Brother Schellenberg, since graduating and then trying to get back into the swing of school I’ve definitely seen the value in the way you structured your online class work. Thanks for putting in the work to put these courses together. This man was one of my instructors in college. He’s a terrific teacher.
IF you took off the rod on the left cylinder (that was being used as an amplifer).. then you would have the same lift distance and amount of oil transfering to the right cylinder with the load
Genesis 12 verse 3 in action... The chosen people sharing their blessed knowledge of using their bodies as minds as an asset to the universe and at one with the energy of God's plan. Thank you Lord Jesus for Sharing that law with all nations.... Plus the step up in heavenly qualities you introduced for every person on Earth to share and accept ✝️🕎
Actualy is one slight mistake. Real lifting weight must be under 3400 pounds because at 3400 pounds we have the same pushing strenght in both dorecton so result becomes 0 lifting. Actualy a good lift from that schematic would be at about 3000 pounds of weight.
Hey bud I know this is way old but thanks to you my kid built some crazy shit with hydraulics I mean some crazy crushing robot shit & at 10 years old I I taught her how to TIG weld and for my auto shop she made me one hell of a car hoist lol ya I did all the finishing welds to be safe but she did it all her self & she told me it was you that helped her understand it way betrer so thanks I'm a proud dad she's only 10 I'm in trouble as she gets older lol stuff that I could not figure out but thanks to your video she did some amazing stuff so I just wanted to say thank you whether you see this or not I don't know but thanks a lot you know I owe you your way better than the library especially the way you explained it she understood it fully compared to some of the books that she was reading & you know just to make it clear yes you could have went in school but she's only 10 years old so thanks
For me the question is what happens when running the cylinders in series when both have equal loads, not just one or the other. Will they move together with equal force at the same time?
So its the normal force-per-area that decides how much force something pushes on something else. The heavy block decides how much pressure it will make on the water be matter the size of the area/diameter. That weight can be used to create low pressure on big areas/volume or high pressure if its a small areavolume.. The weight and the water is the same as the matter in m = V/pressure. You need to count how much liquids there is in the cylinder before you can count the pressure right?
Great video, but the word "hydraulic amplifier" is not quite correct. That's more a hydraulic pressure transformer. With the amplifier the outgoing energy is more than the input energy!
Most manufacturers will use different piston and sizes to those pistons for dimensional diameters for the same bore and same rod size. Is there a universal repair kit made for 4 inch x1.75 shaft size?
Amazing explanation. I want to synchronize 2 hydraulic cylinders, same speeds and same positions. The master cylinder has 2.5" Bore size and 1.5" Rod diameter. I calculated the resulting area of the master cylider. Bore area - Rod area = 2.5x2.5x3.14/4 - 1.5x1.5x3.14/4 = 4x3.14/4 = 3.14in2 The slave cylinder area then should be 3.14in2 DxDx3.14/4 = 3.14 --------- Then square DxD = 4 ------------- D = 2in where D is the slave cylinder diameter. are my calculations correct? Also I want to know if you have previously syncronyzed cylinders, how precise could be. Do you think I can improve the error we already have of using a flow divider at 50%? Regards;
Ro, Thank you for watching. Many people who want to synchronize 2 hydraulic cylinders can do so by putting them in parallel and then using a flow divider. Here is a video highlighting the two types of flow dividers: th-cam.com/video/eRhHbgE3dAs/w-d-xo.html Aaron
Hello Aaron, we have a flow divider 50 and 50 but it does not acurately divides the flow. One of the cylinders moves faster than the other. (could be the 10% of tolerance accuracy? I asked for some help and the engineer I asked told me that gear flow divider is more accurate than the spool flow divider. What is the more accurate method?
you need a fluid slitter, It work by 1 input 2 outputs like 1,gal in 2, 1/2 gal out. you can look it up "hydraulic fluid divider" or "adjustable hydraulic fluid divider" with google or any search
Dear Sir..........I have single acting a cylinder with a bore of 18 mm and a rod of 10 mm and a stroke of 300 mm. I want to know what is the pressure if my cylinder presses 1 mm ........... Please advise and provide a solution with the formula
I deal in water at lower pressures. It seems to me that you are ignoring friction loss and elevation change in the line(s) between the cylinders. Is this because they are very small compared other pressures ? In any case great videos, very informative
You are correct. In hydraulics we are usually dealing with 1500 psi and the elevation change is pretty minimal. since it may only affect 5 psi when in a mobile application. Friction loss is is also small through the hydraulic lines and fittings since we design for laminar flow and may only get 30-50 psi drop in the system. However, we are always worried about heat generation in the oil most of which is caused by inefficiency of our pumps and motors but a portion is caused by friction loss in the lines.
isn't the 'stroke' length also dependant on how far away from the actual ends of the cylinder the valves are installed to either bring fluid in or drain it?
