Complete method: how to find the week-day for any date?

[@mcmerry2846]

Here goes a much more difficult question...how to know what day is today if you don't have a calendar, a date a phone, etc...you just have your compass and a clear night.

[@crxz3yj3rm88]

Ask somone

[@pillow1557]

That's just impossible
U can't do it if ur not sure what day was yesterday and today,so u should just ask some1

[@sazidhasansafwan]

Today is "today" 😩

[@MukeshRajasekar]

Sun's position?

[@rock-afire-fan]

there are ancient structures erected to determine the position of the sun throughout the year for this purpose

[@there.are-no.handlesAVAILABLE.]

By far the best explanation and easiest to remember!!

[@priyaranadive8237]

Why did he divide 50 by 4?

[@MrPathakhemant]

Year part should always be previous year( completed), rest codes need to be revised accordingly ; date folling in Mar.-Dec. of Leap year:Total to be deducted by 1 to get correct day. I have programmed in QB64 and I get correct result for any year 0000 -4000, checked with Mobile & website.

[@inxeoz]

salute 🫡

[@thecalendarninja]

The fastest way (not easiest until after doing the required memorization) to do this is to prememorize all 100 year values from 00 to 99. Then I just add that to the century code and reduce mod7 and finally add that to a prememorized value for each of the possible 366 dates. For example, June 15, 2012 would simply be:
2+2+1=5, so Friday!
June 15 always has a value of 2 (prememorized)
2000's has a century code of 2
and,
year 12 always has a value of 1 (prememorized)
2+2+1=5, Friday!
Anytime leapyear happens just subtract one from the answer for January or February only, all other months stay the same!
I calculate any day of the week using my method in less than a second, almost instantly to 2 seconds tops if I'm thinking a bit. I do both the Julian and Gregorian calendars in both AD and BC infinitely into the past or the future.I do other cool tricks that aren't heard of very often, for example since this calendar math can be viewed as just a simple addition problem, we can also solve for a missing value using subtraction! For example, if we already know the day of the week to be Friday for example, we can solve for a possible month/months or even a date from 1 to 31 or even a possible year or century.
Example: Which month or months did Friday the 13th fall on in 1899?
1899 was a Tuesday year (-2+4=2) or (5-3=2). So, Tuesday was the 10th since 3 days later was Friday the 13th.
So, 2+13+x=5 (Friday)
x=4 because 15+(-10)=5
-10+14=4
Mod7 arithmetic
Only January and October had a month code of 4 😁. So it only happened twice that year, in January and in October. Also we can say more intuitively that since 1899 was a Tuesday year, and Friday being 3 days later, which month/months had the Doomsday of 3,10,17,24,31? and obviously that is only January and October.
If the question changed to what were all of the Fridays in January and October for example in 1899?
We can say "the 6th, 13th, 20th, and 27th"
If someone were to instead ask for example on Friday the 13th from 1883 to 1900 what year/years did that happen?
We can say "only in 1893 and 1899"
In this situation we just needed to find the missing year code of (4 or -3) and only 93 and 99 have that year code in that date range. Likewise, we could have instead solved for the century 😉 also if already given a year.

[@navlikesdesign]

how is that the easiest * cries *

[@Idea_Xpress]

Could you please send a link to a website with all the numbers that have to be memorized
?

[@awmuzahid3517]

Don't come to distrub us if you are a legend than explain it and come for advice 😏

[@AzedoTranslated]

give us the numbers to memorise

[@thecalendarninja]

@@navlikesdesign I apologize, it's not necessarily easy until after all the necessary memorization is done. It's the fastest way though for sure, which is the payoff for doing the memorization required to use my method.

