from what I understood, u need to cancel the three from the right equation, in doing so u need to multiply 3 on both sides, that is why -0.750x3=-2.25 idk if this would help
Because it’s set up as an equality or equation where [🔺A]/🔺t = [🔺B]/🔺t. So when you plug it in you have to multiply by 3 both sides because 🔺B is multiplied by 1/3 or in other words, divided by 3. In the stoichiometric relationship B is multiplied by 3 but for this math to workout it’s the inverse. He was just using multiplication to get rid of the division to find the value of 🔺B
Hi, in the last problem of the video, in the equation i might consider rate of the hydrogen, example: -d[o2]/ dt - 1/2 d[h2]/dt = 1/2 d[h2O]/dt? or not?
Yes you may write an expression in terms of H2: -1/2 d[H2]/dt = 1/2 d[H2O]/dt However, since the problem is providing you a rate for O2, it makes more sense to write the rate expression in terms of O2 and go from there.
In a bimolecular elementary Reaction When the concentration of one of the reactants is in large excess compared to the other, the rate of the reaction becomes independent of the concentration of that reactant. Is this statement true or false,could you explain
Yes this is basically true. Imagine you are making sandwiches and that you have 1,000 slices of bread spread on the counter but only 10 slices of cheese somewhere on the counter. The rate at which you can make sandwiches is really only determined by your ability to find the cheese, because there is bread readily available everywhere (it is in large excess).
can i invent a thing through chemistry can stop the mechanism of converting food to fat into body and instead maybe converting to muscle or just take the nutrients and throw the rest to poop cuz i want to stop getting fats on my body :)
20 years after chemistry wrestled with my brain, here comes a clear lecture that would have made life way much more easier
Amongst all the TH-camr i know, you are the one who made me understand this very well...thanks bro!
he explains it practically where we can actually use the concept
Ghana man n chemistry
Bookmark 15:00 plotting rate data
Keep it up we know that you make as to understand what you teach
This was so helpful!!
22:20 why is it not -0.250M/min?
if delta [A] is -0.750, then isn't delta [B] just -0.750/3 ?
from what I understood, u need to cancel the three from the right equation, in doing so u need to multiply 3 on both sides, that is why -0.750x3=-2.25 idk if this would help
@@aishahplaza808 i mean actually it's 3/0.750 equals to 2.25💀
@@yeshasmarak6365 i mean use calculator bruh
@@aishahplaza808 yeah yeah I'm sorry i didn't see that is was 0.25 💀 (i also forgot to correct the comment too.)
2 yrs late: i think its b/cuz [b2] is 1/3 of [a2] so that factors into why its 3 * (-.750) and not -.750/3
Thank you can you give us this pdf?
Im not attending that afternoon class 😂
I don't really understand plotting graphs
I literally suck at it
Please, can anyone perhaps suggest a link to a site that handles this?
Why did we multiply everything by 3 to find the final answer in the last practice problem
Because it’s set up as an equality or equation where [🔺A]/🔺t = [🔺B]/🔺t. So when you plug it in you have to multiply by 3 both sides because 🔺B is multiplied by 1/3 or in other words, divided by 3. In the stoichiometric relationship B is multiplied by 3 but for this math to workout it’s the inverse. He was just using multiplication to get rid of the division to find the value of 🔺B
sir, how can we get the slides you used for your video
Unfortunately, I only post those to my official class page at university
wonder if i’ll learn this someday
take engineering and its in 1st semester chemistry :(
and now im learning this today😂
Was helpful
Thanks
Easy to understand
Hi, in the last problem of the video, in the equation i might consider rate of the hydrogen, example: -d[o2]/ dt - 1/2 d[h2]/dt = 1/2 d[h2O]/dt? or not?
Yes you may write an expression in terms of H2:
-1/2 d[H2]/dt = 1/2 d[H2O]/dt
However, since the problem is providing you a rate for O2, it makes more sense to write the rate expression in terms of O2 and go from there.
In a bimolecular elementary Reaction
When the concentration of one of the reactants is in large excess compared to the other, the rate of the reaction becomes independent of the concentration of that reactant.
Is this statement true or false,could you explain
Yes this is basically true. Imagine you are making sandwiches and that you have 1,000 slices of bread spread on the counter but only 10 slices of cheese somewhere on the counter. The rate at which you can make sandwiches is really only determined by your ability to find the cheese, because there is bread readily available everywhere (it is in large excess).
so many lightbulb moments I've had in this one video lol
Thanks I appreciate
i love it thanks so much !
nice explanation
ti was really helpful thank you :")
Thank you 😊
Good
We can see the full screen....l didn't see the examples
can i invent a thing through chemistry can stop the mechanism of converting food to fat into body and instead maybe converting to muscle or just take the nutrients and throw the rest to poop cuz i want to stop getting fats on my body :)
Sadly no. Maybe in 100 years we'd be closer to that, but no time soon :(
Why are including a negative sign 😊
thank you sooo much!
God bless u
thank you
0.750 / 3 =0.250
❤️
Thanks you 🥰
Thanks 👍❤️