You literally explained what I wanted to know in 3minutes compared to the hours I used to search up how to do this kind of question online. You are best teacher I've ever seen
Helping daughter with math and a teacher who hands out packet after packet. You're my go to whenever I need to relearn all this stuff and then put it into a language she understands. Much appreciated
Tbh your videos are really helpful. You explain better than my own teacher. I might as well just learn from you. Thank you for helping me understand everything and I just want to say that I really appreciate these videos that you put up.
@@altamashakhtar847 It's been 2 months so you probably found the answer already lol Just in case: You can take x out of each term to make it x(8x^2 - 8x - 9) Then, just solve like a normal quadratic equation. Afterwards, your answers will be the same as in a quadratic equation, but 0 will also be a solution.
I really wish you were my actual teacher its crazy how complex my teacher has made this seem and you made it clear to me. I've always took twice as long as everyone else to understand math but you really are helping me catch up
Thank you so much Mr.Brian. I really appreciate you for taking your time and making these videos. I am preparing for SAT, and your videos are very helpful and easy to understand. They are literally keeping me from giving up on math. Thank you so much🙂!!!
@@OilyMonkeyCheeks you're close but since (x^2 + 9) isn't a difference of squares it can't be split (x^2 - 1) however, can be split into (x+1)(x-1), giving us our finished factored form of (x^2+9)(x+1)(x-1)
After much frustration and eventually consulting Wolfram Alpha, I came up with x^2(x+3)=4, and the knowledge that (x-1) and (x+2) are factors. I wasn't aware you could divide it with the polynomial made by expanding the two factors, and ended up with (x^2+4x)(x-1), which expanded, gives me x^3+3x^2+4x. Which is why I went to Wolf, and it gave me (x-1)(x+2)(x+2) or (x-1)*(x+2)^2. Thank you for this problem! I loved struggling with it.
hey brian! i love your math lessons so much, they help me with my exams. do you mind explaining how to write a to the power of 2 multiplied by a to the power of 4 and a to the power of 2 divided by a to the power of 4 as a power of a? thank you
multiplying a^2 times a^4 results in a^6 a^2 divided by a^4 is the same as saying 1/a^2, or a^-2 All this is showing is that multiplying powers is adding the powers together, and dividing is the opposite- subtraction.
then you would need to either factor it out or use the AC method, here is a playlist I have th-cam.com/play/PL0G-Nd0V5ZMrTIyt4NQFykiyDuWfF_M6S.html the factors are linear but you would just raise them to being squared if your polynomial was quartic
When you're looking at a polynomial with the structure ax^2 + bx + c and trying to factor it into the factored form (x+m)(x+n), the rules are pretty simple m+n = b m*n = ac If either m or n turns out to not be an integer, you have to use the quadratic formula instead
I have been sitting here trying to factor x^4-12x^2+27 for the past 30 mins when it was actually just taking x^2-12x+27 and squaring the x's in the factors. Why'd my teacher never teach me this bruh.
Factor the trinomial fast without substitution - th-cam.com/video/eMiBG0MhPqQ/w-d-xo.html
You literally explained what I wanted to know in 3minutes compared to the hours I used to search up how to do this kind of question online. You are best teacher I've ever seen
He is good like that. I'm just surprised he still has videos out for the level of math I do as when I first needed him I was in the 6th grade.
good teacher, annoying class
haha sorry about that
🤲
I feel like he’s shouting at me😂
Same like that only I had fell bro
I also feel that
And I also 🤪🤪🤪
NOWW UMMM
I know right 🤣😂
This is how maths should be taught. Simple and easy. Thanks Mr Brian. Appreciate you for taking your time to explain to us all.
agree! happy to be able to help you out!
Man i wanted to write down the critical thing at the end of the video 3:21 😩
@G0dPvP SAME!!!
ill never know what the critical thing he wants me to write down is 🥺
Yaa😞
😂
Helping daughter with math and a teacher who hands out packet after packet. You're my go to whenever I need to relearn all this stuff and then put it into a language she understands. Much appreciated
you are very welcome!!
Tbh your videos are really helpful. You explain better than my own teacher. I might as well just learn from you. Thank you for helping me understand everything and I just want to say that I really appreciate these videos that you put up.
you explained this so clearly! thank you so much!!!
lol that kid who said "you think you're sweet?"
🤣🤣🤣
im really glad you post these videos , your teaching style is very effective and proprietary
happy to help Adrian!