[@1mrpowerup]

best explanation on youtube thanks for the formula bro i learned within 30 minutes 🙏🏽

[@JustJoe-yh5dw]

Excellent presentation. One thing to add concerning leap years which need to be determined when the month is either January or February. Leap years are those years that are equally divisible by 4 such a 2000, 2004, 2008, 20012 … and so on. There is 1 exception when determining a leap year which is: years that end in 00 are ONLY leap years if the year is equally divisible by 400. Therefore years 1700, 1800, and 1900 were NOT leap years because they are NOT equally divisible by 400. The year 2000 WAS a leap year because it is equally divisible by 400. Going forward, years 2100, 2200, and 2300 will NOT be leap years because they are NOT equally divisible by 400 while 2400 WILL BE a leap year. Remember, all of the above only apply to years ending in 00.

[@cpfigueiredo]

The date 5 Feb 2000 results in a final remainder of zero: (5 + 3 + 6 + 0 + 0) / 7 = 2 (with remainder 0). This date fits in the exception of Jan or Feb in a leap year. Hence I should subtract 1 from the remainder, but in this case I would get -1.
I suppose I should "wrap" this result such as -1 + 7 = 6 ? I confirmed that this date was a Saturday!

[@cpfigueiredo]

@Anaya Ch It has worked for me. I even coded this method in a microcontroller. The only issue I had with the method was the one I mentioned in the previous comment. If it is not working for you, maybe you are missing some little detail.

[@eduardoxenofonte4004]

yes, as you add 7 just as you can subtract 7

[@shameermandodichalil7696]

@@cpfigueiredonot working for 22\02\1979

[@No-hw7mb]

@@shameermandodichalil7696 22+3+0+79+19 =123/7 remainder 4 which is Thursday

[@NEENASPSCPOINTS]

Here for subtracting purpose, 0 should be taken as 7. Then 7-1=6 i.e. Saturday.

[@user-en9il9bu9j]

in 1582 when the gragorian callender was started .
10 days was emitted .
but in 1582 years; surplus days
become 12 days.
plz explain this gap .

[@simranmittal4815]

Thank you so much, this video was very helpful 😍

[@eforexplorer8900]

Thank you👍 stay connected

[@waqasmansoor7657]

extremely amazing..I understoood every thing just in one this video

[@mohitvashishth6056]

Amazing, loved the method.

[@joepiacente2311]

There are so many explaining the formula, This is the only one that no questions have to be answered
Thank you very much! You made it so simple to understand. Do you also teach Vedic math?

[@eforexplorer8900]

Not vedic math

[@manojk1849]

@@eforexplorer8900 if i calcuate for 24 oct 2028 as it was leap year you told to subtract 1 from givwn answer got wrong

[@manojk1849]

got monday instead of tuesday

[@piyaburman634]

​@@manojk1849
Is oct not Jan or Feb , so you don't have to subtract...and if you don't subtract you get Tuesday which is correct.

[@claudiobuttazzo4513]

​@@manojk1849 yet not!! You need to subtract *-1* only if you want to try to find the day of week from JANUARY and FEBRUARY about every LEAP YEAR. Example for your date *24 Oct 2028* even if is a leap year, you don't need to subtract - 1. If the date were 16 February 2028 then you need to SUBTRACT -1. So the day of week from 24 Oct 2028 will be : 7+0+6+24+0= 37 = 37:7= *2 remainder* = Tuesday and NOT how you thought before. 💪🤙👍

[@s1lly_sunny]

My grandpa somehow knows how to do this so im learning this to be able to bond with him lol since we dont really have much to talk about together 😅

[@saikatgigabyte]

the easiest method loved it bro❤

[@masroorahmad3510]

Why is it not working for 31st OCT 1957?????

[@CARDER_BOLTE_]

No bro it's work i can explain you
=31+0+0+57+14=102
So 102/7=4 and according to week chart the 4 is Thursday ✅

[@Mhike177]

The name of that mathematician you’re talking about is John H. Conway. He figured out the algorithm to finding out the day for a past or future date by just using one hand.
Btw, I checked my birthdays with 3 leap years (2024, 2028, 2044) and no subtractions were necessary. They were all correct with just regular calculation. Perhaps subtraction isn’t necessary.

