This is actually very helpful, my research class is not much of a help in this(stats) the formula given to us was very confusing.I got my homework correct, the first try with this video
hello Jonathan, thank you for this video. let us assume that the 1st quartile falls in the first class. what would be the cumulative frequency of the class FQ1-1? Thanks
Hi 0SakA, The quick answer is that the cumulative frequency before the quartile class would be zero. The reason is that there is a class before your first class - it just happens to have no observations in it - that is a frequency of zero. As such any cumulative frequencies would be zero too. I hope this helps. Regards. Jonathan.
@@MathsAndStats Yes, this helps a lot and makes sense. Thank you very much for the answer and making such a great video! Regardless of what others might say, NOTHING is more enjoyable than the Irish accent! All the best!
Would Q1 still be 18-31 if another class 83-102 was added (meaning that there is a now an odd total number of classes instead of an even total number of classes)?
Hi Wei. It depends on the actual frequency of observations associated with that class. The more observations there are in your new interval, the more likely the first quartile Q1will move into the following interval. Remember, quartiles are all about how many observations there are and not on their values. I hope this helps and please share :-) Regards. Jonathan
Hi Anissa, the distance between two numbers is defined to be there difference (x - y). Therefore, the distance between 5 and 18 is 18 - 5 = 13. Maybe if you count how many steps you need to take from position 5 through to 18 you will see the concept a little clearer. I hope this helps. Jonathan
I really don't know much about this sort of stuff, but is it possible for your 1st quartile, if rounded off, not be in the first quartile class? or is it impossible? Still, thanks for the video I learned a lot from it.
Ok Miles, let me try to answer your question then. If you consider the Quartile formula there are two parts to it - the first being the lower bound of the quartile class + a fractional amount of the class width. This fractional amount of the class width can only take on values between 0 and 1 (inclusive) and so the quartiles in their extreme cases can be either the lower bound or the upper bound of your class. So to answer your question - no - the quartile has to fall in the quartile class you identified (by definition the quartile class) but could reside at its extremities. I hope this helps. Kindest regards. Jonathan
You choose the first cumulative frequency (F) that exceeds 14. So with 56/4 = 14 equaling a cumulative frequency, you don't choose that, instead you choose the next one.
Hi Dalyn. Yes, of course I can. The key thing to remember is that 'Fq1-1' is a single value the '-1' is not telling us to substract 1. What it tells us is ' the cumulative frequency of the class before the quartile class.' You are correct 14 is the cumulative frequency of the quartile class, but we require the one before it, which is 4. I hope this is somewhat helpful. Jonathan
I still don't understand why he choose the 2nd class instead of the 1st class? Shouldn't the value of 13 got from the q1 belongs to the 1st class? Please help me. Tq
Hi Hazim. There are only 4 observations in the first class so the first quartile value could not possibly reside in that class. The first quartile value is the 13th observation. This must be in the second class as there are 10 observations in that class, and cumulatively there are 14. Regards. Jonathan
I wish I can like this twice. Thanks for making this so simple. I don't know why teachers enjoy shrouding and complicating things.
this is very helpful. since it was confusing to understand with my teachers.
millions of thanks..every steps explained clearly & great accent..keep it up prof!❤️👍
Thanks, Irshad. It would be great if you could share. Regards. Jonathan.
This was really helpful in preparing for my exam this weekend
A really helpful explanation.
Thank you so much!
hey man. got exam tomorrow and you saved me with this video. thanks. i really appreciate it. and love the accent man, its enjoyable. God Bless you
Hi Julius. That's great to hear and I'm glad it was of help. It would be great if you could share with your classmates. Thanks, Jonathan.
Trying to tutor my little cousin, did this ages ago. Thanks so much. Your accent is also quite enjoyable to listen to.
Thanks TM. The accent might be because I am Irish, but maybe not. :-) Thanks for watching. Jonathan
This is actually very helpful, my research class is not much of a help in this(stats) the formula given to us was very confusing.I got my homework correct, the first try with this video
That's great news Silver. Please share. Regards Jonathan.
Excellent explanation
Millions of Thanks
Thank u bro its very help full..
Very much appreciated.
Thank you very much sir!
thanks it really help me
Thank u so much!! i learned it very well now im the one teaching my friends LOL
Well, thank's great news. Please share. Regards. Jonathan.
Thank you so much.
Thankyou, it was helpful 🙏
very good, thumbs up!!!
Thank you so much 😚
shouldnt we subtract the lower bound with 0.5
Thank you
Where do you classify boundary numbers like 18, 31, 44?
Arent you going to minus the lower boundary with 0.5?
