Cannot believe someone can make physics seem so easy, i study from my book and whenever i feel like i am unable to apply any topic to questions or just simply i am not understanding it , I come here and you totally give the feel of physics to students, In my school the teachers dont teach properly(i know it is very disrespectful but thats the truth) They never do any derivations or questions and just read out the definitions of topics, like can you believe a lecture of physics in which the teacher just keeps sitting down and does not even write the name of chapter on board let alone the derivations or numericals, your channel has proved to be a very big help to me. Thanks alot sir.🗿🗿
Sir I have one doubt. Please reply this one. Sir you have imagined that radius of drop is increasing by dr and pressure is also increasing by dp...... But equation dictates that increse in radius results in decrese in pressure inside the drop!!
dr is small change and change can be -ve and +ve... The Equation tells that pressure decreases on increasing volume.. Which is correct... We Initially don't assume dr to be +ve Or -ve but upon solving we can see dr to be -ve...
Sir, soap bubbles k case me dono surface reduce hona chahte h , what does this mean , outer surface aur inner surface k reduce hone k directions kya honge ?
Sir is derivation me for liquid drop & for soap bubble dono k leye work done jo left me equation leya gaya hai waha ek hi surface area ku leya gaya hai 4(pi)(r)2..soap bubble k leye to work done due to double area [ p x 2{4(pi)(r)2} = 16T (pi)(r)2 ] hona caheye..
Hello sachin sharma ! For writing I use SmoothDraw 4.0.5. It is like MSPaint, but better than that. For recording the screen I use CamStudio 2.7. Both of them are free of any cost. Writing Pad : iBall Pen Digitizer Model No. 8064. And as always .... thanks for following us.
Sir don't you tnink that force in soap bubble will be two time i.e. 2*P* 4 (pie ) * r^2* 2dr .( dr inside and dr outside as you take increase in surface area two time Plz reply sir, thank you
this derivation actually gave me the feel rather than the derivation done in class.
Cannot believe someone can make physics seem so easy, i study from my book and whenever i feel like i am unable to apply any topic to questions or just simply i am not understanding it , I come here and you totally give the feel of physics to students, In my school the teachers dont teach properly(i know it is very disrespectful but thats the truth) They never do any derivations or questions and just read out the definitions of topics, like can you believe a lecture of physics in which the teacher just keeps sitting down and does not even write the name of chapter on board let alone the derivations or numericals, your channel has proved to be a very big help to me. Thanks alot sir.🗿🗿
Sir u solve each derivation very easily 🙏🙇thanks
Sir your teaching method is very useful to me.
I am a private Tutor also.your explanation is excellent.
Sir Aap se excellent koye nahi
Excellent video very helpful
thanks sir aap gjb ka smjhate ho wo bhi practically taur p iissse hme smjhne m bhut aasani ho jati h...keep supporting us sir fabolous👍👍👍👍👍👍👍👍👍👍
Not clear explanation
Thanks for the derivation.... Understood Finally...
Hello Sparsh ! You are welcome and as always... thanks for watching.
Thank you so much sir✨
It was so clear...thanks for such good video...
+EVERYTHING TECHNICAL
You are welcome and good luck.
And as always..... thanks for watching.
it was really very gud understood it clearly.
Best video for c.tech first year students
thnks sir...ap bot achhi treh smjhate ho..thnks a lot sir..bs ap chemistry ki or video bna diya kro
Osm explanation sir...
Very nice. I didn't understand the derivation with balancing force of surface tension so watching this.
Hello ARJAV GARG !
Thanks for your support and encouragement.
Aapka saath hamari taqat hai.
Thanks a lot sir...total cleared my doubt
Thank you for the fantastic explanation sir🙂🙂🙂
Nice voice tone gr8 work 👍
Well explained, helped during exam time
Thanx a lot sir.. Totally cleared my concept
+Debojit Roy
You are welcome.
It's really a very very good video
Thanks ❤️
Thanks for your lucid explanation.
Thanks a lot sir ❤ 🙏
fab video sir!
Nice explanation...
Respected sir, कृपया बताएं आप कौन सा software ya device use karte hai vedio banane me , please help
thanks sir. waiting for other videos. i have subscribed it
How is principle of virtual work related to it
Good explanation
Supper explain tq sir
thanks sir very good teaching sir thank u sir finally i understood
really maja aa gaya thank you sir
+surendra singh
Welcome and thank you very much for being supportive.
Your support is very helpful.
Aapko ascent formula ke uper video banana chahiye
When you wrote the expression for work done on bubble why don’t we consider pressure as p+dp which causes a change of dr?
