Theory of Equation | Solution Of Cubic Equation | Roots are in A.P.

[@gajendrapurohit]

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Dr.Gajendra Purohit

[@hiest4757]

Sir please solve the problem of biquadratic in GP it's very hard to get the value of r from the additive equation

[@Raven-c2x]

Sir can u suggest the books that based on theory of equation

[@study-junction02]

Thank you so much sir ❤

[@devanshuraj7181]

14:10
question correction
2p^3 - 3pq + r = 0

[@cofactor8127]

2nd questions me prove me 2p^3 hoga

[@siddamazingthought]

Yes

[@sourabxyk2690]

Thanks sir

[@pritydey9437]

Thanks sir... Your's video are very helpful for bsc students

[@freakgamer1313]

For jee mains also bro

[@namansharma2721]

Thank you sir! Great video!!

[@shekhar5063]

Bhut bhut dhnyabad sir mujhe aasani se samajh aa gya
Hriday se dhnyabad sir🙏

[@pranjalpandey1060]

Very brilliant explained 😍💯

[@bhargavpanchal85]

competitive exam ke liye bahut help mil rahi he.....thank u sir...

[@balasubramanian9016]

Most best of your way of teaching sir more helpful for all maths students

[@agent_op_is_live]

in the last problem the question should be 2p^3-3pq+r=0

[@momentcollegeboy]

It is helpful for me thanks for sharing knowledge

[@gmmathematicslove]

Many many thanks 🥰😘😘🙏🙏🙏🙏🙏 sir

[@jLiFe_CaptuRed]

Tq sir tomorrow my exam will be held .....hope ki acha jaaye mera exam

[@kavita2.o636]

sir thank you ........bht achha samjhate hai aap................

[@pachranga.gaming315]

Thanks 😊😊👍😊 sir provide this concept

[@mathematixswithns816]

It is 2p^3-3pq+r=0

[@sourav_-_7038]

sir kitna cool hoe ap, 30min ka lecture, 5 min mein samjha diye apppp.

[@Chandrabindu67]

10:48
Ans 2p³-3pq+r =0

[@shivamagarwal3046]

Symmetric function of roots par bana dijiye sir

[@Nitian_huzaifa]

Literally this lecture helps in even jee advanced 2023

[@ajeetpdsingh1099]

Theory of equation is perhaps extension of quadratic equations . notation of coefficient and roots may be kept distinct . Very good explanation .

[@ratnarai3231]

You are great sir 🙏🏻🙏🏻🙇‍♀️🙇‍♀️

[@rvyadav9834]

Sir u r the best ur videos helps us lot in corona time

[@dimplegupta1575]

Very nice teaching 👍🙏🙏😍sir

[@akr0786]

We all are also motivated sir

[@sanjaykr.m4389]

Sir , you are best teacher..

[@HimanshuSingh-ed7uo]

wow sir kya padhate hain aap maja aa gaya.

[@arbeenabilalpala7943]

Good speed , excellent explanation....

[@Avinashkumar-pz1kf]

Mai aapka fan ho gya sir

[@babansahani9286]

Sir plz apse anurodh h ki theory of equestions completely video upload kijiyga plz ap very well explain karte h thanku so much

[@Amit-hz3ew]

@@babansahani9286 yes sir

[@ExpertpramodPrajapati]

Best teachings sir jee

[@vvignesh-n1z]

super teaching sir

[@parikushwaha6634]

Sir aap bhot ache se explain krte hai ak chote se video me hi sare concept clear ho jate hai tanku so much sir

[@miningzone7180]

U r the best sir

[@anshikasharma1813]

thank you so much sir

[@ektasharma7049]

Thank u Sir!

[@PritiKumari-kj3oj]

Thanks sir 🙏🙏🌹🌹

[@swapanbiswas4630]

Find the equation whose roots are the roots of the equation x3+3x2-8x+1=0, each increased by 1

[@jLiFe_CaptuRed]

How to solve it bro

[@jLiFe_CaptuRed]

Any one tell. Us

[@Benglbankar87]

Tq sir for this video, very helpful

[@dimplegupta1575]

Thank you so much sir for helping us 🙏

[@ppriyansh2327]

Thanks sir
Really nice explanation

[@nitinhathiya5058]

Sir you are great

[@detacreations1999]

Thank u sir..... I understood theory of equation

[@kaushalbhardwaj1434]

Real analysis

[@prateekvijay7730]

Thank you sir..for your support ❤️❤️❤️❤️❤️

[@bazilaayoub6762]

Ty soo much sir

[@santoshpinjari7]

Very very helpful 🙏🙏❤️❤️

[@ypvlog6202]

Thank you so much sir
Thanks for doing wonderful work for students
It is really helps

[@patiramkajle1218]

Good job sir

[@honeybunny8462]

Outstanding

[@anubhav2251]

Thanks sir😁

[@rekhachoudhury1970]

Thank you sir aap bhut acha pdate ho
Sir koi koi sabd English ke smj me km aate he aap aek bar usko hindi me bol dete to smj me aa jata

[@soudippatra9775]

Make more videos on complex numbers

[@mohitxyz]

Sir real analysis par video banao sir, mere sir kahate hai ki real bahut kathin hai patanahi vo aisa kyo ka kahate hai ya ve hi sahi nahi jante . Sir real par ap 20-30 video banao vo bhi roj ak video .I am bsc 3rd year student . You are great sir .

