S = ut + 1/2at² S = 10m/s • 10s + 1/2 • 1/2m/s² • (10s)² » S = 100m + 25m = 125m ans Or v² - u² = 2as = (15m/s)² - (10m/s)² = 2•1/2 m/s² • S = (225-100)m²/s² = S • m/s² = 125m = S ans
Sir my name is MD FIRAS KHAN u= 10 m/s t=10 s V= 15 m/s By using second equation of motion that is:- S=UT +1/2× AT^2 S= 0 + 1/2 × 0.5×100 S= 125 m Therefore distance covered is 125 m.
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v=15m/s
u=10m/s
a=0.5ms^-2
v^2=u^2+2as
15^2=10^2+2x0.5xs
225=100+1s
225-100=s
125=s
s=125 metres
The answer is 125m
Sir answer= 125m🤗
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S = ut + 1/2at²
S = 10m/s • 10s + 1/2 • 1/2m/s² • (10s)²
» S = 100m + 25m
= 125m ans
Or
v² - u² = 2as
= (15m/s)² - (10m/s)² = 2•1/2 m/s² • S
= (225-100)m²/s² = S • m/s²
= 125m = S ans
Sir my name is MD FIRAS KHAN
u= 10 m/s
t=10 s
V= 15 m/s
By using second equation of motion that is:-
S=UT +1/2× AT^2
S= 0 + 1/2 × 0.5×100
S= 125 m
Therefore distance covered is 125 m.
Sir right answer is 125m ❤
Sir the answer is
S=125
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Since 2aS = v² - u²
=> 2 × 0.5 × S = 15² - 10² m
=> 1S = 225 - 100 m
=> S = 125 m (Ans)
Good morning sir
s =ut+½at²
s=10×10+½×0.5×10²
s=100 +½+0.5×100
s=100+½+50
s= 100+25
s=125. Ans
2as=v²-u²
2×0.5×s=15²-10²
1×s=225-100
s=125. Ans
Sir answer is 125m 👍
Ans:- fusing second equation of motion
=2as=v^2-u^2
=2×0.5×s=15^2-10^2
= s=225-100
S=125m ans
Tqq sir ji 😊first comment
125m🎉
125m Distance
125 is the answer ❤
S = 125m correct answer ha sir
Sir the correct answer is 125m
125m answer
Answer is S=125m
Distance = 125 m
Sir ans = 125m
Sir answer is 125 metre
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Ans. v²= u² + 2as
15²= 10² + 2×5/10×S
225= 100 + 1 × S
225-100 = S
125m = S Answer
S=125 Metre
S=125m.
answer S = 125
S =125
The answer is 125
Sir answer is 125 m
Distance=125
DISTANCE = 125 METRES
Sir aaj hw question nhi hai kya?
Video ke last mei mene apko bola hai ki iss question mei displacement by the body find kijiye... Vansh aapne last video mei jo ans dia tha uska calculation apne sahi nhi kia... Ans sahi tha lakin formula mei galat values daal di thi aapne...
Sir answer is 125m
s=125m
Sir answer is 125m