Excelent! Frumos, elegant, logic explicat și animat. Acestea sunt explicații necesare și suficiente pentru un student care studiază mecanisme și organe de mașini pentru a înțelege și calcula raportul de transmitere în cazul mecanismului planetar cu roți dințate. Caut de mult timp pe net așa ceva și acum am găsit. Am reținut raționamentul logic de calcul. Sănătate și succes în continuare.
There are three main configurations of planetary gear systems: 1:planetary, 2: solar, 3:star. 1: Planetary type (internal gear fixed, sun gear as drive shaft, planetary carrier as output shaft): Gear ratio = number of teeth of sun gear / number of teeth of internal gear Example: For 12 teeth sun gear and 60 teeth internal gear, gear ratio = 12 / 60 = 1/5 2: Solar type (sun gear fixed, internal gear as drive shaft, planetary carrier as output shaft): Gear ratio = number of teeth on internal gear / number of teeth on sun gear Example: For 12 teeth sun gear and 60 teeth internal gear, gear ratio = 60 / 12 = 5 3: Star type (planetary carrier fixed, sun gear as drive shaft, internal gear as output shaft): Gear ratio = (number of teeth on internal gear / number of teeth on sun gear) + 1 Example: For 12 teeth sun gear and 60 teeth internal gear, gear ratio = 60 / 12 + 1 = 6 Therefore the gear ratio is 1:6 in the case of a *star type (fixed planetary carrier, sun gear drive wheel, internal gear output shaft).
Beautifully Emplaned!! These 2 concluded formulas to determine the ratio, apply well when the input is the sun and the output is the carrier as mentioned in the video. What about a scenario in which the input is the sun with the carrier arrested and the output is the ring? How can that ratio be determined?
Thanks for a clear explanatin. Can any body explain, if the sun gear has 30 teeth, panatary has 15 teath, and ring has 90 teath what will be the RPM of the carrier if the sun gear is rotated at 1000 RPM, under the following conditions. Sun gear is the driver and carrier shaft is the driven connected to a load. 1. The ring gear is held stationary. 2. The ring gear is free to rotate, and the carrier shaft is loaded.
Perfect instructions!!! I got full understand for my planetary gear system. And I have one question for compounnd planetary gear such that one tooth of planetary gear meshes with sun gear and other tooth meshes with ring gear. From googling, I understand both tabular method and algebraic method can be used. But I couldn't solve gear ratio formula for compound planetary gear using your method ... Vc and zero velocity at the ring contact point and instantaneous velocity at the sun contact point and so on. Please could you give me some directions?
I want to ask For example Sun 12 teeth Planet 24 teeth Ring 60 teeth If the sun gear turns 360° 12 teeth, the planet gear will turn 12 teeth 180° If the planet gear turns 12 teeth 180°, the ring gear will turn 12 teeth 72° But if we calculate this by using this formula we get 360÷((60/12)+1)=60° How it can be? (The formula is true, i dont say it is wrong) but What is my mistake?
I was falling into the mistake of thinking it was as simple as the ratio of the sun gear tooth No. and the ring gear tooth No. I can now see why I was always wrong until now! Great educational tutorial!!! By the way I have also heard the ring gear referred to as an Annulus, has anyone else heard of this or used this term! Just curious. John, Australia. en.wikipedia.org/wiki/Annulus_(mathematics)
Me.encanto. Entiendo el inglés y la explicación. Desde ya agradezco , es muy útil, interesante . Pero sería conveniente que estuviera los subtítulos, por lo menos en castellano. Muchos que se beneficiarían de esta información, y no tienen PC, deben verlo por el celular. Yo, de mi parte estoy agradecido por estos tips. Atte. Alberto.
can you derive a simple relationship for the gear ratio expressed as a function of number of teeth in the sun and ring gears of an epicyclic (or planetary) gear train.
ring /planet = number , the sun / by that number = radius for example Ring100, Planet 10, Sun 100. So 100/ 10 = 10 , and 100 / 10 = 10 meaning ring moves once and the sun moves 10 times 1:10
Just count the teeth --> carrier as input = ring teeth/planet teeth. Carrier as output = planet teeth/sun teeth. Carrier stationary = sun teeth/ring teeth (planetry teeth value = ring teeth + sun teeth. no need to actually count teeth on planet)
Help is possible..I need a care box like the one used in wind turbines..convert from slow speed to high speed ... it is connected with a head of electricity generation.It produces 1000 watts .... thank you very much ... possible model
You pick the number of teeth of all three types of gears arbitrarily based on the desired gear ratio or pure aesthetics. However they are subject to restrictions, the main one being R = 2 * P + S. Also, the number of teeth in the sun and ring gears must be divisible by the number of planet gears. Typically, there are 3 planet gears, but sometimes there are 2, 4 or more. The 60/24/12 combination used in our example will work with 2, 3, or 4 planet gears. However, a 60/20/20 combination will work with 2 or 4 planet gears but won't work with 3, as 20 is not divisible by 3.