[@devisnomiac212]

I calculated
For a leap year
Subtraction is only required for January and February
Meaning your birthday is not in those two months
Do clarify please.

[@hamdikorkmaz5497]

Please calculate it for 7 march 2016 . It gives sunday but it has to be monday

[@eforexplorer8900]

Do properly

[@johnsonantony3490]

It's just Monday 7+3+6+16+4=36divide by 7 we got balance 1 and as per chart it's Monday got it.

[@inayathinayath4506]

2016 is a leap year so subtract answer with 01 then u will get final answer as 0 so it's sunday

[@NEENASPSCPOINTS]

@@inayathinayath4506 Subtraction is applicable only for Jan and Feb of leap year. For March, no subtraction and the day is Monday.

[@rexcavalier]

This formula is for Gregorian dates only, I think.

[@aviation.7]

Why did you divide 50 by 4 and the total with 7

[@johnsonantony3490]

Their is hidden the formulae ofcourse.7 means it's one week yes I think it's because of we have calculated it for the year having 28 days for February month it is my guess.for leap year calculation will differ.

[@shivatejavangala7023]

For every leap year or only for your example we have to minus 1

[@eforexplorer8900]

@@shivatejavangala7023 😄

[@AbdulMannan-mz8wd]

It is kind of hard to learn the codes but when you do it is so easy this is very helpful

[@davecorrea2686]

I'm surprised how well this worked for every-other date thank you so much for this method

[@jamshiriyas5395]

Thank you boss 👍🏻, tomorrow i have a scholarship exam for CUET tution, i hope this can help me tomorrow 👍🏻

[@eforexplorer8900]

Best of luck for your exam.

[@nipunkarthikeyan1008]

Thanks for this video. Just saying you missed the letter p in the word explorer at the starting of the video

[@eforexplorer8900]

Yes that's right.

[@vijayakumari9055]

Ok now 1947 August is friday but if we calculate according to this formula 15+2+0+47+16=80 and 80÷7 we get remainder as 3 but it is showing it as Wednesday so it is wrong

[@eforexplorer8900]

Wrong calculation

[@darshb8031]

It should be 15 + 2 + 0 + 47 +11 = 75 so remainder is 5 which is Friday correct ans

[@riya2744]

How can we find the day if the year won't be divisible by 4??

[@JustJoe-yh5dw]

Every year is divisible by 4. If the year is less than 4 the quotient is 0 and remainder is the year.
If the year is 00 00/4 = quotient of 0 and remainder of 0
If the year is 01 01/4 = quotient of 0 and remainder of 1
If the year is 02 02/4 = quotient of 0 and remainder of 2
If the year is 03 03/4 = quotient of 0 and remainder of 3

[@aidanlynch5995]

i can’t get this to work for at least the battle of hastings ie 14 october 1066 if somebody could help would be appreciated

[@raginijha7610]

15th August 1956 is leap year and this formula does not give right answer which is Wednesday.

[@JustJoe-yh5dw]

That’s because the Julian calendar was used back then. The only difference between the old Julian calendar and the current Gregorian calendar is that under the old Julian calendar every year ending in 00 was a leap year while under the current Gregorian calendar, years ending in 00 are ONLY leap years if they are equally divisible by 400. The years 1800 and 1900 were not leap years while 2000 was a leap year.
October 14, 1066 ( Julian calendar ) was a Saturday.

[@jaswindersingh5248]

easy way to learn 😊😊thnku brdr ❤

[@adveshdarvekar7733]

this is good but will take a long time to do it mentally

[@sumanpawar402]

Sir your notes are so much helpful can u plz make all reasoning topics

[@eforexplorer8900]

Yes, I have plan to do that.