I have a question. I have a tractor with one hydraulic cylinder that operates the bucket dump function. If I add another cylinder of the same size without changing the psi coming from the pump would I gain anything?
Dear Sir............Example Problem I have a single acting hydraulic cylinder with a stroke of 300 mm, a bore of 18 mm and a rod of 10 mm if the press weight is 10 mm on the Piston Head what is the pressure.....Please explain the calculations
And I said why should I watch this? I know all about hyd cyls! Well I stand corrected, this was so well done, thank you for the time it took to put this together.
F=PxA. Algebra calls for dividing both sides of the equasion by F, leaving PxA/F/ The F cancles out if divided into F on the left side of the equasion. This IF Algebra causes a fight to break out with the Electricians since 1900. Coverting to business math does not help. This same relationship mathematically cannot be pondered unless they have thoughts that are not going to cause harm to themselves or others. E=IxR can cause death to Electricians.
Dear Sir............Example Problem I have a single acting hydraulic cylinder with a stroke of 300 mm, a bore of 18 mm and a rod of 10 mm if the press weight is 10 mm on the Piston Head what is the pressure.....Please explain the calculations
Brother Schellenberg, since graduating and then trying to get back into the swing of school I’ve definitely seen the value in the way you structured your online class work. Thanks for putting in the work to put these courses together.
This man was one of my instructors in college. He’s a terrific teacher.
Thank you! You explain things so logically. Made far more sense than my teacher...
Pressure amplification! I never knew that.Thanks.Brilliant presentation.
This is one outstanding video! Not one person in a thousand. trying to explain something, can articulate the way this gentleman does.
Mez mas as y
lllllppllll😥😧😥😥😧😧😥😧😧😧😧😥😧😧😧😧😧😧😧
lp😧😧😂🔰🔰🔰😑😂😂😂🔰😂😂😂🔰😂🔰🔰😂😂😂😑😑😧😂😂😂😂😂🔰🔰🔰😂🏢🔰🔰🔰🏢🔰🔰🔰🏢🔰🔰🔰🔰🔰🔰🔰🔰🔰🔰🔰🔰🔰🔰🔰🔰🔰🔰🔰🔰🔰🔰🔰🔰🔰🔰🔰🔰🔰🏢🔰🔰🔰🔰🔰🔰🔰🔰🔰🏢🔰🔰🔰🔰🔰🔰🔰🏢🏢🔰🔰🔰🔰🔰🔰🔰🔰🔰🔰🔰🔰🔰🔰🔰🔰🔰🔰🔰🔰🔰🔰🔰🔰🔰🔰🔰🔰🔰🏢🏢🔰🔰🔰
pllppppppp
This is 6 year old video and have all the information I needed.
Thanks
Wow. I just found your video and immediately I can assess the clarity of your presentation. I will look for more of your videos. Thank you.
Thank you for the knowledge that you share ❤️ good teaching very easy to understand.
GOD bless 🙏
Nice video I understood very well and he explain very well
What software did you use?
The illustration and presentation were both excellent.
Aaron Schellenberg Great video, man. Thank you.
This is very interesting , i have not heard of pressure amplifier back in my school days, very informative video thanks Mate!
Thank you Mr Aaron , I found it so useful.
Put some more videos like this which are related to Hydraulics or Mechanical Engineering ...
Very impressive teaching skills and voice...
IF you took off the rod on the left cylinder (that was being used as an amplifer).. then you would have the same lift distance and amount of oil transfering to the right cylinder with the load
Could you please do more videos on hydraulic. You explain really well
penjelasan yang sangat baik dan mudah dimengerti. terima kasih
Genesis 12 verse 3 in action... The chosen people sharing their blessed knowledge of using their bodies as minds as an asset to the universe and at one with the energy of God's plan. Thank you Lord Jesus for Sharing that law with all nations.... Plus the step up in heavenly qualities you introduced for every person on Earth to share and accept ✝️🕎
what size hydraulic pump do I need for 5 horse power at 3000 psi and what is the formula at 1600rpm
Really clear explanation, thanks
Fantastic. thanks for putting the video together
Great teaching, very nice.. now i want to figure out how much air does it take if this same cylinder was at 10 psi to fully extract the piston please
I do like the clarity of your presentation.
