127N. (Pt. 1) Differential Amplifiers: MOS, BJT, and ATD

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  • เผยแพร่เมื่อ 19 ก.ย. 2024
  • Analog Circuit Design (New 2019)
    Professor Ali Hajimiri
    California Institute of Technology (Caltech)
    chic.caltech.ed...
    © Copyright, Ali Hajimiri

ความคิดเห็น • 9

  • @ferrabras
    @ferrabras ปีที่แล้ว

    These classes are much better than ones I had at my university time.

  • @corydiehl764
    @corydiehl764 4 ปีที่แล้ว +5

    I really like how you use the ATD as an example. I've been playing with some JFETs and GaAs FETs lately, and it's really helped for understanding how to design these basic circuits using these types of transistors.

    • @strongman325
      @strongman325 4 ปีที่แล้ว

      What does ATD mean?

    • @corydiehl764
      @corydiehl764 4 ปีที่แล้ว +1

      @@strongman325 ATD =Arbitrary Three Terminal Device
      If I remember correctly or Arbitrary Transistor Device

  • @bios546
    @bios546 4 ปีที่แล้ว +3

    These lectures... are so friggin good!

  • @NAGAGANESHAKURI
    @NAGAGANESHAKURI ปีที่แล้ว

    Hi Sir, Good Morning ,Please explain me how does Re increases dynamic range in BJT differential amplifier

    • @nurahmedomar
      @nurahmedomar 4 หลายเดือนก่อน

      You can watch his video about Emitter/Source Degeneration. By placing Re, the slope gets smaller, the range increases at the cost of smaller gain.

  • @LocNguyen-ep4hv
    @LocNguyen-ep4hv ปีที่แล้ว

    sir, in differential pair of mosfet, if the current source can be seen as a M3( mosfet ) that mean the current source ISS is equivalent to M3 ( mosfet). How to calculate the Vgs of M3 if the current source ISS =0.5mA and (W/L)3 is chosen arbitrarily by the designer . Can you give me some ideas sir?, thanks you !

    • @nurahmedomar
      @nurahmedomar 4 หลายเดือนก่อน

      You can calculate the Vgs of M3 by Vgs = sqrt(0.5mA/k'). where k'=1/2*(un*Cox*(W/L)3).