[@navlikesdesign]

THANK YOU SO MUCH THIS VIDEO IS SO UNDERRATED

[@ArvindKumar-kd2je]

28 Mar 3136 ( being a leap year ) result should be Sat, but with pattern, it's Friday . What may be wrong?

[@dev_kame425]

Only Jan and Feb -1

[@duggirambabu7792]

28 + 3 + 0 + 31 + 7 = 69
Remainder of (69/7) = 6 = *Saturday*

[@archishmanbera4403]

Don't you think that the quotient spelling is written wrong

[@sixihili1956]

best fastest method I think all others took a lot of calculations

[@Atax_gaming]

If the year is like 2003, for the quotient we need to divide 03 by 4 which is kinda impossible. How to do with this? Can you please please help.

[@eforexplorer8900]

@@Atax_gaming quotient 0 coming

[@Incepter.]

Hmmm, interesting that you can find the week-day for any date by just calculating it in your mind...cool

[@SahidKhan-lg6mn]

Thank you so much sir ❤ it's very helpful for me 🎉😢

[@shen3509]

How would you know if it's a leap year?

[@eforexplorer8900]

Divide by 400 if last two digits are zero otherwise divide by 4

[@sidhumoosewala4583]

Sir kitni badi problem solv krdi Apne thankyu sir

[@dfl5015]

NICE....Like it !!!!

[@alexandre.111]

According to my calculations, 1st of April 2004, we get 1+6+6+04+1 = 18
Then, from 18/7 we obtain a rest of 4 as our final clue...
Once 2004 was a leap year, I subtracted 1, so 4-1= 3 (wednesday)
However, 1/4/2004, was on a Thursday!
Where's the mistake here? Do we really need to subtract 1 on leap years??

[@eforexplorer8900]

For Jan / Feb month only

[@mayureshpatil2468]

thanks bro best video on this topic , able to solve all questions 👍👍👍

[@Captain_OM_]

for me... any year perfectly divided by 4 is a leap year.

[@lennoxfukala5434]

not always, end of century years have to be divisible by 400, so 1800 isnt a leap year

[@MTBwithjamie]

I’ve watched this over 5 times and have never gotten it to work what am I doing wrong

[@advaykabade]

Maybe you could try solving the questions first than look at the video then see where you went wrong?

[@user-eu3rm6ul5k]

It is not well as I am trying to me

[@souvikbag8040]

What is logic behind divide by 4 and 7?

[@eforexplorer8900]

The derivation needs a separate video

[@thegem597]

Nice one. Subscribed. Waiting for more maths tricks. 👌👌

[@incomputeraccountingwithma482]

You shotcut value of calculation 😊

[@manikandans7303]

For 5th Oct 2016 I got Tuesday but the day was really Wednesday
Plz solve this

[@JustJoe-yh5dw]

5+0+6+16+4=31 31/7 = 4 with a remainder of 3 which is a Wednesday

[@manikandans7303]

@@JustJoe-yh5dw but it is leap yr ,so we have to subtract 1 from 3 and we get 2 which is Tuesday
But the answer is Wednesday how?

[@JustJoe-yh5dw]

@@manikandans7303 You only subtract 1 if the date is a leap year AND the month is either January or February. You DO NOT subtract 1 for leap years when the months are March through December.

[@manikandans7303]

@@JustJoe-yh5dw why sir or it is rule ah sir ?

[@JustJoe-yh5dw]

@@manikandans7303 This method of calculating the day of the week for any date is based on 365 days. When a leap year happens, an extra day is added at the end of February making it a 366 day year. An adjustment of subtracting 1 needs to be made for all the days on and before the extra day that is added at the end of February.

[@Orion225]

Since century code for 1900 is 0. Should I add the zero in the equation?

[@lennoxfukala5434]

adding zero doesn’t do anything

[@Orion225]

Yeah 😂

[@lennoxfukala5434]

@@Orion225 so it wouldn’t matter if you add it or not

[@alliswell5947]

How I divide 2002 last digit 02, with 4?

[@eforexplorer8900]

Here quotient 0.