FYI, the area is always 78.5% of the square of the diameter
logically explained, it was so understanding. Thank you for the video
VERY NICE AND EASILY UNDERSTANDABLE VIDEOS
OMG. This guy really knows his stuff into the detail. The explanation was perfect. Thanks for the video.
Awesome presentation! That was explained very well, thanks.
great explanation but it would be better if it was metric it is as clear as it gets tho
Thank You so much for your lesson. It is clear and fluently.
great video, you explained very well
Actualy is one slight mistake. Real lifting weight must be under 3400 pounds because at 3400 pounds we have the same pushing strenght in both dorecton so result becomes 0 lifting. Actualy a good lift from that schematic would be at about 3000 pounds of weight.
Great work bro. Thank you
Hey bud I know this is way old but thanks to you my kid built some crazy shit with hydraulics I mean some crazy crushing robot shit & at 10 years old I I taught her how to TIG weld and for my auto shop she made me one hell of a car hoist lol ya I did all the finishing welds to be safe but she did it all her self & she told me it was you that helped her understand it way betrer so thanks I'm a proud dad she's only 10 I'm in trouble as she gets older lol stuff that I could not figure out but thanks to your video she did some amazing stuff so I just wanted to say thank you whether you see this or not I don't know but thanks a lot you know I owe you your way better than the library especially the way you explained it she understood it fully compared to some of the books that she was reading & you know just to make it clear yes you could have went in school but she's only 10 years old so thanks
best explanation ever I have seen!!
can you do a video on how these forces are balanced to compensate for the loss and imbalance in cylinder movement
For me the question is what happens when running the cylinders in series when both have equal loads, not just one or the other. Will they move together with equal force at the same time?
Neither Fred
Thanks for the very clear explanation. It will help me design the hydraulic press I am contemplating.
So its the normal force-per-area that decides how much force something pushes on something else. The heavy block decides how much pressure it will make on the water be matter the size of the area/diameter. That weight can be used to create low pressure on big areas/volume or high pressure if its a small areavolume.. The weight and the water is the same as the matter in m = V/pressure. You need to count how much liquids there is in the cylinder before you can count the pressure right?
Could u make vedio about calculating required wall thickness of cylinder
Great video, but the word "hydraulic amplifier" is not quite correct. That's more a hydraulic pressure transformer. With the amplifier the outgoing energy is more than the input energy!
Most manufacturers will use different piston and sizes to those pistons for dimensional diameters for the same bore and same rod size. Is there a universal repair kit made for 4 inch x1.75 shaft size?
Amazingly explained. Thank you!
Great video. Helped me get a foot in the door.
Then the hydraulic pressure crushed it.
Good day - your assumption of the 1000 psi variable can you elaborate on that please ???
Regards
Amazing explanation. I want to synchronize 2 hydraulic cylinders, same speeds and same positions.
The master cylinder has 2.5" Bore size and 1.5" Rod diameter.
I calculated the resulting area of the master cylider.
Bore area - Rod area = 2.5x2.5x3.14/4 - 1.5x1.5x3.14/4 = 4x3.14/4 = 3.14in2
The slave cylinder area then should be 3.14in2
DxDx3.14/4 = 3.14 --------- Then square DxD = 4 ------------- D = 2in
where D is the slave cylinder diameter.
are my calculations correct?
Also I want to know if you have previously syncronyzed cylinders, how precise could be.
Do you think I can improve the error we already have of using a flow divider at 50%?
Regards;
Ro,
Thank you for watching. Many people who want to synchronize 2 hydraulic cylinders can do so by putting them in parallel and then using a flow divider. Here is a video highlighting the two types of flow dividers: th-cam.com/video/eRhHbgE3dAs/w-d-xo.html
Aaron
Hello Aaron, we have a flow divider 50 and 50 but it does not acurately divides the flow. One of the cylinders moves faster than the other. (could be the 10% of tolerance accuracy?
