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You did a better job explaining how you arrived at K = 2 than my math textbook did. Thanks a (2.5 * 4) ^ 6!
You’re welcome. Glad it helped.
Thank you very much sir, i struggled a full day to find out how my professor arrived at k. This video made everything clear.
what happened to the e when u started taking derivatiges
Great explain this video help me a lot in my exam thanks you.
Thank you.
It was just what i needed ..thanks alot
You’re welcome.
what if it's( 2 s 0 (4x^2)+10 dx)?
Nice explanation I subbed!
Thank you. Glad it helped.
Okay why are you flipping the < sign when you do the error bound??
You mean at the end? It still equals the same thing, he just put the (n) on the other side of the equation. n never stopped being greater than what was on the other side.
Because sides are changed. If 3 < x , then x > 3, right?
wait so "K" is the largest value of the 2nd derivative?
yes on the interval
thansk buddy apperitae it
K was supposed to be one since its a decreasing function
what happened to the e when u started taking derivatives
You did a better job explaining how you arrived at K = 2 than my math textbook did. Thanks a (2.5 * 4) ^ 6!
You’re welcome. Glad it helped.
Thank you very much sir, i struggled a full day to find out how my professor arrived at k. This video made everything clear.
You’re welcome. Glad it helped.
what happened to the e when u started taking derivatiges
Great explain this video help me a lot in my exam thanks you.
Thank you.
It was just what i needed ..thanks alot
You’re welcome.
what if it's( 2 s 0 (4x^2)+10 dx)?
Nice explanation I subbed!
Thank you. Glad it helped.
Okay why are you flipping the < sign when you do the error bound??
You mean at the end? It still equals the same thing, he just put the (n) on the other side of the equation. n never stopped being greater than what was on the other side.
Because sides are changed. If 3 < x , then x > 3, right?
wait so "K" is the largest value of the 2nd derivative?
yes on the interval
thansk buddy apperitae it
You’re welcome.
K was supposed to be one since its a decreasing function
what happened to the e when u started taking derivatives