[@shashketh]

So my birthday is on Monday in the year 2050!! He used my birthday date btw!! ;)

[@VDSShortFilms135]

U Have Explained One Exception At Last For Leap Year, It Is Applicable For Only Jan/Feb Months Aaa Bro...🤔

[@zakariazraalk9905]

Whats the logic behind this algorithm , how does it work ?

[@shekinajoseph]

It's not working for me, because the day for jan 3rd 2007 was Wednesday, but when i follow your method it shows Saturday
Also for leap year 3rd jan 2008 i got 0 as remainder what i have to do when i get zero, should i subtract zero by 1

[@eforexplorer8900]

Follow the same method as shown with proper calculation

[@shekinajoseph]

You didn't tell what to do when it comes zero remainder for leap year in the video

[@eforexplorer8900]

@@shekinajoseph 0-1=6

[@shekinajoseph]

@@eforexplorer8900 OK but the correct answer is Thursday = 4, anyways thank you

[@eforexplorer8900]

@@shekinajoseph yes if you apply this method you will always get right answer, thank you.

[@priyaranadive8237]

Why did you divide 50 by 4?

[@eforexplorer8900]

@@priyaranadive8237 i will make separate video for that i guess

[@palaeoloxodonantiquus4880]

great video

[@laurieguard0]

Doesn't work for me...
12th March 1856 (leap year)
12 + 3 + 2 + 56 + 12 = 85
85 / 7 gives remainder 1
Which would be Monday
But it is actually a Wednesday when looking it up...

[@JustJoe-yh5dw]

Your match is wrong. When you divide 56 by 4 you get 14 not 12 . So, 12+3+56+14=87
87 / 7 gives a remainder of 3 which is a Wednesday

[@anshusharma3133]

0:43 WdHd (weekday hidden in date)... 0:53... 3 charts - week (sat 0 sunn 6), month(033-(aay...chhay 6maii 1 juu two 2 ). 612- 625(jul6 A had 2 legs so Aug=2 Sept S=5). 035(oct=0 looks like o.). 1:00 wkcht....1:15 month chart how to ratta see...1:35 infinite cent chat_6024_6024 ( rmbrr prant cent THISS cent== 6. 20th cent 0 all before 20c is 24"" TOO FARRRRr to b Rmbrrd TOO FARRRRR). 2:34... 6 steps see for fast, 4 quotient & 7 remainder ans @ last .

[@atrueindian4033]

In leap year it is only for Jan feb or any month. Abe jaldi bta

[@eforexplorer8900]

Are re re train miss hoi gawa ka, it's for jan and feb only

[@Asmr_food_shorts_]

Its not working for 26th jan 1960 ....as you said for leap years you should substract 1 from the ans ....but its cmg wrong

[@JustJoe-yh5dw]

26 Jan 1960 is a Tuesday 26+0+0+60+15=101 101/7=remainder of 3 Subtract 1 for leap year and month of January. 3-1=2 2 is a Tuesday

[@sriharikandimalla2669]

Sir in leap year modification, shall we consider all months or it is only January and February

[@eforexplorer8900]

@@sriharikandimalla2669 only jan/feb

[@eforexplorer8900]

Nd leap year rule always same

[@jojoii7490]

And if you have the first 4 years of a century, you don't Devise by 4, you just add them EG.
19.8.2001
19+2+6+1+1=29÷7=4(leftover 0)=sunday

[@DGEL03]

Is the exception only for leap years with date in january or february?

[@eforexplorer8900]

Yes

[@Ignitequotes]

Why to divide by 4

[@Minutehyderabad]

Thank You ❤

[@mrmath729]

Thank you very much for your video. Very Useful

[@keerthinathpremkumar5270]

Thank you very helpful please make more of these🙏🙏🙏👍👍👍🎉🎉🎉

[@eforexplorer8900]

Thank you👍 stay connected

[@theonexx762]

​@@eforexplorer8900 I have a question, why does 6th of July 1944 (Thursday) not work. Only when I don't count the -1 from the total of 4. But that doesn't make sense, because its a leap year and I should technically deduct it.

