My lecturer did not explain this very well and I have been struggling to do this type of question for a long time now. Your video has come as a huge blessing. Thank you immensely.
For problem 2, it's much easier to solve algebraically first. It looks daunting because I've included extra steps for clarity and review. Most people will be comfortable jumping from 1 to 3 and then 3 to 5. It takes a minute. Doing the algebra first this way helps you spot any errors in unit analysis at the end and means you just have to move symbols, rather that keep track of numbers. If this helps you great. If it looks too scary then you should do this more until it's second nature. q1+q2+q3=-q4 "mi" is the mass of ice. "ci" is specific heat of ice. "mw" for water. "cw" for water. *NOTE* q3 considers the mass of ice, but _in liquid, or water, form._ This is because this term accounts for the grams of ice that have gone through fusion, and while they are zero degrees C, these grams are now liquid water.* 0. begin by setting up. Remember you negative sign! micidTi + midH + micwdT = -mwcwdTw 1. dT equals Tf minus T initial micidTi + midH + micw(Tf - 0) = -mwcw(Tf - #) 2. Distribute masses and specific heats micidTi + midH + Tfmicw - -0xmicw- = -Tfmwcw + #mwcw 3. anything times zero is zero, so ^ term goes away. Also pay attention to the negative and rearrange. #mwcw - micidTi - midH = micwTf + mwcwTf 4. Factor out what you can to simplify #mwcw - mi(ciTi - dH) = Tfcw(mi + mw) 5. Divide through by "cw(mi + mw)" Tf = (#mwcw - mi(ciTi - dH))/cw(mi + mw)
Thank you so much for providing examples for both situations, my professor skipped over this but assigned it for homework. I was very lost to say the least but I stumbled upon your video and you explained and walked through the process very beautifully! Thank you! After struggling on this question for over an hour now, I was able to complete it in 15 minutes!
Thank you so much.. Before this not a single teacher made me understand this logic.. You really teach so smoothly and easy to understand... At the same time your voice is so clear!!!!
Professor Organic Chemistry Tutor, thank you for using pictures and equations to explain How to calculate the Final Temperature of an Ice- Water Mixture in AP/General Chemistry. The two practice problems outline how to calculate the mass in grams of ice and how to calculate the final temperature of a mixture. These two problems can be problematic from start to finish. This is an error free video/lecture on TH-cam TV with the Organic Chemistry Tutor.
What about a question concerning some water to be in contact with ice in a low enough T, such that all water freezes to ice? How to solve the question and find the final temperature?
Amazing video, exactly what I needed!!! Thank you so much. Do you take requests for Patreon? I would definitely sign up if it meant I could ask for more of a certain type of question review before finals haha.
can you answer my question 🥺 Amin adds 50 g of ice at -10 °C into 100 g of milk at 75 °C in the mug. Compute the thermal equilibrium temperature of the system. Given the specific heat of water is 4,186 Jkg 1 °C*1, specific heat of milk is 3,830 Jkg ' °C*', specific heat capacity of ice is 2, 100 Jkg 1 °C•1 and latent heat of fusion of ice = 330,000 Jkg*-1
PLEASE I NEED THE FORMULA OF THIS… Suppose you heat 1,000grams of water into boiling and mix it with 3,000grams of Water at 16 °C contained in an aluminum pail of mass 50.0 grams. What is the resulting temperature in °C?
sorry for the lame question, but I can never understand why you use the same specific heat capcity of 4.18 ( instead of 2.11 specific heat of ice ) on the left and LEFT side of the equation, when calculating iCe melting. For instance 5295+15(4.18)*(tf-0) = 250 (4.18)*(tf-90) instead of 5295+15*(2.11)*(Tf-0) = 250*(4.18)*(Tf-90)
You said it yourself? The ice already melted. It's water now. q1 the ice is just heating up so the c is still of ice. q3, it already melted. (It melted during q2.) q3 is you calculating the melted ice heating up even further because it's mixed with warm water.
I'm not really sure why you are picking your delta T for these the way you are why is zero the point you are picking for these rather than the change in temperature between both solids... or anything else?>
Because when talking about a change in temperature it doesn't matter if it is in kelvins or Celcius because the number is going to end up being the same
The help is nice, but can you guys please increase the volume a little? It is incredibly frustrating to try to pick out what you're saying every time there is the slightest background noise. You don't have to whisper.
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In question 2 if all of the ice has melted then why it isn't the mixture temperature is 0°c ?
GOD BLESS U! and YOUR FAMILY..u are the reason im going to graduate..i dont understand the textbooks,and even worse i cant understand my lectures.
Congrats for ph.ed
My lecturer did not explain this very well and I have been struggling to do this type of question for a long time now. Your video has come as a huge blessing. Thank you immensely.
My prof never explained this and it's not in the book, this explanation makes perfect sense thanks!
For problem 2, it's much easier to solve algebraically first. It looks daunting because I've included extra steps for clarity and review. Most people will be comfortable jumping from 1 to 3 and then 3 to 5. It takes a minute. Doing the algebra first this way helps you spot any errors in unit analysis at the end and means you just have to move symbols, rather that keep track of numbers. If this helps you great. If it looks too scary then you should do this more until it's second nature.
q1+q2+q3=-q4
"mi" is the mass of ice. "ci" is specific heat of ice. "mw" for water. "cw" for water.
