Phase Plane | Nonlinear Control Systems
ฝัง
- เผยแพร่เมื่อ 6 ก.ค. 2024
- Topics covered :
00:34 Phase plane analysis
02:31 Butterfly effect
03:19 Mathematical definition of Phase plane method
03:50 Symmetry of phase trajectories in phase plane
Animations by Prof. Robert Ghrist: ve42.co/Ghrist
EDIT : While discussing about symmetry with respect to x2 axis, for f(x1,x2) to be an odd function of x1, the formula should be f(x1,x2)=-f(-x1,x2)
Thank you for the explanation. I think symmetry of the phase trajectories about the X2 axis the statement is correct ie ; f(x1,x2) should be an odd function of X1 but the formula should be f(x1,x2)=-f(-x1,x2) right ?
Yes you are right! I'm sorry. This mistake slipped past while I edited the video. Thank you for notifying me!
awesome video. very straight to the point. The whole series of NONLINEAR CONTROL SYSTEM videos have just saved my life
Thank you for your kind words :)
next level visuals
Thank you! Hope this video was helpful. :)
This is such a great video! I loved the animations and the wonderful explanation. Thank you!
Glad to hear that :)
I genuinely didn't felt it was about 8 mins video. Good work!
Thank you! Your words mean a lot to us :)
Thank you sir
Thanks you so much for this wonderful explanation with animations
Thank you for your kind words :)
Very good and systematic lectures
Thank you
Thank you! Your appreciation means a lot :)
Thanks a lot for your explanation! It helped me a lot for preparing Modeling Dynamics exam :)
Glad to hear that :)
great Video. Thank you
Your appreciation means a lot! Thank you :)
wow.. that's pretty cool..which software have you used for visual effects and animation ?
If you see the video description, you can see that the animation credits goes to Prof. Robert Ghrist. I took permission from him to use it in this video :)
Hello and thank you for the explanation, i have only one question, when you compare the two ecuations of dx2/dx1 to get the ecuation f(x1,x2)=f(x1,-x2) why the two dividing X2 are negative? i thought that only the X2 from the ecuation dx1/dx2 in the 4th quadrant was negative.
I believe you are referring to moment 06:43 of the video. Please note that I'm simply substituting f(x1,x2) in place of f(x1,-x2) in the expression (-f(x1,-x2)/(-x2)). Hence -x2 is from the 4th quadrant itself. It's not changing. I hope this clears your doubt. If not, please comment. I'm happy to explain again :)
@@Topperly yeah thank you for your explanation, so f(x1,x2) is equal to f(x1,-x2).
Yes :)
4:41 about the straight line which u plotted as f(x1,x2) : Is it the function f(x1,x2)=0? Because there is not coordinate to mark the value of 'f'. The straight line you plotted is x2=x1 or (x2-x1) = 0 or f(x1,x2)=0, where f(x1,x2)=x2-x1. Please clarify this.
Hi Blesson,
As you rightly said, we are not plotting the value of function f. We are simply plotting the function f=0 which is a function of two variables x1 and x2 in the x1-x2 plane.
really good videos, i am a study a master degree in control and one subject is non-linear systems and control and i have been looking for online curses but aren't good, this videos are really good, may be you can aboard slinding control for next control methods.
Thank you for your kind words :)
it was magical...
Thank you :)
Don"t you have any patreon account?
Sorry, we don't have a patreon account. Our channel is comparitively new to youtube and hence we are still building up.
x1 = x, x2 = x1Dot = xDot, x2Dot = xDDot = -f(x1, x2).