I believe the first product-to-sum identity is supposed to be SinASinB = 1/2 [Cos(A-B) -- Cos(A+B)] It would make sense that the 4 product-to-sum identities were 1 with SinASinB, 1 with CosACosB, 1 with SinACosB, and lastly, 1 with CosASinB.
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the first one is sin a sin b = 1/2 [cos(a-b)-cos(a+b)]
thanks so much,i was a bit confused
thank you i almost pulled out my hair
I was thinking 🤔what f-ck
thanks,why'd he take it in another form tho?
I believe the first product-to-sum identity is supposed to be SinASinB = 1/2 [Cos(A-B) -- Cos(A+B)] It would make sense that the 4 product-to-sum identities were 1 with SinASinB, 1 with CosACosB, 1 with SinACosB, and lastly, 1 with CosASinB.
I was thinking this same thing !
MR. Organic Chemistry Tutor, thank you for explaining and analyzing the Product to Sum Identities and Sum to Product Formulas.
This video helped me a lot, thank you bro
But in my book its :-
2 SinACosB=Sin(A+B)+Sin(A-B)
2CosA SinB=Sin (A+B)
Wow I love this it made me this particular particular place very well
is the first one 1/2( sin(u+v(+sen(u-v)) , and whats
is the same thing to have
sinU CosV and cosU Sen V
These ads are becoming ridiculous (Sitting through at least 6 ads through this video that would not let me skip)
man if there was only such a thing that bl*cked them
I know this comment was 9 months ago, but this is just useful for in general. If you skip all the way to end of the video and then let it end all the way, if you tbrn click replay on the video, the ads will go away
I had no ads though
use adblocker
what am i supposed to do when i have something of the form : sin(a)+sin(b)+sin(c)? how should i go about transforming it?
Thank you!
Hello! I noticed that some of the signs were opposites compared to the book and internet, does this affect the answer? Thank you!
Agreed, I was thinking about the same thing. Some of the signs are complete opposites compared to my book as well.
They have thrown everything on us in just 11th grade .This is insane 😳I'm dying 😭
fr
I'm in 9th grade doing this
0:24 it's wrong
Yeah.. should be
1/2[sin (A+B) sin (A-B)] right??
@@killing_gaming0973 pretty sure it's 1/2[sin(a+b)+sin(a-b)]
These are cool but how do you prove them
I got confused the moment I saw a correction
So which is which??
Am more confused than I came🙁🙁😒
I'm Khalid from Nigeria
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Was this video repeated?
Can I get a link
Of course no reply..
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