Thanks. I love being able to actually show this to students. I look forward to sharing it with my non-APPhysicsC students as well. I _always_ get asked about the direction of centripetal acceleration and now I have a video which shows exactly how it is derived. Quite happy about it. 😀
god knows how much we are a part of or even at different continents but I still find that your explications are rather better than my college professors, Thank you so much also I really appreciate the other characters' questions it is really keeping me on track and asking the same question as what we might've asked. 😄
at 4:43, you say "radius of the chip" instead of "position." I think it should be "position," but the diagram makes it clear what you mean so it isn't too important to me.
Also I really appreciate the distinction between vectors and scalars here (and also the quick mention of why we still call it "v" even though it's now just speed).
Since I can't imagine how long it takes to produce one of these videos, I would ask you to tell me. It must be some sort of labor of love. Just your three alter egos alone must add hours to the process. I would never have the patience myself. I might be too ADHD.
Thanks for the love, my friend. And, rather than tell you how long it takes to make one of these videos, let me show you: www.flippingphysics.com/making-a-video.html
That’s because the v initial and v final are both tangent to the circle and the triangle formed is isosceles. If the angle subtended at the centre is theta then the remaining ones are (pi-theta)/2 now because the tangent line is at pi/2 or 90 degrees to the radius you subtract pi-theta)/2 from pi/2 to get the angle we want which is theta!
This channel offers best explanations on youtube. Thanks so much , Love respect from India
You are very welcome.
This is the most missing part in my classic physics. Thank you!
Wonderful. Loved how you took it from AP1 up to APC by finding the value for the magnitude.
Thanks. I love being able to actually show this to students. I look forward to sharing it with my non-APPhysicsC students as well. I _always_ get asked about the direction of centripetal acceleration and now I have a video which shows exactly how it is derived. Quite happy about it. 😀
Thanks mr. P. You're fantastic teacher.
god knows how much we are a part of or even at different continents but I still find that your explications are rather better than my college professors, Thank you so much also I really appreciate the other characters' questions it is really keeping me on track and asking the same question as what we might've asked. 😄
That is wonderful that I can help you learn physics from a different continent!
Sir you are the best
at 4:43, you say "radius of the chip" instead of "position." I think it should be "position," but the diagram makes it clear what you mean so it isn't too important to me.
Oh and you definitely say "position" shortly after, so now I really don't care.
I had noticed that as well in post, however, it also felt it was clear enough as is.
Great video! I expect that the animations in the diagrams are going to be really helpful for students.
Also I really appreciate the distinction between vectors and scalars here (and also the quick mention of why we still call it "v" even though it's now just speed).
Thanks. Your insistence has helped me to be more careful and clear like that!
Since I can't imagine how long it takes to produce one of these videos, I would ask you to tell me. It must be some sort of labor of love. Just your three alter egos alone must add hours to the process. I would never have the patience myself. I might be too ADHD.
Thanks for the love, my friend. And, rather than tell you how long it takes to make one of these videos, let me show you: www.flippingphysics.com/making-a-video.html
@@FlippingPhysics Thanks for the link. Two hours per minute. YIKES! And that's with you knowing what you are doing.
but why theta is same. is there any theorem for that, please explain this. everyone explains the derivation but no one explains this theorem.
That’s because the v initial and v final are both tangent to the circle and the triangle formed is isosceles. If the angle subtended at the centre is theta then the remaining ones are (pi-theta)/2 now because the tangent line is at pi/2 or 90 degrees to the radius you subtract pi-theta)/2 from pi/2 to get the angle we want which is theta!
Amazing
Those group of students ruined the explanation
You know it's all him, right?