(1-x^2)(2-x^2)=4m
m is constant
Find x
Yea I like Brian he teachers you step by step and it’s easier to understand.
I know the teacher I got seems like she takes the long steps ways and explain it fast
MIND BLOWN. I bet I got this at one point and forgot it because its so simple. You explained it in a really good way.
i binged half your videos to finish this humongous assignment i had it put off and you helped me astronomically tysm
This really helped a lot, easier than it seems..thank you!
great teacher. Respect from India
Nice. Things like these make it easier for students who are enrolled in online classes. Thank you for putting this here for everyone.
absolutely!
Oh my gosh, i was stuck on a problem for hours and then i watched this video, i finally got it!! Thank you SO much
Can you help me?
You are the great to explain this simple version
Thanks sir g
i like yo cut g
Thank you! Thank you! Thank you! You always make so much sense and write easier ways to get it done fast!
This video stresses me out.
sorry about that Zak, just think of it as x^2+8x-9 and then raise the power of the factors
You
Sir can you solve this :- 8x3-8x2-9
@@altamashakhtar847 rip man
@@altamashakhtar847 It's been 2 months so you probably found the answer already lol
Just in case: You can take x out of each term to make it
x(8x^2 - 8x - 9)
Then, just solve like a normal quadratic equation. Afterwards, your answers will be the same as in a quadratic equation, but 0 will also be a solution.
I would have used x² = t and re-written it out as t² + 8t - 9 and factored that out as (t + 9)(t - 1) ans substituted x² back in
This is really helpful!
I so wish I had watched this before going to today's exam
ahh bummer, next time
You summed up what took me an hour - thank you
happy to be able to help you out Ellie
I really wish you were my actual teacher its crazy how complex my teacher has made this seem and you made it clear to me. I've always took twice as long as everyone else to understand math but you really are helping me catch up
Man you just solve my problem that's been stuck for a week 😂 thank you man 👍
Thank you so much Mr.Brian. I really appreciate you for taking your time and making these videos. I am preparing for SAT, and your videos are very helpful and easy to understand. They are literally keeping me from giving up on math. Thank you so much🙂!!!
So happy to be able to help you out!!
@@brianmclogan I understand how you got your final answer, but can’t you factor it more for (x^2+9) to (x+3) and (x+3)?
@@OilyMonkeyCheeks you're close but since (x^2 + 9) isn't a difference of squares it can't be split
(x^2 - 1) however, can be split into (x+1)(x-1), giving us our finished factored form of (x^2+9)(x+1)(x-1)
Teachers like this are the reason I have anxiety in a classroom lol, good, straightforward teaching though this really helped me today thank you 😊
You could also use direct substitution, I got X = +or- 3*i, 1
How would you factor -1/3x^3+x^2-4/3=0 ?
Yaa, im also trying to figure it out😞😞 Brian sir please explain🙏
Itna asan nhi hora
@@aparichit9728 nhi hora, tum explain kar do plzz🙏
After much frustration and eventually consulting Wolfram Alpha, I came up with x^2(x+3)=4, and the knowledge that (x-1) and (x+2) are factors. I wasn't aware you could divide it with the polynomial made by expanding the two factors, and ended up with (x^2+4x)(x-1), which expanded, gives me x^3+3x^2+4x.
Which is why I went to Wolf, and it gave me (x-1)(x+2)(x+2) or (x-1)*(x+2)^2.
Thank you for this problem! I loved struggling with it.
I have some students who don't understand cause their not paying attention... oops actually I did it wrong.
haha yea........
Thank you! :) This was really helpful!
thanks! teacher never taught this
you are a legend Mr. Brian, thanks for the lessons
This is fantastic . Thank you man👍👍👍👍
sir we can also let x^2=a then x^4+8^2-9=a^2+8^a-9 it will be easy to solve and after factorizing put value of a=x^2
But how do you graph (x²-1)(x²-4)
Thank you so much this helped me a lot
Thank u Takle, samjhane ke liye love from india
If anyones confused, what he did was; Let X=x^2 and then factored it in terms of X then subbed the x^2 back in.
yes called substitution
x squared minus one is diff of 2 squares so we can simplify it more
Yo, if there was a coefficient in front of the x^4 what would you do differently
Thank you a thousand fold
Wow what a nice teacher!! 🙅🙅
Brian mclogan (x^2-1)=(x+1)(x-1) so we can factorize it one more time
Got an algebra 2 final tomorrow so i'm watching a bunch of your vids to review lol. Thanks for making these!
you are very welcome! best of luck!