I asked for some help and the engineer I asked told me that gear flow divider is more accurate than the spool flow divider.
What is the more accurate method?
you need a fluid slitter, It work by 1 input 2 outputs like 1,gal in 2, 1/2 gal out. you can look it up
"hydraulic fluid divider" or "adjustable hydraulic fluid divider" with google or any search
@@jessecobern2069 I solved it with a flow divider 50% and it worked amazing, I tested different methods but only that worked properly
@@aaronschellenberg what mean is 200psi
Excellent video.
if load is going down, which work must the motor do?
Thanks sir, meanwhile i want to know how to calculate the back pressure or restricted pressure based on port size or flow rate. Plz explain .
great video, it contains everything i need to build a simulation!
I will write my notebook. Thank you for tutorials.
Very informative video. Thank you.
What is the formula to calculate what diameter is need to push 800 ft pounds at 120 psi?
Thanks
Great video!! Thanks for sharing
Thank you sir for clearing this up, very helpful
Dear Sir..........I have single acting a cylinder with a bore of 18 mm and a rod of 10 mm and a stroke of 300 mm. I want to know what is the pressure if my cylinder presses 1 mm ........... Please advise and provide a solution with the formula
I deal in water at lower pressures. It seems to me that you are ignoring friction loss and elevation change in the line(s) between the cylinders. Is this because they are very small compared other pressures ? In any case great videos, very informative
You are correct. In hydraulics we are usually dealing with 1500 psi and the elevation change is pretty minimal. since it may only affect 5 psi when in a mobile application. Friction loss is is also small through the hydraulic lines and fittings since we design for laminar flow and may only get 30-50 psi drop in the system. However, we are always worried about heat generation in the oil most of which is caused by inefficiency of our pumps and motors but a portion is caused by friction loss in the lines.
How to find a back pressure between cylinder and valve?
isn't the 'stroke' length also dependant on how far away from the actual ends of the cylinder the valves are installed to either bring fluid in or drain it?
No
Excellent
Very clearly stated, thanx for sharing.
Thanks a lot,The technical explanation is really simplified
I have a question. I have a tractor with one hydraulic cylinder that operates the bucket dump function. If I add another cylinder of the same size without changing the psi coming from the pump would I gain anything?
Very well explained.. Thanks
This drawing makes it look that you need three oil tanks.
Amazing explanation,thanks.
Great Explanation. Thanks a Lot................
Dear Sir............Example Problem I have a single acting hydraulic cylinder with a stroke of 300 mm, a bore of 18 mm and a rod of 10 mm
if the press weight is 10 mm on the Piston Head what is the pressure.....Please explain the calculations
Splendid. Bravo. 👏👏👏👏👏
ya its good basic explaination
And I said why should I watch this? I know all about hyd cyls! Well I stand corrected, this was so well done, thank you for the time it took to put this together.
what is the name of this app? thank you!
Perfect explanation..
Sir can you explain the linear guiding assembly.....
Nice information
perfect
and clear
hi Iam tade mechanical engineering student,can you give the design of duable acting in single rod haydraulic cylinder
Difficult to follow the cursor on the small screen of my phone, such a shame.
im enjoying thank yu
THANK U SIR ,FOR YOUR INFORMATION
software???????
F=PxA. Algebra calls for dividing both sides of the equasion by F, leaving PxA/F/
The F cancles out if divided into F on the left side of the equasion.
This IF Algebra causes a fight to break out with the Electricians since 1900.
Coverting to business math does not help. This same relationship mathematically cannot be pondered unless they have thoughts that are not going to cause harm to themselves or others. E=IxR can cause death to Electricians.
excuse me sir, so what the conclusion about your video, thanks
Thank you verry much.
Thank you
thank you
I like it
Good morning to you in the good job
I need power pack design
Ada yg punya alat ng buat 4 silinder bisah bersamaan
Thanks
អគុណthank
+
sir can you give your email ID.I want to ask some doubt in hydraulics related to my project
Dear sir pls send your mail is I I need power pack design
are you a student?.... if you put 4 in you will get 4 out... this topic is relative to the phrase water column... you need to delete this video
Dear Sir............Example Problem I have a single acting hydraulic cylinder with a stroke of 300 mm, a bore of 18 mm and a rod of 10 mm
if the press weight is 10 mm on the Piston Head what is the pressure.....Please explain the calculations