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2nd like 😊
(2y^3)^2 ➖ (y)^2= {4y^6 ➖ y^2}=4y^4 2^2y^2^2 1^1y^1^2 1y^2 (y ➖ 2y+1).
Будет цифра два это в уме просчитывается за несколько секунд
Yes it can be, but we needed to show full working 👍
You only did -8y +7y because you knew the first solution. Why didn't you just say that from the start and proceed to form the quadratic for the other two solutions.
Okay
2nd like 😊
(2y^3)^2 ➖ (y)^2= {4y^6 ➖ y^2}=4y^4 2^2y^2^2 1^1y^1^2 1y^2 (y ➖ 2y+1).
Будет цифра два это в уме просчитывается за несколько секунд
Yes it can be, but we needed to show full working 👍
You only did -8y +7y because you knew the first solution. Why didn't you just say that from the start and proceed to form the quadratic for the other two solutions.
Okay