I considered the projection of the radius of measure 1 of the inner circle on the radius of the quarter circle and added the diameter 2 of the semicircle obtaining 3, then I proceeded as you did. I found your geometric demonstration of the radius of measure 3 fabulous: you have a stimulating mind!🔥🔥🔥👋🇮🇹
If the radius of the big circle is 3 units, then your figure is not drawn to scale, and is deceptive. Also, you did not challenge your viewers to solve the problem with only the available information, while also warning them that the figure is not drawn to scale. That would have been a fair challenge.
@@SpartanG007 In the video, using the property of regular hexagon.. you can create 6 equilateral triangles, thus creating a circle on the 6 vertices, you can also create one circle the middle, because 2*radius = side of the triangle.
I considered the projection of the radius of measure 1 of the inner circle on the radius of the quarter circle and added the diameter 2 of the semicircle obtaining 3, then I proceeded as you did.
I found your geometric demonstration of the radius of measure 3 fabulous:
you have a stimulating mind!🔥🔥🔥👋🇮🇹
@@godhell8039 thank you so much 👌❤️
Thank you very much for stimulating my mind with your problem: it makes for a good start to the day.😄
@@fj8848 😁😁😁
I did know the radius of the big circle was 3, but it was a guess. Thank you for teaching me how to prove my answer was correct
@@Bartolito201 Thank you so much ❤️
If the radius of the big circle is 3 units, then your figure is not drawn to scale, and is deceptive. Also, you did not challenge your viewers to solve the problem with only the available information, while also warning them that the figure is not drawn to scale.
That would have been a fair challenge.
Noted Sir..👌👌
Thank you so much 🙏
Where was it proven that the inner circle's lines' length is also 1?
@@SpartanG007 In the video, using the property of regular hexagon.. you can create 6 equilateral triangles, thus creating a circle on the 6 vertices, you can also create one circle the middle, because 2*radius = side of the triangle.
@@ZahlenRMD I realized that I confused the meaning of "equilateral" with the one of "isosceles", and now it makes sense. Thx
@@SpartanG007 great 👌👌👌