At 13:13 by mistake i wrote that sum of Fourier series at x=0 is (1+1)/2=1. There is a mistake, here left hand limit is -1 and right hand limit 1 so Average will be 0.
Yes...technically they should... If not, then other way of asking this is - find cosine series for the given function... Or Find sine series for the given function.. Then they will also fall under the category of half range..
@@DrMathaholic ohkk Thank youu very much Sir...tmrw we have our UVC endsem...aapka aashirwaad saath rahe😊🙏🏻also Happy teachers day sir...couldnt wish yesterday😅...UVC aapke wajah se nikalne wala hai🙏🏻Thanks a lottt U r a saviour🙏🏻
At 13:13 by mistake i wrote that sum of Fourier series at x=0 is (1+1)/2=1. There is a mistake, here left hand limit is -1 and right hand limit 1 so Average will be 0.
At 13:13 by mistake i wrote that sum of Fourier series at x=0 is (1+1)/2=1. There is a mistake, here left hand limit is -1 and right hand limit 1 so Average will be 0.
At discontinuity the mid point of the Fourier function at the point of discontinuity is the sum of Fourier series at a discontinuity.
Hello sir , i have completed my syllabus from you , this playlist is great , have watched almost all 69 videos. You are a great teacher
Good👏👏 all the best for exams
Thank you 😊
Now, also, solve tutorial problems on ur own.. your score will b v.good
Great video sir
Sir please make a playlist on Fourier integrals ❤
Ok, noted..hopefully soon 🙂
Great video sir💥💥. Can you take some more problems on half range concept??
Okay. I will make a video on half range in a day or two.
Made one video on half range.. hope this will help you.
Here is the link-
th-cam.com/video/omo51WEuqkE/w-d-xo.html
@@DrMathaholic thank you sir
Sir at 3:25 LHL is 0 and RHL is 1 at x=0 so avg must be 1/2 right...i mean should we check the values from graph or should we do it using formula?
Yes you are right..average is 1/2.. thanks for pointing it out..you can approach by whichever way is easier for you
@@DrMathaholic Ohkk..Thank you sir🙏🏻🙌🏻
@@THUNDER-kw3wq 😊👍
Sir can you make videos on fourier transform thank you
I have made on fourier series..
Fourier transforms, hopefully soon :)
sir this playlist does not have videos for fourier integrals sect 11.7 please help
@adarsh5997 yes, I have not recorded Fourier integrals yet..
Sir at 6:00 no need to find bn na as f(x) is even function ?
See the graph for the function. Is it even?😀 We have defined from 0 to 1 and not -1 to 1.
see graph which i drew before writing coefficients.
@@DrMathaholic oh yes sir I was focusing on f(x)=f(-x) instead of intervals mentioned
@@tomtac820 happens 😊
sir at 5:39 why is the limit of integration 0 to 1 and not -L to L
Here the function is not defined from -1 to 1. It is defined over 0 to 1 and we have to fourier series of given function over 0
@@DrMathaholic thank you sir
@@sarthakpawar9303 welcome 😊
Sir will it be mentioned in the ques that we have to solve it by half range expansion?
Yes...technically they should...
If not, then other way of asking this is - find cosine series for the given function...
Or
Find sine series for the given function..
Then they will also fall under the category of half range..
@@DrMathaholic ohkk Thank youu very much Sir...tmrw we have our UVC endsem...aapka aashirwaad saath rahe😊🙏🏻also Happy teachers day sir...couldnt wish yesterday😅...UVC aapke wajah se nikalne wala hai🙏🏻Thanks a lottt U r a saviour🙏🏻
@@THUNDER-kw3wq thank you for your wishes..
Hahahaha..koi na, acha jaaega..mera aadhirwad hai tum logo k sath😉
@@DrMathaholic 😂😊🙏🏻aced t1 t2 because of ur videos i hope its the same tmrw
@@THUNDER-kw3wq oh great..Happy to hear that..Kal b Acha jaaega..
At x=0, in sine series how we get that please explain it.
At 13:13 by mistake i wrote that sum of Fourier series at x=0 is (1+1)/2=1. There is a mistake, here left hand limit is -1 and right hand limit 1 so Average will be 0.