Its adding the lower boundary and the preceding upper boundary then you divide by two since they are equal no adding or subtracting any value
hello Jonathan, thank you for this video.
let us assume that the 1st quartile falls in the first class. what would be the cumulative frequency of the class FQ1-1? Thanks
Hi 0SakA,
The quick answer is that the cumulative frequency before the quartile class would be zero. The reason is that there is a class before your first class - it just happens to have no observations in it - that is a frequency of zero. As such any cumulative frequencies would be zero too. I hope this helps.
Regards. Jonathan.
@@MathsAndStats Yes, this helps a lot and makes sense. Thank you very much for the answer and making such a great video! Regardless of what others might say, NOTHING is more enjoyable than the Irish accent! All the best!
@@MathsAndStats Thank you very much for this... It's exactly what I was looking for and your explanation is very clear.
thanks!
Thanks
Would Q1 still be 18-31 if another class 83-102 was added (meaning that there is a now an odd total number of classes instead of an even total number of classes)?
Hi Wei.
It depends on the actual frequency of observations associated with that class. The more observations there are in your new interval, the more likely the first quartile Q1will move into the following interval. Remember, quartiles are all about how many observations there are and not on their values. I hope this helps and please share :-)
Regards. Jonathan
Why would the width of the class be 13 instead of 14?
Hi Anissa, the distance between two numbers is defined to be there difference (x - y). Therefore, the distance between 5 and 18 is 18 - 5 = 13.
Maybe if you count how many steps you need to take from position 5 through to 18 you will see the concept a little clearer.
I hope this helps.
Jonathan
how he arranged the data into columns.....i couldn't find the earlier video ...?please help me to find it
Hi. Here is a link to the video: th-cam.com/video/gVr2eYfc4vk/w-d-xo.html
Regards.
Jonathan
Love the accent man
Cant say 13😂😂😂
Thanks Sir
No problem Hamid. i am glad it was helpful. Jonathan.
I really don't know much about this sort of stuff, but is it possible for your 1st quartile, if rounded off, not be in the first quartile class? or is it impossible?
Still, thanks for the video I learned a lot from it.
Hi Miles,
Why don't you respond with the Grouped Frequency Distribution that you are using for your calculation and i will check.
Jonathan
Thanks for responding, Sadly I didn't use anything, I just want to know if its possible to have that kind of event to occur.
Ok Miles, let me try to answer your question then.
If you consider the Quartile formula there are two parts to it - the first being the lower bound of the quartile class + a fractional amount of the class width. This fractional amount of the class width can only take on values between 0 and 1 (inclusive) and so the quartiles in their extreme cases can be either the lower bound or the upper bound of your class. So to answer your question - no - the quartile has to fall in the quartile class you identified (by definition the quartile class) but could reside at its extremities.
I hope this helps.
Kindest regards. Jonathan
how to allow advertisements on your video hehe?
What if estimated value (sigma(f)/N ) is equal to class frequency ? For example :
56/4=14 ??
You choose the first cumulative frequency (F) that exceeds 14. So with 56/4 = 14 equaling a cumulative frequency, you don't choose that, instead you choose the next one.
your accent is unsettling me , but i like what you taught , thanks !! cheers !!
There is an overlapping in interval
Thanks for help...
But did you minus Q1=L_(f/4_Cf)i÷f
But you didn't*
Thank you!!
can you please explain that Fq1-1 should be 14 but it becomes 4?
Hi Dalyn. Yes, of course I can. The key thing to remember is that 'Fq1-1' is a single value the '-1' is not telling us to substract 1. What it tells us is ' the cumulative frequency of the class before the quartile class.' You are correct 14 is the cumulative frequency of the quartile class, but we require the one before it, which is 4.
I hope this is somewhat helpful.
Jonathan
thank you so much. it helped a lot.
I still don't understand why he choose the 2nd class instead of the 1st class? Shouldn't the value of 13 got from the q1 belongs to the 1st class? Please help me. Tq
Hi Hazim. There are only 4 observations in the first class so the first quartile value could not possibly reside in that class. The first quartile value is the 13th observation. This must be in the second class as there are 10 observations in that class, and cumulatively there are 14. Regards. Jonathan
@@MathsAndStats ohh ya I really didn't realize about that. Thank you very much, Jonathan.
7:32 anyone observed the Cq1 = 13.... But i count to 14,, Please correct me if i am wrong.
Thank you very much for this it's really a great help😢😢😢💕
PS.Potamasmagalingpatomagturokesasateacher namin🤐
My bae IRENE pareho lang tayo bes hahaha
Amen tayo diyan
can i have that paper
Hi Soren. What particular paper are you referring to? Regards Jonathan.
is he scottish?
Irish.
Please use a filter over your mic
Your classes are overlapping.
What do you mean torteen, isn't it thirteen!!!
wtf you put so many ads confusing af