Professor Organic Chemistry Tutor, thank you for analyzing the Second Derivatives of Parametric Equations that Concaves Up or Down in Calculus I/II. This is an error free video/lecture on TH-cam TV with the Organic Chemistry Tutor.
Lol hopefully you figured it out by now but, the dt comes from the notation. What the notation of the derrivative tells us is "with respect to the function called..., take the derrivative of the varriable ...". In this case, we're taking the derrivative of the function defined by x, with respect to the variable t. And with respect just means that that is what we're treating as a variable and everything else for that function isn't
@@tinmay292 students today are too conformed to the idea of abiding to the rules or in this case, "following formulas." They don't question certain concepts and they don't wonder where certain formulas come from. All they care about is getting the right answer and just getting their homework done with.
one error, once you have taken the second derivative with respect to t, which equaled 1/8, that means the entire graph respect to t is increasing, not only at point t=2.
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Your explanations are amazing and the reason I have a 92 in calc 2, 14 years after taking calc 1....you are my lifesaver!
definitely same also in my condition
This channel literally proves we literally attend lectures only to return home and learn via TH-cam. 🤣Great video
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Professor Organic Chemistry Tutor, thank you for analyzing the Second Derivatives of Parametric Equations that Concaves Up or Down in Calculus I/II. This is an error free video/lecture on TH-cam TV with the Organic Chemistry Tutor.
at the end h says square root 15/3 when its square root 5/3 lol but bro is still saving me from failure
انت راجل محترم و كفاءة
OKAY NOW I KNOW WHO TO FOLLOW
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Another Superb Learning Session: ) Keep it up
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at 6:03 correct me if im wrong. The numerator coud have been simplified even more
this man really saving me rn
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what if i first elliminate the parameter,will i get the same answer
Can I know whether to include the (5/3)^(1/3) in the interval or not?
From what I know, it shouldn't be included as its result is zero! Neither positive nor negative number!
@@godwinsilayo1863 I see.. Thank you!
hello, how did you solve for "t" in the beginning to get 2?
That’s just part of the question, it’s asking for the slope and concavity at the point where t=2
Thanks alot .
1:00 Where's the t from?
Lol hopefully you figured it out by now but, the dt comes from the notation. What the notation of the derrivative tells us is "with respect to the function called..., take the derrivative of the varriable ...". In this case, we're taking the derrivative of the function defined by x, with respect to the variable t. And with respect just means that that is what we're treating as a variable and everything else for that function isn't
thanks
thanks again
Why don't we derivative the dy/dx to get the second derivative? I got a different result if I do this. What's wrong here??? Thank you!
I mean why we need to divided dx/dt?
Thats the formula we need to follow it
@@tinmay292 students today are too conformed to the idea of abiding to the rules or in this case, "following formulas." They don't question certain concepts and they don't wonder where certain formulas come from. All they care about is getting the right answer and just getting their homework done with.
let us see what you did
@@davisjohn-d6h I mean that was always the case...
What if dx/dt is zero?
Good
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dört sene oldu nasılsın joplu ayı
Thank
What if d^2y/dx^2 does not include a t?
What does it include?
did u figure out this question yet, I still need halp
Why we just derivate x one time ?
one error, once you have taken the second derivative with respect to t, which equaled 1/8, that means the entire graph respect to t is increasing, not only at point t=2.
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Useless