Since I tutor math, I appreciate that you consider what some teachers would like to see. "if your teacher ... divide everything by the largest power". It's important to be consistant with the classroom teaching.
9:56 you can also split the sum into two parts one with numerator n and one with numerator 2 and you can show that by the DCT both converge and therefore their sum converges. Obviously it’s important to note that you can only split up this sum because both parts of the numerator are strictly positive for all n in the sum and therefore you wouldn’t have an infinity - infinity case.
From the limit comparison test, we know if a_n ∈ Θ(b_n), then both (sum of a_n) and (sum of b_n) converges / diverges. Similarly, can I say if a_n ∈ ω(b_n) and (sum of b_n) converges, then (sum of a_n) converges?
Timestamps
Question 1: 0:01
Question 2: 4:31
Question 3: 6:23
Question 4: 8:33
Question 5: 13:01
Question 6: 15:59
Question 7: 19:31
Question 8: 21:50
Thank you!!
Since I tutor math, I appreciate that you consider what some teachers would like to see. "if your teacher ... divide everything by the largest power". It's important to be consistant with the classroom teaching.
9:56 you can also split the sum into two parts one with numerator n and one with numerator 2 and you can show that by the DCT both converge and therefore their sum converges. Obviously it’s important to note that you can only split up this sum because both parts of the numerator are strictly positive for all n in the sum and therefore you wouldn’t have an infinity - infinity case.
You are a good teacher ❤🫡🫡
I'm from Algeria, all of time i prefer to watch to your vedios that have a different ideas thank you for your efforts and continue in your way🥰💗
7:16 it's suppose to be greater than or equal to 1/n
I couldn't understand these until i saw the video 😊
thank you for this!! ❤ I keep hearing "dumber little part" instead of "dominating part"🤣
is 8:21 correct,? shouldnt it converge according to lhopitals rule??
19:30 was pretty cool 😂
Maybe some homework questions at the end of the video
Yes, 100 series! 😆
Sweet
♥
From the limit comparison test, we know if a_n ∈ Θ(b_n), then both (sum of a_n) and (sum of b_n) converges / diverges. Similarly, can I say if a_n ∈ ω(b_n) and (sum of b_n) converges, then (sum of a_n) converges?