Thank you for the video! Very helpful! For the maximum queue length there is another way to think about it. The wave front may move forward, backward, or remain stationary (relative to the roadway). In this case, the wave front is moving forward (relative to roadway) but relative to the truck the wave front is moving backwards (11.23 -20 = -8.77). You would expect for the queue length to be 11.23*0.04, but that is true for a red light (stationary) in this case you need to use the relative speed which would "make the truck stationary" and then the queue length is 8.77*0.4 = 0.35, which results in the same answer. Hope this is helpful!!
Thank you sir for the clear explanation. I have a question please, in 8:16-8:30 you said that point 1 is before entry of the truck, point 2 is after entry of the truck and point 3 after exit of the truck. My question is why when the truck left the flow is shifted to point 3 and not point 1 before the entering of the truck ? thank you
I have covered many topics of Traffic Flow Theory in different videos. Just have a look at the playlist in Traffic Engineering and tell me further topics you want. Thanks
Nice video. I have a question. How do you calculate the speed of a shock wave given the following: Demand volume, average speed, capacity of the closure lane with traffic distributed evenly on two lanes?
I would suggest you to watch Part 2 of this video and it will answer your question. It will be too long to answer it here. If your doubt is not cleared in Part 2 also then come back.
@SatishIITR I have done that but still not clear with how the parameters in the formula for shock wave could be obtained. Can you just explain more briefly how I could get Q1,Ki,Q2,and K2?
@@AromeOzigagu These are obtained from field studies only. Say for example you are studying the shock wave movement past an accident on a road. You should know the flow parameters on the road before accident ( I mean the point (1) on flow-density curve. after accident, the lane is closed so it is all stopped behind the accident point, density becomes jam density and that is point 2 on the curve. once the site is cleared the traffic starts moving at low headway and flow will be corresponding to capacity. This is point 3 on the curve. I hope I made it clear. All points coming from field data.
@@SatishIITR Sir what is the relation between queue length and truck leaving at 800 m. Queue length should be 11.23*0.04 only, right? I am not able to understand which distance we are considering after subtracting from 800 m ?
@@parthpandey4186 No, queue length will be infinite if the truck stays on the road for indefinte time and therefore queue length will depend on the time spent by the rruck on the road. the first vehicle is the queue has also moved 800 m during this time. Therefore formation of the queue will be slower (compare it with a traffic sgnal where the first vehicle is stopped).
The second value of k is 114 veh/km, which is unrealistic. Please see the equation is not correctly printed (very sorry). It is Q = k(100 - 0.8K) or 1000 = 100k - 0.8 (k squared).
These are two different term. Queuing is the process of joining the queue by a vehicle. Shock wave is the speed at which a queue buils up or dissipates.
It is simple Aman. In a normal case, the queue length is red time multiplied by the rate of arrival. Here it is equal to red time multiplied by the velocity of the shockwave.
@@SatishIITR sir why you have subtracted the total length shockwave travelled in 0.04 hour with 800m?This concludes that max distance the shockwave will travell will be equal to the distance traveled by the truck? It's confusing please explain!!
Thank you for the video! Very helpful! For the maximum queue length there is another way to think about it. The wave front may move forward, backward, or remain stationary (relative to the roadway). In this case, the wave front is moving forward (relative to roadway) but relative to the truck the wave front is moving backwards (11.23 -20 = -8.77). You would expect for the queue length to be 11.23*0.04, but that is true for a red light (stationary) in this case you need to use the relative speed which would "make the truck stationary" and then the queue length is 8.77*0.4 = 0.35, which results in the same answer. Hope this is helpful!!
Thank you.
Hi, could you kindly explain that the 'way front' here, does it mean the wave behind the truck after the truck enters?
A simple and practical discussion beyond mathematical complicated explanations! Sir, lucid and to the point! 👍
Thanks Smruti for liking it. Please circulate the link in your students' groups also.
@@SatishIITR Sure sir!
Thank you sir! This is a very good lecture to understand the basics of shockwaves!
Thanks. Please share the link with your friends also.
Thanks sir for such videos
The way of teaching is excellent
Thanks, Please share the link with others also
Excellent
Thankyou
amazing explanation
Glad you liked it. There are two more parts of shockwave analysis. Watch them also for complete understanding.
Thanks greatly. It does help
Glad it helped!
great sir
Thanks, watch Part 2 and 3 also
Thank you very much.
Keep watching.