[@eforexplorer8900]

@@theonexx762if the month is Jan or Feb then only you should deduct...🙏

[@theonexx762]

@@eforexplorer8900 got it, thank you so much 🙏🏻

[@amarnathpatel6351]

How do we know Whether It was a Leap Year Or Not ? Is There any Hypothesis For This ?

[@eforexplorer8900]

Divide the year by 4, if no remainder comes it's leap year. But for century like 2000, 1900, 2100 etc should be divided by 400.

[@user-en9il9bu9j]

where come the sentuary code 0 -2-4-6 ..
what is its explanation ?

[@pradeepstha4735]

didn't work for 28 feb 2016, by this method answer comes 1 >> monday but the actual week day is SUNDAY

[@user-fg6yi8mf8o]

It was the leap year so U need to minus 1 as per taught 😊

[@valaajay9730]

If year is 2003 how to find leap years by dividing with 4

[@eforexplorer8900]

Not divisible by 4 so it's not leap year

[@muhammadrehman6146]

Best explanation to remember

[@passangdroima8996]

Why you multiplied by 4 and 7 only why not other number

[@marcogazaneo]

I need help, what am i doing wrong: May 10th 1990: 10+1+0+90+11=112/7=16... What am i doing wrong here? Thanks in advance!

[@eforexplorer8900]

Check calculation

[@safrinsultana9213]

What to do in leap year when remainder is zero?

[@eforexplorer8900]

Final clue will be 0-1= 6 (Saturday)

[@AustinBeasley0428]

What if its a leap year and you have 0 left what do you do

[@eforexplorer8900]

If month is Jan/Feb then substract... 0-1=6

[@sureshlingayath]

And also find 25 Dec 1992
Friday is crrct but leap year 1992...
-1 is the 5-1=4 Thursday?is it (leap)only works Jan/Feb?

[@eforexplorer8900]

Yes, exception is for Jan and Feb only.

[@jyotsnanagababy8044]

Explanation is very good

[@avidrationalist7281]

How did you assign code number 2, 0, 6 etc to the respective years...?????? How one can think which code comes before which year????

[@claudiobuttazzo4513]

That depends of century years. Still. Our century from 2000 till 2099 have the *CODE 6* , the last CENTURY from 1900 to 1999 had *CODE 0* , beetwen 1800-1899 had the *CODE 2* and beetwen 1700-1799 had the *CODE 4* . So every 4 century will have the same code, for example 1700-1799 = 2100-2199 = *code 4* !! About all of those CODES have a reason. 🤙💪🇪🇸🇮🇹🇨🇭🇦🇷

[@azumi-hb4iv]

but how about in december 25, 2000

[@manas069]

Tell me 2 things
Why did you divided 50 by 4
And by did you divided 85 by 7

[@duggirambabu7792]

1). To find how many leap years in a given year.
2). Week has 7 days.

[@eclipticpath]

@@duggirambabu7792 Why do you have to find out the amount of leap years?

[@duggirambabu7792]

@@eclipticpath
Ordinary year has 365 days and leap year has 366 days.
*If we don't find leap years, we will get wrong answer.*
Ex: In 5 years
1st year is an ordinary year.
2nd year is an ordinary year.
3rd year is an ordinary year.
4th year is a leap year.
5th year is an ordinary year.
Therefore in 5 years, 4 ordinary years and 1 leap year.
Total days = 4 * 365 + 1 * 366 = 1826 days.

[@aishwaryaminuku8274]

tq u sir

[@maynardtrendle820]

Great- thanks!

[@rajagrawal8180]

2nd oct 2020 leap year weekday goes wrong. Please try it

[@eforexplorer8900]

Leap year but not Jan/Feb

[@varun6098]

amazing video thanku so much

[@navya23723]

Thank you explorer!