Finals in January???
Lightning Mcqueen Yeah midterms
SkolWorks Edits what did you get bro?
Thank you sir❤️
This Helps me a lot
Thanks teacher
Thank you ❤
Wow thank you so much. This was really helpful.
: )
Thank you!
Who ever has this teacher is so lucky
Thank you so much!!!!
Can you only use x squared or are there cases where you would have x and x cubed
this is the guy u need in ur class
Thank you
how would you find the x-intercept? if it was quadratic equation and factor it u could just know the x-intercepts but how would you do for this one?
my mans i fucked this up rn on my advanced functions test
Heyy sir , I was really struggling with these questions, thank you very much for explaining it in and easier way
Cheers, good video. 👏👏👏
Thankyou sir🙏
doesnt the (x^2 -1) need to be factored out into (x+1)(x-1)??
Factorisation is now clear
much thanks
What about complete factorization??
Thanks brother
Question: when you combined 9x (squared) with X (squared) how does this give you 8 X squared?
9x^2 minus x^2 🤷♂️
@@リズワン Can you help me?
hey brian! i love your math lessons so much, they help me with my exams. do you mind explaining how to write a to the power of 2 multiplied by a to the power of 4 and a to the power of 2 divided by a to the power of 4 as a power of a?
thank you
multiplying a^2 times a^4 results in a^6
a^2 divided by a^4 is the same as saying 1/a^2, or a^-2
All this is showing is that multiplying powers is adding the powers together, and dividing is the opposite- subtraction.
U got nuts but still I gotta be helpful now I'm gonna watch it
Not fully factored, the fully factored form would be (x^2+9)(x+1)(x-1) due to there being a difference of 2 squares
u sure?
@@arminaantigro6380 Hundred percent sure
x^2 - 1 is the same as (x+1)(x-1) because the two factors are conjugates
@@Hazelpy I checked, u'r right, can u factor x⁵ + x³ -2x+1? or x⁴?
Not factorable, no
Could you use synthetic division to find the factors of this polynomial?
x^3-6x^2+11x-6 || x3-6x2+11x-6 || x^3-6x^2+11x-6 बहुपद के सभी शून्यक ज्ञात करें
th-cam.com/video/nkWKuXsdbss/w-d-xo.html
Thanks
Very good ☺️
You gotta love how this man just does not take shit
What if leading coeff is not 1 but greater than 1
then you would need to either factor it out or use the AC method, here is a playlist I have th-cam.com/play/PL0G-Nd0V5ZMrTIyt4NQFykiyDuWfF_M6S.html the factors are linear but you would just raise them to being squared if your polynomial was quartic
thanks for this!
I'm in calc 2 and I just watched this video because im a dumb dumb doing integrals by partial fractions and couldn't factor a polynomial lol
Hey Brian, could you do a problem with the numbers in the layout of (x+y)^z
THANK YOU!! i get it now.
Brilliant trick
Thank u big brain 🙏🏻 ur the best 💯 #mclogang 😩🤫
more like#fucklogang
I feel like im learning from a Xbox player in cod 3
Thankyou
Could you show examples of how to solve Factoring a quadratic with leading coefficient? (y+m)(y+n) example: y2-13y+12. Please Help.
When you're looking at a polynomial with the structure ax^2 + bx + c and trying to factor it into the factored form (x+m)(x+n), the rules are pretty simple
m+n = b
m*n = ac
If either m or n turns out to not be an integer, you have to use the quadratic formula instead
teehee I love looking through and replying to old comments 😋
3x2+18x+15=0
for x^4 + x^2 -1 = 0 not working.
not all heroes wear capes
Thanks for the help!
you are very welcome!
My volume was all up and I got scared 😂
Clicked on the video with 1/3 volume and still almost jumped out of my seat 😂
CometPM 😂 lol
factorise x^4+x^2+1
This is absolutely what I needed, thank you so much.
you are very welcome!
How do you do it if all three numbers have an x?
A little late but factor out an x from all three terms and it should leave you with something more familiar! Hope this helped!
why leaving 8?
solve the equation for m is such that m^4-7m^3+15m^2-13m+4
What we have to find
The value of m is 1
I have been sitting here trying to factor x^4-12x^2+27 for the past 30 mins when it was actually just taking x^2-12x+27 and squaring the x's in the factors. Why'd my teacher never teach me this bruh.
Waste of time for India ( Hindi medium)😂😂😂
Thanks for the information....it was helped.....
awesome! happy to be able to help