@@RottingFarmsTV Do you know why we used P and not Q for the bicondition? Because if we did then there could be a possibility where Q is true and P is false
You meet a group of six natives, U, V, W, X, Y, and Z, who speak to you as follows: U says: None of us is a knight. V says: At least three of us are knights. W says: At most three of us are knights. X says: Exactly five of us are knights. Y says: Exactly two of us are knights. Z says: Exactly one of us is a knight. Which are knights and which are knaves? can this be solved using this method?
ahhhh thank youuuu. I couldnt wrap my mind around these problems and with this method you dont even need to understand what theyre saying.
Thanks sir this is first one which i was easily able to understand in english
Thank you man. You are better than my professor
Can Someone explain to me why you use the biconditional and compare P to what A says
A bi condition is true if both sides imply each other. It tells us if the statement is logically true when being said by the person
@@RottingFarmsTV Do you know why we used P and not Q for the bicondition? Because if we did then there could be a possibility where Q is true and P is false
@@zeinnaser9150 in that possibility the bicondition is false.
Why do you assume the bicconditional with P? If you try with Q, you will find another true. Which is the correct one?
Thank you very much. Really help my Discrete Mathematics homework.
Thank you!
Why do you have the and at the end why is it not an or
thanks bro you saved my grade
Can you tell me how to make this truth table if there are 3 people - knaves, Knights and spies?
You have 3 variables, so you need 2^3=8 rows in a table. Then you fill out the table, depending on the statements.
@@OrionConstellationHome what about with 6? :)
@@faterosario7872 2^6 = 64 rows in a table
Thank you so much!
Thanks. Very clear explanation.
This helped so much!!!
Thank you!!!!
Thanks :)
You meet a group of six natives, U, V,
W, X, Y, and Z, who speak to you as follows:
U says: None of us is a knight.
V says: At least three of us are knights.
W says: At most three of us are knights.
X says: Exactly five of us are knights.
Y says: Exactly two of us are knights.
Z says: Exactly one of us is a knight.
Which are knights and which are knaves?
can this be solved using this method?
bruh