Physics Ninja calculated the total force on a current loop placed in the magnetic field produced by a long wire. The force on each segment is considered.
Dude! Excellent presentation of content, except your audio is sub par. Gotta have better sound. Get that mic up in your sheeit! Also, overlapping two different diagrams can be confusing. The red and blue are two separate diagrams, so when you draw red circles and say the magnetic field gets weaker the further you get away from the wire, the circles are drawn on the first blue line, making it look like they are the same distance from the wire. It took a couple seconds to realize you're ignoring the blue diagram.
When you are calculating the magnetic field on segment 1 you didn't consider the magnetic field due to current I2 on other segment (2,3&4) . Similar situation for other segment also.Is that negligible?
I have a question ? If we solve dlxB vectoral product we get opposite direction and same magnitude force for F2 and F4. And B opposite sign due to direction. So F2+F4 is not equal zero and F2+F4 same direction and same magnitude like F2+F4=2F2 ? Please answer my question.
Right hand rule: wrap your fingers around a pencil, and point your thumb in the direction of the current. The way your hand curves around the pencil is the same way the magnetic field curls around the current
Thanks for your comment - I just checked the answer and i seem to have punched in the wrong numbers into my calculator. I'm horrible with numbers! The algebra works but my final answer is incorrect...by a factor of 2! If you do it correctly you should get 2*10^(-8). Sorry about that. Here's a link www.desmos.com/calculator/zn52svzmt2
I think i just wasted your time,I was asking about the "mu naught" it was the Vacuum Permeability constant. got it now. (BTW your complex and RC circuit video was fantastic I understand 100% of it, Thank you so much.)
Hi Jani, i'm not sure i understand the question. The total force (or Net Force) is acting on the loop. There is an equal but opposite force acting on the long wire thanks to Newton's third law.
Hi if i'm looking at the force on a current carrying wire F=i (L X B) . I always place my fingers (right hand) along the first vector - direction of the positive current and curl my fingers toward the second vector - the magnetic field B. My thumb indicates the direction of the magnetic force on the wire. Keep in mind that the field in this case is the field produced by the other wire. Also for any cross product like magnetic force - the force is always perpendicular to the current and also perpendicular to the magnetic field! Happy learning, Dr. E.
simple and straight forward explanation. Please keep it up. Thank you
answer should've been 2*10^-8 N
Great video! Helped me understand the material a lot better.
Very helpful and good explanation.
Good explanation indeed.
amazing explanation
Thank you bro, but can you show me how to do the calculus?
Excellent
I found this extremely helpful thank you? But why would the magnetic field be pointing out of the page?
th-cam.com/video/-EnRggYVGlk/w-d-xo.html
youre an electricity and magnetism GOD
Thankyou!
Dude! Excellent presentation of content, except your audio is sub par. Gotta have better sound. Get that mic up in your sheeit!
Also, overlapping two different diagrams can be confusing. The red and blue are two separate diagrams, so when you draw red circles and say the magnetic field gets weaker the further you get away from the wire, the circles are drawn on the first blue line, making it look like they are the same distance from the wire. It took a couple seconds to realize you're ignoring the blue diagram.
Osm EXPLAINATION!!!
When you are calculating the magnetic field on segment 1 you didn't consider the magnetic field due to current I2 on other segment (2,3&4) . Similar situation for other segment also.Is that negligible?
Good question. I’m considering the force between both objects, treating the loop as one object and the wire as another object.
very clear explanation! tnx
How did you figure that the magnetic field above the wire points out of the page?
Right hand rule
im grateful
what do you do if you arent given either of the currents
I have a question ? If we solve dlxB vectoral product we get opposite direction and same magnitude force for F2 and F4. And B opposite sign due to direction. So F2+F4 is not equal zero and F2+F4 same direction and same magnitude like F2+F4=2F2 ? Please answer my question.
B is the field produced by the long wire and therefore in the same direction.
U r the best 😉😉😉😉😉
Sir i have a question.....if two metal wires carrying the same current then where B is zero plz explain in detail with reasoning
Hey! How did u find out that the magnetic field was coming out of the page?
Right hand rule: wrap your fingers around a pencil, and point your thumb in the direction of the current. The way your hand curves around the pencil is the same way the magnetic field curls around the current
Thanx it helped a lot
How can i calculate F4 ??
So this is an arbitrary magnetic field? You can't really figure out the magnetic field if you only have 1 variable.
How do I find the mutual inductance?
You need to find the flux of the magnetic field produced by the wire through the loop. I’ll put something together soon on this.
@@PhysicsNinja ok please, it'll be of great help.
Also post the link below. Thanks.
How do you get u_0 to be 4pi*10^-7 which is 1.25*10^-6. Did u_0 = I*A right? So 0.04*0.06 * 5*10^-3= 1.2*10^-5
Thanks for your comment - I just checked the answer and i seem to have punched in the wrong numbers into my calculator. I'm horrible with numbers! The algebra works but my final answer is incorrect...by a factor of 2! If you do it correctly you should get 2*10^(-8). Sorry about that. Here's a link www.desmos.com/calculator/zn52svzmt2
I think i just wasted your time,I was asking about the "mu naught" it was the Vacuum Permeability constant. got it now. (BTW your complex and RC circuit video was fantastic I understand 100% of it, Thank you so much.)
is total force is magnitude of the loop???
Hi Jani, i'm not sure i understand the question. The total force (or Net Force) is acting on the loop. There is an equal but opposite force acting on the long wire thanks to Newton's third law.
hey bro I just watched this video to sew the magnitude of F2 and you just skipped that😥
How exactly do you use the right hand rule to find the direction? Not sure how to orient fingers and whatnot lol
Hi if i'm looking at the force on a current carrying wire F=i (L X B) . I always place my fingers (right hand) along the first vector - direction of the positive current and curl my fingers toward the second vector - the magnetic field B. My thumb indicates the direction of the magnetic force on the wire. Keep in mind that the field in this case is the field produced by the other wire. Also for any cross product like magnetic force - the force is always perpendicular to the current and also perpendicular to the magnetic field! Happy learning, Dr. E.
what a G
why would u use a r there i got confused and had to rewrite all my calculations :(
This video should be avoided by Indian student because hand rule convention here is different...you will get confused