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s = input() for i in range(0,len(s)): count = 0 for j in s: if int(j)==i: count+=1 else: pass if count != int(s[i]): print("It is not a autobiographical number") break else: print("It is a autobiographical number")
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I am a 4th year mechanical student I don't know what type of questions that come into the Accenture coding round, this video series is helping me to get the confidence for coding round... thank you .. thankyou so much❤..I definitely share all my mechanical student friends those are feel fear to clear the coding round.. thank you 🙏..and brilliant explanation
Hey☺ We have great audience like you who encourage us to better ourselves day by day❤ Stay tuned with us for latest job updates in our socials: Telegram- prepinsta.com/telegram/ Instagram- prepinsta.com/instagram/ WhatsApp- prepinsta.com/whatsapp/
Firstly thanks to Prep Insta for this wonderful video.And when coming to this video the explanation of the given code was awesome and we are clearly understanding the code was important for us
Hey there Viswanath! 💕 We're glad we could be of help 🤗 Make sure to check out PrepInsta Prime for dedicated preparation materials, courses and more! prepinstaprime.com/ Feel free to reach out to us over Instagram: www.prepinsta.com/instagram/ Or drop a message on bit.ly/primeWA Or call us on 8448440710. Our mentors would be very glad to help you out with your queries and placement. Team PrepInsta is always here to help!
pythoon ans:(it took around 53mins to complete it)... How i will get the accenture 😥😥 def FindAutoCount(n): a=[] for b in range(len(n)): a.append(int(n[b])) count=0 for c in range(len(a)): if 0==a[c]: count +=1 if a[0]!=count: return 0 for d in range(1,len(a)): count1=0 for e in range(len(a)): if a[e] == d: count1+=1 if count1 != a[d]: return 0 z=[] for x in range(len(a)): if a[x] not in z: z.append(a[x]) return len(z) n="6210001000" Subham = FindAutoCount(n) print(Subham)
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here it means the list of certain length is created with all the values to be 0, like in this question counts=[0]*10 =======> counts=[0,0,0,0,0,0,0,0,0,0] Just a method to create empty list of a fixed length
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Kudos to the team for putting together such a fantastic learning opportunity. Looking forward to unlocking even more knowledge with the free app subscription!.
Hey ☺
We are blessed to have your words.
Stay tuned with us for latest job updates in our socials❤
Telegram- prepinsta.com/telegram/
Instagram- prepinsta.com/instagram/
WhatsApp- prepinsta.com/whatsapp/
Sb moh maya h kuch nai milega yha bhai
s = input()
for i in range(0,len(s)):
count = 0
for j in s:
if int(j)==i:
count+=1
else:
pass
if count != int(s[i]):
print("It is not a autobiographical number")
break
else:
print("It is a autobiographical number")
This autobiographical number question is mock test question
Incredibly helpful!. Brilliant explanations❤
Yayyy! Happy to hear that.
Keep up the good work 👍
Hey☺
We can do, because we have great audience like you ❤
It would be great if you stay connected to us over our socials!
Follow our social media handles listed below.
Telegram- prepinsta.com/telegram/
Instagram- prepinsta.com/instagram/
WhatsApp- prepinsta.com/whatsapp/
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LinkedIn- www.linkedin.com/company/prepinsta/
Discord- prepinsta.com/discord
I am a 4th year mechanical student I don't know what type of questions that come into the Accenture coding round, this video series is helping me to get the confidence for coding round... thank you .. thankyou so much❤..I definitely share all my mechanical student friends those are feel fear to clear the coding round.. thank you 🙏..and brilliant explanation
Hey, we appreciate your feedback. 💕
Stay tuned with prepinsta for more learning. 🤟
Bro I am also final yr mechanical student...how are u preparing for coding..we have exam on wednesday.can I know ur num
Thank you sir for making such as useful content...
