Wow! On my second semester of orgo and so for these videos have been extremely helpful. I cannot thank you enough, definitely deserve way more recognition.
You're very welcome Unterhosegotti! I'll actually be re-filming this lesson using a white board in the Spring semester and hope to actually improve on it so we'll see! Happy Studying!
Thank you for the video! I'm in a graduate program in a class for Molecular Spectroscopy and this was helpful. I have one question though: Does it matter which Hydrogen you observe? If so, how do you know which one to look at to determine how many peaks?
Hi, maybe I'm too late but perhaps someone else is wondering the same thing. The way I'm learning to do it is that all of the unique protons show up in the spectrum. To clarify, you observe all of them, each one has its own individual peak/cluster of peaks. Unless you are referring to which one as in which of the 3 hydrogens on, for example, a CH3 group, then the answer to your question is that they share the same environment so they will just show up as a single peak/cluster of peaks. If I misunderstood or am being wrong here someone please correct me.
For the second example (with Z-1-chloroprop-1-ene), why would the peaks of the quartet of doublets all be the same height? Wouldn’t the peaks in the center be higher?
Nice! And OOOHHH you teach?! I just checked out your channel. Loved your intro to Ochem..."And then God created carbon"😆 Fantastic! I wish you and your students the best!
This video really helped my understanding! For the last example where there are the two equivalent red hydrogens, would there be any change in the NMR spectrum if there was only one hydrogen? I would imagine both hydrogens are split the same way as they are equivalent so would this double the intensity on the proton NMR spectrum?
The only change for this signal would be in its intensity as you suspected. With the signal representing half as many hydrogens it would have half as much area under the peak (i.e. half the integration). Hope this helps!
You're exactly right! It would technically still be a doublet of doublets that just "looked like" a triplet. Also note that the J value for cis splitting is 6-12Hz and the J value for trans splitting is 12-18Hz. In the video I chose a value in each range and just happened to choose 8Hz and 16Hz. But had I chose any values within these ranges that were not in a 2:1 ratio then we would definitely see the doublet of doublets properly. I really should have chosen better representative numbers within those ranges to have avoided this. I'm remaking the whole playlist using a whiteboard and when I get to this lesson I will remember not to repeat this error! Thanks!
Wow! On my second semester of orgo and so for these videos have been extremely helpful. I cannot thank you enough, definitely deserve way more recognition.
Glad you've found them helpful Juan!
same
I learned this topic now!!! he explains all the details very well, thank you very much :)
Awesome Samira! 🙂
thanks omg I was having a meltdown before my final
You are welcome, Ale - good luck on your final!
this is it. this is the video. thank you my guy
Awesome Jamie! Glad you found this helpful!
Best video in this topic out there and way better than my professors, thanks
You're very welcome Unterhosegotti! I'll actually be re-filming this lesson using a white board in the Spring semester and hope to actually improve on it so we'll see! Happy Studying!
@@ChadsPrep im pumped
very good! Im always in need of a refresher for more complicated splitting. Good video!
This is really helpful. It makes so much sense now!
Glad to hear it, Julia!
Thanks chad
You're welcome - Happy Studying!
This was incredibly helpful, thank you
Glad to hear it, grodspott!
Thank you for the video! I'm in a graduate program in a class for Molecular Spectroscopy and this was helpful. I have one question though: Does it matter which Hydrogen you observe? If so, how do you know which one to look at to determine how many peaks?
Hi, maybe I'm too late but perhaps someone else is wondering the same thing. The way I'm learning to do it is that all of the unique protons show up in the spectrum. To clarify, you observe all of them, each one has its own individual peak/cluster of peaks. Unless you are referring to which one as in which of the 3 hydrogens on, for example, a CH3 group, then the answer to your question is that they share the same environment so they will just show up as a single peak/cluster of peaks. If I misunderstood or am being wrong here someone please correct me.
Thanks a lot for the last example :)
You're welcome!
Super helpful. Thank you!
You're welcome, Nastia!
Super helpful, thank you so much!
Glad you found it helpful Joshua! Happy studying!😊
Amazing Video !!!!!!!!!!!
Thank You!
6:42 qd are not with equal intensity!!! 1:1:3:3:3:3:1:1
thank you very much for this video. It has helped me very much :)
Awesome Paula!🙂
For the second example (with Z-1-chloroprop-1-ene), why would the peaks of the quartet of doublets all be the same height? Wouldn’t the peaks in the center be higher?
the best.
Thank you
Excellent presentation.
Thanks Chemistryrussell! Love the name!
@@ChadsPrep I used this video for my organic II class. They got it!
Nice! And OOOHHH you teach?! I just checked out your channel. Loved your intro to Ochem..."And then God created carbon"😆
Fantastic! I wish you and your students the best!
@@ChadsPrep thanks! That means a lot. Same to you and yours!
Thank you sir, from India
You are welcome - thanks for watching!
And one more thing...lots of prayers going up on behalf of your country. God bless.
This video really helped my understanding! For the last example where there are the two equivalent red hydrogens, would there be any change in the NMR spectrum if there was only one hydrogen? I would imagine both hydrogens are split the same way as they are equivalent so would this double the intensity on the proton NMR spectrum?
The only change for this signal would be in its intensity as you suspected. With the signal representing half as many hydrogens it would have half as much area under the peak (i.e. half the integration). Hope this helps!
Very Good explication would be cool also to do for benzene substituent and other cyclic compound
thank you so much
You're welcome so much!
Hi! For the sextet example, could you call it a quartet of triplets in addition to a sextet? Or no?
I want to know about this too T_T
love you
Glad you found the channel!
excellent
Thank you, Peter - Cheers!
amazing
Is example 1 incorrect? If you split by 16 and then by 8 the two middle peaks would end up overlapping and make a triplet.
You're exactly right! It would technically still be a doublet of doublets that just "looked like" a triplet. Also note that the J value for cis splitting is 6-12Hz and the J value for trans splitting is 12-18Hz. In the video I chose a value in each range and just happened to choose 8Hz and 16Hz. But had I chose any values within these ranges that were not in a 2:1 ratio then we would definitely see the doublet of doublets properly. I really should have chosen better representative numbers within those ranges to have avoided this. I'm remaking the whole playlist using a whiteboard and when I get to this lesson I will remember not to repeat this error! Thanks!
hey, why the neighbor H in the last example are not equal i mean the is no double bond
Is this regarding the 3Hs on the left versus the 2Hs on the right? They have different environments due to the presence of the Br.
Are you such good in class or in class you are like my teacher?
What you see is what you get! 😁😁😁
What an intro! 😂
Let's go-go-go! 🙂
HAMAAAAN
Hey back, Michael - hope you found the video helpful.
Thanks my teacher did a dogshit job explaining this
Glad we could help.