[@user-zh1nx3gq8h]

Thankyou sir

[@awmuzahid3517]

2000 is leap year but if we minus 1 from the date of 3march 2000 calculation gonna wrong again 12 January if we don't subtract 1 answer gona wrong and again 3jun 2000 need to subtract 1.... So it's confusing sir

[@JustJoe-yh5dw]

If the date is a leap year AND the month is either January or February then you subtract 1. DO NOT SUBTRACT 1 for any of the other months ( March to December ).

[@newbiecompany9252]

13 June 2730 can you tell me about it I had tried to calculate according to the method described by you but it fails

[@eforexplorer8900]

Check calculation

[@nandipraveen1680]

2/7/2003 not getting please make clearing of my doubt

[@JustJoe-yh5dw]

2 July 2003 was a Wednesday. 2+6+6+03+03/4 = 2+6+6+3+0=17 17/7=remainder of 4 or Wednesday
When you divide the year by 4 use only the answer or quotient, do not use the remainder so 03/4=0

[@JustJoe-yh5dw]

Correction: 17/7=remainder of 3 which is a Wednesday

[@arianjaman917]

​@@JustJoe-yh5dwPlz solve for 6 October 2005

[@JustJoe-yh5dw]

@@arianjaman917 6+0+6+5+1=18 18/7 = remainder of 4 = Thursday

[@zakdaman345-gaming6]

Hey E for EXPLORER ! how do you find the quotient? and what it means?

[@ahtoahkeshin7306]

The quotient is the result of a division problem. For example, in the video - 50:4 = 12,5, we ignore the decimal point and write 12 only. We can do this by using the remainder method - it’s 12 with the remainder of 2, so we ignore the remainder and write 12.

[@notturkeysalt1208]

@@ahtoahkeshin7306 but how do we decide what number to use for it. Is it always a 4 or?

[@duggirambabu7792]

4) 50 (12 This is quotient
- 4
------------
10
- 8
------------
2 This is remainder
------------
*Quotient of (50/4) = 12*
Remainder of (50/4) = 2

[@MTBwithjamie]

What do you do with let’s say 8.7 or 8.8 or 8.9?

[@saitanujamakala765]

What if it is not jan or feb in a leap year.. how do we calculate then for march - dec in a leap year?

[@eforexplorer8900]

Then normal calculation

[@venkeysravani5922]

In the century chart u told a basic thing 2064,2064 but here u take 99 years difference so if suppose 1300-1399 is 2 or 0 or 4...?

[@eforexplorer8900]

This method is valid for any date after 1582 AD

[@daniel-xt3tp]

I tried doing 15 jun 2003 it said it was a Sunday I got thur.

[@eforexplorer8900]

@@daniel-xt3tp check ur calculation

[@daniel-xt3tp]

@@eforexplorer8900 oops added wrong. Thanks! Also, if I have a leap year, like say July 5th 2077, is it normal?

[@eforexplorer8900]

@@daniel-xt3tp exception is for Jan or Feb not for July, btw 2077 is not a leap year.

[@daniel-xt3tp]

@@eforexplorer8900 thanks! I meant 2076

[@oZqdiac]

Jan 1 2100
1+0+4+0+0=5
5/7=0 remainder 5
5-1=4 (since 2100 is a leap year)
But Google results show Friday
Edit: Never mind I found my answer in another comment

[@apauncle8357]

Sir how to work in 2004, it is always decrease in 1 to get the right day..can you please help me.. 31/Dec/2004, total is 47, when divided by 7 remainder is 5-1= 4 (leap year), but actually it should be 5 to get the right day....

[@eforexplorer8900]

Substract 1 only for jan/feb of leap year not for Dec as said in the video.

[@apauncle8357]

@@eforexplorer8900 thank you sir ji

[@FlowerBFDI2763]

I did January 1 0001 and got Saturday

[@biranchinarayanmohapatra4491]

Why after 1582?

[@eforexplorer8900]

Gregorian calendar was started since 1582.