrow. Regards
Thank you so much sir.
You're welcome Taslim and Thank you so much for all your kind words of appreciation. It really means a lot. God bless you and your family 🙏
You'r most welcome sir, I have subceibed your channel.
Thank you so much Taslim 🙏
Thank you so much sir for ur help, I am watching it A day b4 my exams👅👅
You're welcome and thanks for all your appreciation. Feel free if you have any queries. All the best for your exam.
Thank you soooooo much 😍😍😍❤.
You're welcome . God bless 🙏
full understanding video ,Thanx sir g
Ur most welcome
Is this for grade 11 ?
Yeah definitely.
Sir tomorrow is my exam your video helped me a lot thank you sir🙏🙏
Thank you so much for your appreciation. All the best for your exams. Regards
Mashallah. Nice Thanks. Sir.
Thanks for your appreciation. Regards
Did I know why emergence angle was 29° because angle of incidence is also 29°
In case refraction takes place in a glass slab, incident ray always parallel to the emergent ray, as they are parallel and the refracted ray can be considered as a transversal, the angle of incidence make equal angle with the angle of emergence. Hope this will clear your doubt. Regards
Science Sir yes
Feel free if you have any other queries.
Sir you are great . Thanks for your video. Sir aapka video ne hamari bohut madad ki. Thank you sir
Ur most welcome & thanks for all your appreciations. Regards
Es practical ko likhna kese hei
Sound will come after 4 min.
Good but there is no sound
How to draw the graph sir
Thanks for your query, are u talking about (Sin i) Vs (Sin r) graph ? please confirm
Science Sir yes sir