Phase Plane | Nonlinear Control Systems

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  • เผยแพร่เมื่อ 6 ก.ค. 2024
  • Topics covered :
    00:34 Phase plane analysis
    02:31 Butterfly effect
    03:19 Mathematical definition of Phase plane method
    03:50 Symmetry of phase trajectories in phase plane
    Animations by Prof. Robert Ghrist: ve42.co/Ghrist
    EDIT : While discussing about symmetry with respect to x2 axis, for f(x1,x2) to be an odd function of x1, the formula should be f(x1,x2)=-f(-x1,x2)

ความคิดเห็น • 34

  • @krishnajithk9322
    @krishnajithk9322 3 ปีที่แล้ว +9

    Thank you for the explanation. I think symmetry of the phase trajectories about the X2 axis the statement is correct ie ; f(x1,x2) should be an odd function of X1 but the formula should be f(x1,x2)=-f(-x1,x2) right ?

    • @Topperly
      @Topperly  3 ปีที่แล้ว +2

      Yes you are right! I'm sorry. This mistake slipped past while I edited the video. Thank you for notifying me!

  • @philasandenxumalo192
    @philasandenxumalo192 ปีที่แล้ว

    awesome video. very straight to the point. The whole series of NONLINEAR CONTROL SYSTEM videos have just saved my life

    • @Topperly
      @Topperly  ปีที่แล้ว

      Thank you for your kind words :)

  • @anurag8484
    @anurag8484 4 ปีที่แล้ว +7

    next level visuals

    • @Topperly
      @Topperly  4 ปีที่แล้ว

      Thank you! Hope this video was helpful. :)

  • @bofasaldana6849
    @bofasaldana6849 2 ปีที่แล้ว

    This is such a great video! I loved the animations and the wonderful explanation. Thank you!

    • @Topperly
      @Topperly  2 ปีที่แล้ว

      Glad to hear that :)

  • @surbhi57866
    @surbhi57866 3 ปีที่แล้ว +1

    I genuinely didn't felt it was about 8 mins video. Good work!

    • @Topperly
      @Topperly  3 ปีที่แล้ว +1

      Thank you! Your words mean a lot to us :)

  • @GauravGupta-pb8mk
    @GauravGupta-pb8mk 3 ปีที่แล้ว

    Thank you sir

  • @vigneyshukla2155
    @vigneyshukla2155 ปีที่แล้ว

    Thanks you so much for this wonderful explanation with animations

    • @Topperly
      @Topperly  ปีที่แล้ว

      Thank you for your kind words :)

  • @ImthiasAhamed
    @ImthiasAhamed 4 ปีที่แล้ว +1

    Very good and systematic lectures
    Thank you

    • @Topperly
      @Topperly  4 ปีที่แล้ว

      Thank you! Your appreciation means a lot :)

  • @sonjababac9033
    @sonjababac9033 2 ปีที่แล้ว

    Thanks a lot for your explanation! It helped me a lot for preparing Modeling Dynamics exam :)

    • @Topperly
      @Topperly  2 ปีที่แล้ว

      Glad to hear that :)

  • @saptarshisahoo5075
    @saptarshisahoo5075 4 ปีที่แล้ว

    great Video. Thank you

    • @Topperly
      @Topperly  4 ปีที่แล้ว

      Your appreciation means a lot! Thank you :)

  • @AbidAli-rz9xi
    @AbidAli-rz9xi 3 ปีที่แล้ว +1

    wow.. that's pretty cool..which software have you used for visual effects and animation ?

    • @Topperly
      @Topperly  3 ปีที่แล้ว

      If you see the video description, you can see that the animation credits goes to Prof. Robert Ghrist. I took permission from him to use it in this video :)

  • @Callejondelgaming
    @Callejondelgaming 4 ปีที่แล้ว +1

    Hello and thank you for the explanation, i have only one question, when you compare the two ecuations of dx2/dx1 to get the ecuation f(x1,x2)=f(x1,-x2) why the two dividing X2 are negative? i thought that only the X2 from the ecuation dx1/dx2 in the 4th quadrant was negative.

    • @Topperly
      @Topperly  4 ปีที่แล้ว +1

      I believe you are referring to moment 06:43 of the video. Please note that I'm simply substituting f(x1,x2) in place of f(x1,-x2) in the expression (-f(x1,-x2)/(-x2)). Hence -x2 is from the 4th quadrant itself. It's not changing. I hope this clears your doubt. If not, please comment. I'm happy to explain again :)

    • @Callejondelgaming
      @Callejondelgaming 4 ปีที่แล้ว

      @@Topperly yeah thank you for your explanation, so f(x1,x2) is equal to f(x1,-x2).

    • @Topperly
      @Topperly  4 ปีที่แล้ว +1

      Yes :)

  • @blessoneasovarghese9834
    @blessoneasovarghese9834 3 ปีที่แล้ว +1

    4:41 about the straight line which u plotted as f(x1,x2) : Is it the function f(x1,x2)=0? Because there is not coordinate to mark the value of 'f'. The straight line you plotted is x2=x1 or (x2-x1) = 0 or f(x1,x2)=0, where f(x1,x2)=x2-x1. Please clarify this.

    • @Topperly
      @Topperly  3 ปีที่แล้ว

      Hi Blesson,
      As you rightly said, we are not plotting the value of function f. We are simply plotting the function f=0 which is a function of two variables x1 and x2 in the x1-x2 plane.

  • @guillermoolay4416
    @guillermoolay4416 3 ปีที่แล้ว

    really good videos, i am a study a master degree in control and one subject is non-linear systems and control and i have been looking for online curses but aren't good, this videos are really good, may be you can aboard slinding control for next control methods.

    • @Topperly
      @Topperly  3 ปีที่แล้ว

      Thank you for your kind words :)

  • @future_millionarie4560
    @future_millionarie4560 2 ปีที่แล้ว

    it was magical...

    • @Topperly
      @Topperly  2 ปีที่แล้ว

      Thank you :)

  • @ashtiw11
    @ashtiw11 3 ปีที่แล้ว

    Don"t you have any patreon account?

    • @Topperly
      @Topperly  3 ปีที่แล้ว

      Sorry, we don't have a patreon account. Our channel is comparitively new to youtube and hence we are still building up.

  • @PrasannaRoutray97
    @PrasannaRoutray97 10 หลายเดือนก่อน

    x1 = x, x2 = x1Dot = xDot, x2Dot = xDDot = -f(x1, x2).