For the differential equation part (the part when he integrated both sides with different limits), I don't really understand why does it work since both sides are of different quantities. For me I will just integrate indefinitely to obtain a general equation with c then use [A]_0 to complete the equation.
The graph is the same as a linear function y=mx+b. In this case, ln[A] is the y in linear function, t is x, and -k is m. Since k is positive, -k must be negative, which makes the graph go downward.
Which Khan Calculus video should I watch to understand this one?
+Jose all of them
The one with Calculus in it
This is an application of differential equation.
You need to go through Derivatives, Integrals before you do Differential Equations
I don't understand what is "d" starting at 1:25 ? What happened to Delta symbol above?
it's a derivate, from calculus
Nathan Parrish 'd' is for the instantaneous rate
Nathan Parrish 'd' is the smaller change cuz its instantaneous whereas delta is the larger change in concentration
th-cam.com/video/zCJALBbWeLM/w-d-xo.html
Rather than go through all the steps will the last equation work?
THANKS !!
im in ap chem and ap calc ab and about to have my chem test, i was curious
all vedios sound is very low that we cannot heear them rightly
For the differential equation part (the part when he integrated both sides with different limits), I don't really understand why does it work since both sides are of different quantities. For me I will just integrate indefinitely to obtain a general equation with c then use [A]_0 to complete the equation.
th-cam.com/video/zCJALBbWeLM/w-d-xo.html
Your method also works. He uses accumulation function which has been discussed in AP Calculus.
This was blessed. Thanks man. #APSC132
I am a Tiger what is APSC132
Queen's University 2nd Sem 1st year engineering chem.
This is how you calculate the physics of starkiller base
Why is the line of the graph straight and going downward? Can anyone pls explain
The graph is the same as a linear function y=mx+b. In this case, ln[A] is the y in linear function, t is x, and -k is m. Since k is positive, -k must be negative, which makes the graph go downward.
Remember, the equation is ln[A]=-kt+ln[A]0
Can't we do this without using calculus?
No, lol.
Learn some calculus is always helpful on learning ANY sciences.
@@tobywang9679 we don't have calculus in our syllabus tho, but anyways I'm learning it
is this like college level stuff in america?
This is first year level chemistry, how is it in your country?
@@shahbukhari2573 It is taught in class 12 in India..
Is there a way to do this without calculus?
Shah Bukhari
yep, just stick with the derived equation ln([A]_t/[A]_0) = -kt
I still can't get my head around why you take the natural logs. Is this some log law I've missed?
+Chewie Lewie they are tabelar integrals
It is the integral of (1/[A]) d[A]. If you know your calculus, then you know that the integral of 1/x dx = ln(x). It's the same thing.
goclbert yup cheers
Please slow down....youre working through this too fast
setting -> speed 0.5