The pumping/absorption through Photon/Light is said to be Radiative Transition So, is pumping or absorption through Electric current/ Electric field will said to be Non-Radiative Transition?
Really awesome!!!!!Cleared my all doubts..... I want to ask about ro c derivation about how 2mc rest to 3/2 came and ro v rest to 1/2 came..............PLEASE EXPLAIN IF ANYONE CAN..............
Ok... So, this term is basically came from the derivation of "DENSITY OF STATES for 3D" for the case of Semiconductor... plz go through any reputed book for semiconductor physics and search for the topic...
There is a key question(or issue) in the derivation: p(E2)dE2= p(hv)dhv. This step assumes that only the density of states in one band matters for the total transition. However, in reality, one should expect that the transition is related to both the density of states in the valence band and the conduction band (the concept of joint-density of states). For example, if one band is highly degenerated, one would expect a shift in the absorption spectra (so-called moss Burstein shift). To me, the method used in this video can not predict that change. The derivation, from the point of p(E2)dE2= p(hv)dhv, is not correct and misleading.
In the first part of the video, only the allowed transitions are considered. Under the parabolic approximation, for a given k value the density of states around E1 and E2 are equal as the bands are mirror images of each other.
Thank you for putting this crystal clear lesson available for us all.
Thanks for this, the lecture is so clear and straightforward.
I always wish I could learn from prof of iit but jee was way tough than I thought... this faculty are such a great.
Very good and clear lecture, useful to the teachers and as well as to students
The best explanation ever
Now i'm damn clear about this topic
Really helpful.........Awesome explanation...
Thank you so much sir..for the lecture ❤
Thank you for your great lecture professor
very nicely delivered
thank you so much sir for the lecture
professor is professor.....
Very good lecture sir
非常好的视频，很有启发性
The pumping/absorption through Photon/Light is said to be Radiative Transition
So, is pumping or absorption through Electric current/ Electric field will said to be Non-Radiative Transition?
Thank you
Really awesome!!!!!Cleared my all doubts.....
I want to ask about ro c derivation about how 2mc rest to 3/2 came and ro v rest to 1/2 came..............PLEASE EXPLAIN IF ANYONE CAN..............
Ok... So, this term is basically came from the derivation of "DENSITY OF STATES for 3D" for the case of Semiconductor... plz go through any reputed book for semiconductor physics and search for the topic...
There is a key question(or issue) in the derivation: p(E2)dE2= p(hv)dhv. This step assumes that only the density of states in one band matters for the total transition. However, in reality, one should expect that the transition is related to both the density of states in the valence band and the conduction band (the concept of joint-density of states). For example, if one band is highly degenerated, one would expect a shift in the absorption spectra (so-called moss Burstein shift). To me, the method used in this video can not predict that change. The derivation, from the point of p(E2)dE2= p(hv)dhv, is not correct and misleading.
In the first part of the video, only the allowed transitions are considered. Under the parabolic approximation, for a given k value the density of states around E1 and E2 are equal as the bands are mirror images of each other.
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HAHA @2X speed @23:50
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