Thank you sir for the clear explanation. I have a question please, in 8:16-8:30 you said that point 1 is before entry of the truck, point 2 is after entry of the truck and point 3 after exit of the truck. My question is why when the truck left the flow is shifted to point 3 and not point 1 before the entering of the truck ? thank you
Point 3 is same as point 1 with respect to flow conditions, You see the trajectory lines shown in Stage 3 are parallel to those in Stage 1.
@@SatishIITR thank you for the clarification.
Thank you so much sir
Keep watching, there are two more parts of shock waves.
Create a course on traffic flow theory much needed
I have covered many topics of Traffic Flow Theory in different videos. Just have a look at the playlist in Traffic Engineering and tell me further topics you want. Thanks
EXCELLENT PRESENTATION SIR, PLEASE MAKE A VIDEO RELATED TO THE CAR FOLLOWING THEORIES
Thanks for the appreciation, will make video on car following theories also. Please circulate the link in your groups to increase the viewership.
@@SatishIITR k sir
nice
Watch Part 2 and 3 also.
Thank a lot
Most welcome. Watch Part 2 and 3 also.
Please tell your friends also
Nice video. I have a question. How do you calculate the speed of a shock wave given the following: Demand volume, average speed, capacity of the closure lane with traffic distributed evenly on two lanes?
I would suggest you to watch Part 2 of this video and it will answer your question. It will be too long to answer it here. If your doubt is not cleared in Part 2 also then come back.
@SatishIITR I have done that but still not clear with how the parameters in the formula for shock wave could be obtained.
Can you just explain more briefly how I could get Q1,Ki,Q2,and K2?
@SatishIITR I am a international graduate student and would appreciate if I could get more clarity on this particular question. Thanks.
@@AromeOzigagu These are obtained from field studies only. Say for example you are studying the shock wave movement past an accident on a road. You should know the flow parameters on the road before accident ( I mean the point (1) on flow-density curve. after accident, the lane is closed so it is all stopped behind the accident point, density becomes jam density and that is point 2 on the curve. once the site is cleared the traffic starts moving at low headway and flow will be corresponding to capacity. This is point 3 on the curve. I hope I made it clear. All points coming from field data.
Sir, why queue length is 0.8 -11.23*0.04.
It should be 11.23*0.04, why we are subtracting from 0.8m
It is given in the question that the slow truck exits after 800 m (0.8 km)
Hi bro
@@SatishIITR Sir what is the relation between queue length and truck leaving at 800 m. Queue length should be 11.23*0.04 only, right? I am not able to understand which distance we are considering after subtracting from 800 m ?
@@parthpandey4186 No, queue length will be infinite if the truck stays on the road for indefinte time and therefore queue length will depend on the time spent by the rruck on the road. the first vehicle is the queue has also moved 800 m during this time. Therefore formation of the queue will be slower (compare it with a traffic sgnal where the first vehicle is stopped).
sir,
please make video on polish stone value and resin based skid resistance 🙏
Deepak ji, I have noted down this topic for my future video. Thanks for suggestion,
For the first state, the K is solved by a quadratic equation, why did you choose the lower value 10.96 instead of the other value 114.04
It is because state 1 is in stable flow condition, when volume is less than capacity. State 2 is congested condition and therefore k will be higher.
Sir, in state 1, there are two values for K but you only consider 10.96. Why is that sir plz help !
The second value of k is 114 veh/km, which is unrealistic. Please see the equation is not correctly printed (very sorry). It is Q = k(100 - 0.8K) or 1000 = 100k - 0.8 (k squared).
@@SatishIITR thanks
Difference between Shockwave and Queuing ?
These are two different term. Queuing is the process of joining the queue by a vehicle. Shock wave is the speed at which a queue buils up or dissipates.
@@SatishIITR Thank you Sir
@@shubhamkumarsingh3449 stay blessed
Sir,
Kindly explain how we arrive at the formula for calculating the max queue length in the above example.
It is simple Aman. In a normal case, the queue length is red time multiplied by the rate of arrival. Here it is equal to red time multiplied by the velocity of the shockwave.
@@SatishIITR sir why you have subtracted the total length shockwave travelled in 0.04 hour with 800m?This concludes that max distance the shockwave will travell will be equal to the distance traveled by the truck? It's confusing please explain!!
@@amansartaz5864 No, The maximum distance of shock wave is 0.35 km (350 m) and it will take 0,04 h to reach this distance.
Hello sir, can you please send me the zip folder for IITPAVE software? I will send you my email if you accept.
I have already sent this folder to you yesterday. Please check your mailbox.
@@SatishIITR Thank you sir