*NOTE* q3 considers the mass of ice, but _in liquid, or water, form._ This is because this term accounts for the grams of ice that have gone through fusion, and while they are zero degrees C, these grams are now liquid water.*
0. begin by setting up. Remember you negative sign!
micidTi + midH + micwdT = -mwcwdTw
1. dT equals Tf minus T initial
micidTi + midH + micw(Tf - 0) = -mwcw(Tf - #)
2. Distribute masses and specific heats
micidTi + midH + Tfmicw - -0xmicw- = -Tfmwcw + #mwcw
3. anything times zero is zero, so ^ term goes away. Also pay attention to the negative and rearrange.
#mwcw - micidTi - midH = micwTf + mwcwTf
4. Factor out what you can to simplify
#mwcw - mi(ciTi - dH) = Tfcw(mi + mw)
5. Divide through by "cw(mi + mw)"
Tf = (#mwcw - mi(ciTi - dH))/cw(mi + mw)
Thank you so much for providing examples for both situations, my professor skipped over this but assigned it for homework. I was very lost to say the least but I stumbled upon your video and you explained and walked through the process very beautifully! Thank you! After struggling on this question for over an hour now, I was able to complete it in 15 minutes!
Wts ur age btw?
Thank you so much.. Before this not a single teacher made me understand this logic.. You really teach so smoothly and easy to understand... At the same time your voice is so clear!!!!
massive thanks for making this video as my physics teacher failed to clearly explain this despite it coming up in a near exam
I love this channel, I carry’s me through my math and Chem tests
Professor Organic Chemistry Tutor, thank you for using pictures and equations to explain How to calculate the Final Temperature of an Ice- Water Mixture in AP/General Chemistry. The two practice problems outline how to calculate the mass in grams of ice and how to calculate the final temperature of a mixture. These two problems can be problematic from start to finish. This is an error free video/lecture on TH-cam TV with the Organic Chemistry Tutor.
Gonna pass the quiz tomorrow thanks to you
I like ur smooth voice, it'ss very calming
What about a question concerning some water to be in contact with ice in a low enough T, such that all water freezes to ice? How to solve the question and find the final temperature?
I have a feeling I'm going to be watching a lot more of your videos from now on....
Thank you teacher :D
I mean, what if the temperature goes below zero and freezes?
😂
Where does the 80.13 come from in question 2 it’s like he just came up with it
Why don’t you consider the water that would freeze at equilibrium?
For the first problem why do you not used the of Q2?
Amazing video, exactly what I needed!!! Thank you so much. Do you take requests for Patreon? I would definitely sign up if it meant I could ask for more of a certain type of question review before finals haha.
What if you have equal amount of water that you do for ice. The two Tf just cancel
So explicit!
Thank you sir
It is so helpfull but sir tell slowly !!
What is the minimum age for someone to be able to solve these questions (assuming he is an average student)
Perhaps AP chem students in high school (16 yo) or first year in college (19 yo)
I am srichaitanya techno school as and they are saying this my age 12
can you answer my question 🥺
Amin adds 50 g of ice at -10 °C into 100 g of milk at 75 °C in the mug. Compute the thermal equilibrium temperature of the system.
Given the specific heat of water is 4,186 Jkg 1 °C*1, specific heat of milk is 3,830 Jkg ' °C*', specific heat capacity of ice is 2, 100 Jkg 1 °C•1 and latent heat of fusion of ice = 330,000 Jkg*-1
He taught you, so that you can do it your self
@@PandaPanda-i4e shut up if you don't have any solutions , asking is the key in learning
bless up fam
Can i use this method to calculate how much cool water must be added to lower the temperature?
Hey,does it mean calculating the energy required for water to be at lower temp=m×specific heat capacity×∆T.
How do you know that some of the ice melts and not some of the water freezes?
Grades savior
PLEASE I NEED THE FORMULA OF THIS…
Suppose you heat 1,000grams of water into boiling and mix it with 3,000grams of Water at 16 °C contained in an aluminum pail of mass 50.0 grams. What is the resulting temperature in °C?
Thank you
How many grams are in a common 10 pound bag of ice?
is it spontaneous?
Why is it -30 and not 30 positive
because 30 degrees needs to leave the water so it’s a minus
sorry for the lame question, but I can never understand why you use the same specific heat capcity of 4.18 ( instead of 2.11 specific heat of ice ) on the left and LEFT side of the equation, when calculating iCe melting. For instance 5295+15(4.18)*(tf-0) = 250 (4.18)*(tf-90) instead of 5295+15*(2.11)*(Tf-0) = 250*(4.18)*(Tf-90)
That's my problem too. Now, I'm having confusion on when to use the specific heat of water.
That's because the process is already converting ice to water, so, the specific heat capacity should be of water.
You said it yourself? The ice already melted. It's water now.
q1 the ice is just heating up so the c is still of ice. q3, it already melted. (It melted during q2.) q3 is you calculating the melted ice heating up even further because it's mixed with warm water.
I'm not really sure why you are picking your delta T for these the way you are why is zero the point you are picking for these rather than the change in temperature between both solids... or anything else?>
But the ice melts at a temperature above 0°C, and here the final temperature is 0°C so how the ice can melts in the 1st example?
q1 is for making the ice 0 celsius. And q2 is to melt the ice from 0 celsius to whatever new temperature it becomes.
please give full ans means process
te quiero mucho video de youtube
Now I understand less
Why did You not Change the Temperature in Celcius into Kelvin
Because when talking about a change in temperature it doesn't matter if it is in kelvins or Celcius because the number is going to end up being the same
Sir tell slowly
For question two my final temperature was 78.01 C. I checked and it works but a little confused how he got 80.1 C.
on blud
The help is nice, but can you guys please increase the volume a little? It is incredibly frustrating to try to pick out what you're saying every time there is the slightest background noise. You don't have to whisper.
#JEE ASPIRANT