![ลองสุ่มไอโฟน 990 โกงมั้ย? [ โกงมั้ยครับ ep.101 ] | DOM](http://i.ytimg.com/vi/bfsWe0j492k/mqdefault.jpg)
Excelent! Frumos, elegant, logic explicat și animat. Acestea sunt explicații necesare și suficiente pentru un student care studiază mecanisme și organe de mașini pentru a înțelege și calcula raportul de transmitere în cazul mecanismului planetar cu roți dințate. Caut de mult timp pe net așa ceva și acum am găsit. Am reținut raționamentul logic de calcul. Sănătate și succes în continuare.
Awesome video, thank you so much!
There aren't many channels out there who post good and clear tutorials about the mathematics behind mechanisms.
Thank you very much! This is the clearest explanation that tells how the gear ratio is derived. It's really helpful for me to understand my textbook.
There are three main configurations of planetary gear systems: 1:planetary, 2: solar, 3:star.
1: Planetary type (internal gear fixed, sun gear as drive shaft, planetary carrier as output shaft):
Gear ratio = number of teeth of sun gear / number of teeth of internal gear
Example: For 12 teeth sun gear and 60 teeth internal gear, gear ratio = 12 / 60 = 1/5
2: Solar type (sun gear fixed, internal gear as drive shaft, planetary carrier as output shaft):
Gear ratio = number of teeth on internal gear / number of teeth on sun gear
Example: For 12 teeth sun gear and 60 teeth internal gear, gear ratio = 60 / 12 = 5
3: Star type (planetary carrier fixed, sun gear as drive shaft, internal gear as output shaft):
Gear ratio = (number of teeth on internal gear / number of teeth on sun gear) + 1
Example: For 12 teeth sun gear and 60 teeth internal gear, gear ratio = 60 / 12 + 1 = 6
Therefore the gear ratio is 1:6 in the case of a *star type (fixed planetary carrier, sun gear drive wheel, internal gear output shaft).
Beautifully Emplaned!!
These 2 concluded formulas to determine the ratio, apply well when the input is the sun and the output is the carrier as mentioned in the video.
What about a scenario in which the input is the sun with the carrier arrested and the output is the ring?
How can that ratio be determined?
The best explanation i found, thanks you!
A good explanation of a very interesting mechanism.
Learning with GLaDOS. Awesome video!
Thanks for a clear explanatin.
Can any body explain, if the sun gear has 30 teeth, panatary has 15 teath, and ring has 90 teath what will be the RPM of the carrier if the sun gear is rotated at 1000 RPM, under the following conditions.
Sun gear is the driver and carrier shaft is the driven connected to a load.
1. The ring gear is held stationary.
2. The ring gear is free to rotate, and the carrier shaft is loaded.
Best ever .TH-cam needs more videos like that.
A planetary gear calculation is ring divided by sun
So.
46 ring.9sun=5.1
A very interesting explanation, Now your calculation is only true if the ring is static!
Great explanation 👌
Perfect instructions!!! I got full understand for my planetary gear system. And I have one question for compounnd planetary gear such that one tooth of planetary gear meshes with sun gear and other tooth meshes with ring gear. From googling, I understand both tabular method and algebraic method can be used. But I couldn't solve gear ratio formula for compound planetary gear using your method ... Vc and zero velocity at the ring contact point and instantaneous velocity at the sun contact point and so on. Please could you give me some directions?
I want to ask
For example
Sun 12 teeth
Planet 24 teeth
Ring 60 teeth
If the sun gear turns 360° 12 teeth, the planet gear will turn 12 teeth 180°
If the planet gear turns 12 teeth 180°, the ring gear will turn 12 teeth 72°
But if we calculate this by using this formula we get 360÷((60/12)+1)=60°
How it can be? (The formula is true, i dont say it is wrong) but What is my mistake?
Oh ! What a fantastiiiic explanation !! Thanks so much
Ko ko ko ko ko lol Pp pop pop PP
Thanks for those
Awesome Videos
Great explanation
Great explanation - thanks a lot.
Me ha gustado mucho la explicación. Lo he comprendido bien.
