Professor, I did not get the concept of how you figured out the roots or the 3rd degree equation using this method of "synthetic division". Is there another video in another playlist where you have explained this? If not, could you please describe the method? Thank you.
I will try to explain the problem question: The function y = 1 - e^-x for x=0 or/and x>0 . Does have a point P on the graph which we draw one line straight down to the x-axis and one line straight to the y-axis. These create a rectangle with the corner P on the graph. The function y=1-e^-x splits the rectangle and there becomes two areas, A¹ and A², what we know is that A¹ / A² = 1 / 2 . Determine the x-coordinate of the point P. Michael I love you and this math problem and you have to solve it I cant sleep at nights because of this problem.. I wish u a very good week, from Sweden.
Professor instead of using your method in the video in finding the closest point to (3,1), how about using the perpendicular of the derivative of the given equation (y = x^2 + 1) and equate both the derived equation and its perpendicular to find x which is easier?
I think that you can leave out the square root since its monotonous function so it will not affect the solution.
3:27 "oops, I'm getting ahead of myself" me too bud, lol
Fantastic explanation. I now have a much firmer grasp on this concept. Thank you sir!
Amazing explanation you give. I always watch your videos
Professor, I did not get the concept of how you figured out the roots or the 3rd degree equation using this method of "synthetic division". Is there another video in another playlist where you have explained this? If not, could you please describe the method? Thank you.
That is explained here in this playlist: ALGEBRA 47 - SYNTHETIC DIVISION
Thanks Sir...However you did not solve the quadratic polynomial after the synthetic division.
Michael, I have an interesting calculus II question of this problem type, do u have a email? So i can send a picture of the problem
I will try to explain the problem question: The function y = 1 - e^-x for x=0 or/and x>0 . Does have a point P on the graph which we draw one line straight down to the x-axis and one line straight to the y-axis. These create a rectangle with the corner P on the graph. The function y=1-e^-x splits the rectangle and there becomes two areas, A¹ and A², what we know is that A¹ / A² = 1 / 2 . Determine the x-coordinate of the point P.
Michael I love you and this math problem and you have to solve it I cant sleep at nights because of this problem..
I wish u a very good week, from Sweden.
@@awinbmx7418 Do you still want to do this problem?
@@jennali9800 yea lol im curious, send me your email, I remember the problem in my head, and I also have it on paper cus I wrote it down after my exam
@@jennali9800 wait nvm this one my teacher have gone through with me already
@@awinbmx7418 alright, got it. have fun lol
Professor instead of using your method in the video in finding the closest point to (3,1), how about using the perpendicular of the derivative of the given equation (y = x^2 + 1) and equate both the derived equation and its perpendicular to find x which is easier?
Did you try it?
@@MichelvanBiezen Yes sir and I still came up with the correct answer which is (1,2).
What's the point of taking derivative?
If you here for AOD for IIT JEE/CBSE Board.....U Are not alone
perfect short videos for emergency
Helped a lot thnku
Glad you found it helpful! 🙂