Happy! Happy , Happy! Thank you for the feedback ☺😎🎀
Amazing video I really need this video it very informative please provide more such video to build logic👍
Din bana diya! Thank you 😊
This video's are very informative,and useful to the students.keep going 🎉
Yayyy! Thank you for the feedback.
Thank u for ur videos. it does help us in preparations!
Hey☺
We have great audience like you who encourage us to better ourselves day by day❤
Stay tuned with us for latest job updates in our socials:
Telegram- prepinsta.com/telegram/
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public class Main{
public static void main(String[] args) {
String s="6210001000";
int val=0,t=0;
for(int i=0; i
Join our TA Support Group on Discord, where we will help you out with all your technical queries:
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Firstly thanks to Prep Insta for this wonderful video.And when coming to this video the explanation of the given code was awesome and we are clearly understanding the code was important for us
Hey there Viswanath! 💕
We're glad we could be of help 🤗 Make sure to check out PrepInsta Prime for dedicated preparation materials, courses and more! prepinstaprime.com/
Feel free to reach out to us over Instagram: www.prepinsta.com/instagram/
Or drop a message on bit.ly/primeWA
Or call us on 8448440710. Our mentors would be very glad to help you out with your queries and placement.
Team PrepInsta is always here to help!
in your google drive link there is no code files from video2
yes
sir whether inbuilt functions can be used ??
Hi,For technical related queries you can freely connect with our TA's on discord. Here is the link prepinsta.com/discord 🙌🧐
thank u soo much
Glad it helped you!!!
your google drive folder is not containing correct file .
This video is really helping me for my placement preparation.
Thank you! Stay connected for more such content ☺
pythoon ans:(it took around 53mins to complete it)... How i will get the accenture 😥😥
def FindAutoCount(n):
a=[]
for b in range(len(n)):
a.append(int(n[b]))
count=0
for c in range(len(a)):
if 0==a[c]:
count +=1
if a[0]!=count:
return 0
for d in range(1,len(a)):
count1=0
for e in range(len(a)):
if a[e] == d:
count1+=1
if count1 != a[d]:
return 0
z=[]
for x in range(len(a)):
if a[x] not in z:
z.append(a[x])
return len(z)
n="6210001000"
Subham = FindAutoCount(n)
print(Subham)
wish i had prime , content is great
Hi, Yes you can get an instant discount on prime now prepinstaprime.com/ Kindly give us a call on 8448440710.
Could have simply used dictionary and returned it's length
Hi, Great you have answered. For technical related queries you can freely connect with our TA's on discord. Here is the link prepinsta.com/discord 🙌🧐
❤
Stay Connected!
Please make a video on how to prepare for computer basics and Microsoft fundamentals, networking part of accenture test
Hey😊
We will surely forward your message to our team.❤
You can refer this link for Accenture preparation: prepinsta.com/accenture-previous-papers/
We are allowed to do coding in Python right? Please reply
yes ,we can do
Yes, you can code in your preferred programming language.
What if both of my code is wrong?😢will they reject me
Yes, they will
28 th I have exam 4 pm evening
Great! How it went?
Feel free to share us the experience here.
Also, For technical related queries you can freely connect with our TA's on discord. Here is the link prepinsta.com/discord
@@PrepInsta sir my round also completed on 4 aug
@@PrepInsta waiting for result
@@nandinivasamsetti904 what was your result
counts = [0] * length what does it mean can anyone know
here it means the list of certain length is created with all the values to be 0, like in this question
counts=[0]*10 =======> counts=[0,0,0,0,0,0,0,0,0,0]
Just a method to create empty list of a fixed length
I watched the part 1 and now the part 2 . I'm now confident that I can crack the exam
Hey,
You are Awesome , Best Wishes for your Exam!! 💚
We have dedicated material for Accenture, Dm us on Instagram to know more 💟
can i get the answer in c++ language
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bro will get correct ans in chatgpt???
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put it in java sir
Hi, Sure. You can connect with us on discord and we will help you with it prepinsta.com/discord