Top 30 Pseudo Code Questions to Crack Accenture
ฝัง
- เผยแพร่เมื่อ 14 ต.ค. 2024
- Preparing for an Accenture interview? This video covers the top 20 pseudo code questions you need to know to crack the Accenture interview process. Master these questions to boost your chances of success.
What You'll Learn:
Overview of key pseudo code questions for Accenture interviews
Detailed explanations and solutions
Tips for understanding and writing pseudo code
Strategies to handle common and complex scenarios
Key Topics Covered:
1. Essential Pseudo Code Questions:
Frequently asked pseudo code questions in Accenture interviews
Step-by-step solutions and explanations
Practical examples and scenarios
2. Effective Preparation Tips:
How to study and practice pseudo code questions
Resources for additional practice
Time management strategies during the interview
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Ans for -> 8:30
4>2(true)
6>2(true)
return 4+6+fun(5, 1);
fun(5,1)
5>2(true)
1>2(false)
so this fun return a -b which is (5-1) = 4 and this 4 is return back to his prev fun call and it become
4+6+4 = 14(ans)
(5>2 but 1>2) so 5-1=4 and 4+4+6=14 will be the answer
Thank you a lot Yash From Tamil Nadu . Early waiting for aptitude video like this
@@iamdhanush03 i am Aditya Mishra 😂.
sir these are easy questions accenture increased the difficulty level of psedocodes kindly provide us with them
check the mock test and cheatsheet video today
did u get anything for pseudo code
10:57 p=p-2p=p here p-2p gets assigned to p ,say if equation was p=p-2p=q will both p and q have value p-2p?How this thing works?
p = p - 2q ignore 'q'
@@PrimeCoding19 okk.Thanks
@@PrimeCoding19normally if I write a=b=c then both a and b will have value of c ,if I write p=p-2q=q will p be equal to q or p-2q??
@@PrimeCoding19 I think you are wrong because precedence of * is high then - then = (assignment) so the calculation take place in between then value of q is assigned into that calculation and after it will assign to p because associativity of assignment operator will from right to left . but this code give error .
@@aadn_abhishek6799 ignore means - typo error
14 is the answer for the homework question
ans for 13.00 p=p&r=>0&3=0=>p+q+r=0+4+3=7 is the answer.
8:24 ans is 14
sunday suspense lover
Can you please share a pdf like mock test.. Then we will try to complete it within 90 minutes.. So it will really helpful for us. Please
hello can i get the pdf of this session, BTW thanks for the video
Sir you are not well then also you are uploading vedio thanks❤
Keep learning!
@@PrimeCoding19 please make video for the mastek company and DeltaX please please
7:03 ==> if I want to find sum of 3 its returning 7. but sum of 3 is 6 . I think resurion stop case Have to return 0 ; but its returning 1 . like this ===>
N=3; sum = 3+2+1+1 = 7
++x prefix increament, it should be y=5 option a
No if it is x++ post increment only it need to be 5 but here they used the pre increment therefore it is 6.
9:02 systax error hai ussme,kindly check that sir
yes bro
for i=0 to 4 it should run 4 times am i right
no include '0' iteration
Thank you ... nice explanation... please give more pseudo code Accenture vidios
Mock test series has already started. Watch recent videos
16:03 in that question i think the if statement might be if(n
No, that's correct. When it reaches 0 the state will return to 1.
@@PrimeCoding19 Ooo got it..
Please provide pdf of this session
28/30
8:36 14 ans.
Answer -14
Thanks sir
8:50 the answer is 14
Bhai last Mai kuch jyada hi easy nahi Karwa diyai assai satai bhi hai?
Concepts ha waha same chez scenario me puchunge
@@PrimeCoding19 got it!
brooooooooooooo you literally sound like striver aka raj vikramaditya
yes , i do think so
12:27 & operator nahi na logical and hai na
if me
Logical operator hota agar "and" or "&&" likha hota.
good
8:44 ans 14
14
27/30
Y u say bingo??!
when something happens successfully
25/30
Bhai infosys ka test h kal video daal do aage ki
14 👍🏻
0^3=0 not 3
0 0 0 ^ 0 1 1 = 0 1 1. Hope u understand
@@ronysedits2866 thanks
8:50 14
Baki sab to thik hai Writing badi gandi hai smjh nhi aata kabhi kabhi
@@Ricky02 Thanks for the feedback I will definitely work on it.
14
8:44 14
14
14
14
14
14
14
14
14
14
14
14
14
14
8:56 14
Can u explain