Yes I also have the same doubt
I think this work done p* area is already stored in PE as this drop behave like a streched membrane due to surface tension same like as string
In p+dp, only dp is responsible for the work done. So it shouldn't be P but dp. The final equation will be dp=2T/R. dp is excess pressure.
Cause that change dr is very small that the pressure inside bubble remains unchanged
Superb
Sir I have one doubt.
Please reply this one.
Sir you have imagined that radius of drop is increasing by dr and pressure is also increasing by dp......
But equation dictates that increse in radius results in decrese in pressure inside the drop!!
Ans plz
dr is small change and change can be -ve and +ve... The Equation tells that pressure decreases on increasing volume.. Which is correct... We Initially don't assume dr to be +ve Or -ve but upon solving we can see dr to be -ve...
Thank u sir....soooo much.
Thank you
Sir, soap bubbles k case me dono surface reduce hona chahte h , what does this mean , outer surface aur inner surface k reduce hone k directions kya honge ?
best than thought in school
well explained
+Comedy Clips
Thanks........
Thanks for made this
Thank you sir
Sir ye mujhe sab ache se samjh main aa gaya par aapne jo let kiya ki ye ek adiabatic process hai iske puche koi fact hai ya ise let karna padta hai
Sir is derivation me for liquid drop & for soap bubble dono k leye work done jo left me equation leya gaya hai waha ek hi surface area ku leya gaya hai 4(pi)(r)2..soap bubble k leye to work done due to double area [ p x 2{4(pi)(r)2} = 16T (pi)(r)2 ] hona caheye..
which app u used for making vdo
Please upload more videos related to BSc physics ❤️🙏
Dear sir hydraulic machine ke kuch topics upload kariye Kaplan turbine etc.thanks
Nice
Makes vedios on ripple methode of determination of surface tension for bsc. Please sir!!!!!!!!!
Sir yahi request hai ki science ka koye ve topic Aap se bachne naa paye......
Please cover all topic of science......
Tnq
Very good ....Sir which software or writing pad used for Lecture
Hello sachin sharma !
For writing I use SmoothDraw 4.0.5. It is like MSPaint, but better than that.
For recording the screen I use CamStudio 2.7.
Both of them are free of any cost.
Writing Pad : iBall Pen Digitizer Model No. 8064.
And as always .... thanks for following us.
Thanks sir....
sir agar koe bubbles par charge spread karte hai to kitni radius bathegi bubbles ki
Sir don't you tnink that force in soap bubble will be two time i.e. 2*P* 4 (pie ) * r^2* 2dr .( dr inside and dr outside as you take increase in surface area two time
Plz reply sir, thank you
Yes it would be
In a soap bubble the surface tensions are acting in opposite directions so why does the expression become double that for a drop?
Thank yuo so much
topic on nuclear model
Sir plzz 12 ka v Sare chapter ka video daliye..... It is a humble request🙏😊🙏😊🙏😊🙏😊🙏😊🙏😊🙏😊🙏😊🙏😊🙏😊🙏😊🙏😊
Available.
Sir can you uploaded numerical solution of class 11 and 12 physics on this chennal. NCERT based
sir face revel kab karo ga?????????
Sir plss tell how air bubble have 1 surface and soap bubble have 2 surface
Isame jo work done hai use kya kahenge apana kam ? lekin yaha pe jo bubble ya drop jo bada hua use work done kahte hai?
Sir Lekin force will be p+dp × area
Archana Hire ryt.. I was thinking the same
I think this work done p* area is already stored in PE as this drop behave like a streched membrane due to surface tension same like as string
It vil end up vid dp*dr which can be neglected as dp & dr is very small
I could not understand why P is coming instead of dP.
Please can someone explain the adiabatic assumption part
Sir dr^2 ke sath 4π kyu cancel hua??
sir what about pressures inside a cylindrical bubble
Hello dharun chagarlamudi !
OK ! let me create that video.
And as always ... thanks for watching.
@@edupoint.physics is there anything like a cylindrical bubble?
S/r
A. Diabetic for adiabatic
Ooooooo.
Yes I was wrong there.
SHM (BSc) par v ek series..exam najdik h ..help bhaiyya
Hello Faizan Raza,
I shall try my best.
sir excess pressure is P-Pa = ∆p not P
I am just looking for ONE good english tutorial... guyz pleaseeee speak englishhhh
Sir excess pressure inside an air bubble in the liquid to btaye hi nhi.... Uska video bhejie
+Nitish Bhakat
Are you sure?
EduPoint yes uska various condition wala
Additives in Hindi
y
mood khrab ho gya 1 min ka bat jhela diye
No sir thoda acha explaine kijiye
I shall try harder.
OK sir thank u
If I only need soap bubble..
Then I hv to see from first😣😣
Not good explanation
thank you sir.
Nice
Additives in Hindi