Pls help to clear ratio in 5 cases such as all gears rotate, ring gear fix,sun gear fix, planetary gear fix. Tks!
nice graphics and great explanation.
Super explanation!! Thank you very much..
Great video. Thank you!
Warning: Machine voice. The bane of TH-cam.
Irrespective, the information is still good.
I was falling into the mistake of thinking it was as simple as the ratio of the sun gear tooth No. and the ring gear tooth No.
I can now see why I was always wrong until now! Great educational tutorial!!!
By the way I have also heard the ring gear referred to as an Annulus, has anyone else heard of this or used this term! Just curious.
John, Australia.
en.wikipedia.org/wiki/Annulus_(mathematics)
joandar1
I wonder if the ring gear can also be called the “orbit” gear.
That would make sense as well, as the planets are “in orbit” around the sun.
yes. It's referred to as the annular gear in the UK.
'Annulus' is Latin for 'ring': translate.google.com/#view=home&op=translate&sl=la&tl=en&text=annulus
this is brilliant
Thank you so much 💖
Me.encanto.
Entiendo el inglés y la explicación.
Desde ya agradezco , es muy útil, interesante .
Pero sería conveniente que estuviera los subtítulos, por lo menos en castellano.
Muchos que se beneficiarían de esta información, y no tienen PC, deben verlo por el celular.
Yo, de mi parte estoy agradecido por estos tips.
Atte.
Alberto.
thanx. good video
excellent videos learning a lot
Just watched because it was lovely to watch, though I did not understand one bit of it.
You’re hired
Hello..Are there small sizes, the Care Box is used in wind turbines .. Can it give the same work? Thank you very much ..
Can we have a tutorial on how to understand this tutorial
the ratio = 1+R/S can this formula be used in any circumstance, no matter which one gear out of three is stationary?
No, it is only applicable to this specific scenario.
I had the same question. Thank you all for clarifying. Great tutorial! Exactly what I was looking for!
HOW MUCH TORQUE WILL BE INCREASE ? IN GENERAL
can you derive a simple relationship for the gear ratio expressed as a function of
number of teeth in the sun and ring gears of an epicyclic (or planetary) gear
train.
ring /planet = number , the sun / by that number = radius for example Ring100, Planet 10, Sun 100. So 100/ 10 = 10 , and 100 / 10 = 10 meaning ring moves once and the sun moves 10 times 1:10
Just count the teeth --> carrier as input = ring teeth/planet teeth. Carrier as output = planet teeth/sun teeth. Carrier stationary = sun teeth/ring teeth (planetry teeth value = ring teeth + sun teeth. no need to actually count teeth on planet)
Andrew Semple why do you add the ring and sun teeth?
Help is possible..I need a care box like the one used in wind turbines..convert from slow speed to high speed ... it is connected with a head of electricity generation.It produces 1000 watts .... thank you very much ... possible model
I want to ask? How about that, if internal helix planetary gear with 3 of planet?
How do I determine the amount of teeth of the planet gears?
You pick the number of teeth of all three types of gears arbitrarily based on the desired gear ratio or pure aesthetics. However they are subject to restrictions, the main one being R = 2 * P + S. Also, the number of teeth in the sun and ring gears must be divisible by the number of planet gears. Typically, there are 3 planet gears, but sometimes there are 2, 4 or more. The 60/24/12 combination used in our example will work with 2, 3, or 4 planet gears. However, a 60/20/20 combination will work with 2 or 4 planet gears but won't work with 3, as 20 is not divisible by 3.
does the diameter refer to pitch diameter
Any references for the same? For further reading. Please do suggest.
Theory of Machines by Khurmi
Nice explain
Remarkable
Or you can add the teeth of the ring gear and the sun gear and divide by the teeth of the sun gear. 60+12/12=6. Hmmm
derrick dry how does this work?
@@shaq__2400 Simple math substitution. Change the 1 to zs/zs...
Or you can
12+60=72
72-48=24
24+12=36
36/6=6 that's it! Easy pesy
@@shaq__2400 it is basically different form of the formula used in video above
Fine
Exelente
muito bom.
I’m 14 and you just confused the life out of ne
desafortunadamente la traducción al español es desastrosa confusa ininteligible
No te preocupes, es igual en Ingles, no es mucho mas mejor... buscas otra video
Super
OSM
sugoi ne.
v 2v Vc Vs thank you!
I give a thumb down each time I hear a TTS.
Speak to me o chocolate lips.
Ohh, no, this voice. Please change! :-)
Venus 😂
Great Explanation, many thanks