[@DrVineetaNegiMaths]

I've uploaded many videos on real analysis.

[@Rp63888]

Nice class sir 🙏🙏🙏

[@skakramhossain3575]

Good lecture sir.

[@dharmendranath4267]

Tq sir please upload on vector space

[@vinetip5578]

Thanks sir for this content

[@Chandrashekhar-yt3ve]

Sir plss upload coordinate geometry

[@Soni__Aryan]

Sir in question no. 1st you should to write roots not root because that is a biquadratic equation so it will be definitely 4 roots.

[@pushparaj9203]

No one cares

[@bankingcontestentsatyam5794]

Sir.plz upload video on coincs and geometry.

[@SouravKumar-wt6zm]

Thank u sir

[@awakenedauras11]

Thanks a lot for the video! Please do some on abstract algebra!

[@ravisahani8708]

Thanks sir

[@ankitmishra399]

Sir plz give me link of integration using reduction formula
Area under the curve, length of the curve, volume and surface area of solids of revolution about axixs only
Plz sir bahut dhoonda
Mon ko exam ha please

[@mahamahimmotivational9846]

Love you sir

[@amarsinghsidhu7028]

Carry on sir

[@indsachin8302]

Sorry sir 8:17 actually 608 is not right sir
Sorry sir 🥺
Thank you
aap mere fav ❤️ teacher ho sir bas

[@learnwithkk5830]

Upload all Bsc video for 3D

[@Northeast-71]

Theory of Equation ka ak Book ka naam baataye- jesse boht help mile?

[@mohammedsameer3239]

Sir u r class is super.but next time plz send us pdf.what u have thought us.

[@hemendrasinghtanwar592]

Sir, there is mistake,
Product of all roots =-e/a but you have taken it e/a.
Please reply..

[@Chandrashekhar-yt3ve]

Bro alternately + and - come just like -b/a , c/a , -d/a , e/a

[@selvaraj4939]

Sir, one doubt, if one biquadratic equation is given and they asked to show that that the roots are in AP. How to solve like that problem sir.

[@anikaitdash6519]

Sir, that's twice of cube of p.

[@indsachin8302]

Hlw sir I'm a big fan of you ,
But sorry to say sir ki aapne 2nd Que. Me last me 2p³-3pq+r=0 prove kiya hai ,
But aapne Question me 2p² - 3pq +r =0 diya hai
Sir kya main. Question me 2p³ karlu

[@pallavichoudhary9559]

Thanku sir

[@wasimkabir9737]

Plz sir make more videos

[@sejalsharma6236]

Keep it sir

[@pachmowala9370]

Sir , last question me small mistake hai
prove 2p^2 kar na hai jabki ans me 2p^3 hai

[@sabaahmadturk3670]

sir plz aap white bord use kiya kre

[@deepaksuwalka4681]

SIR plzz abstract algebra

[@DrVineetaNegiMaths]

I've uploaded detailed videos on abstract algebra.

[@iamindian1000]

Sir the question was great but I literally spent half an hour doing the wrong question.
Please check the question before doing it

[@SHOHIDULISLAM-cl2nk]

1:16

[@sonamsingh3673]

Sir fst question me 4ac ko kaise kya kiye hai jo 608 aaya

[@omnipresentreader7791]

How to assume 2 roots?

[@dineshvalvi8410]

sir, Roots kaise nikale jate hai.

[@pranabkumarmandal2246]

sir apne last me galat se likh diya but video khubsurad

[@babansahani9286]

Plz video 30minite ka banaye plz

[@NibhaKumari-p5u]

1st question mei 40 *4 = 160

[@prabhaabhishek6260]

Gjb

[@YTSHORTS1701]

BIT'D wale like kre

[@educationpoint6480]

AP konse chowk use karte hai reply anyone

[@study-junction02]

Best quality chawk 😅

[@hemendrasinghtanwar592]

Sir aapne kha h ki roots AP me h.
Yha difference 3 aa rha h jabki d ki value to 3/2 aari h.

[@chetanashrimali8577]

Here in the roots we assumed difference is 2d not d so if we obtain d=3/2 then difference will be 2d= 3

[@chetanashrimali8577]

Here the roots we assumed has difference "2d" so if we get d=3/2 then 2d= 3 that occurs in solution

[@nagendrapolinagendrapoli8035]

Screen shot kosam side jargadi sir

[@rockeyrider7282]

5.46 may 4a kaha say Aya 4a=-2

[@deepaksuwalka4681]

Nd sir video thoda jld upload kre plzz

[@SWATISINGH-iv3mh]

Sir iske bad mechanics topics le lijiye please .it is very hard

[@Amit-hz3ew]

🙏

[@sarojrana6878]

❤️❤️❤️

[@Neha-ep6cv]

Kaha hai ye playlist