At 16:29 Correct solution is given below lim (x -> 3) (x^4 - 81) / (2x^2 - 5x - 3) 1. Find the derivatives of the numerator and denominator: f(x) = x^4 - 81 g(x) = 2x^2 - 5x - 3 f'(x) = 4x^3 g'(x) = 4x - 5 2. Evaluate the limit of the ratio of the derivatives: lim (x -> 3) (f'(x) / g'(x)) = 108 / 7 3. If the limit of the ratio exists and is finite, then the original limit is the same: lim (x -> 3) (x^4 - 81) / (2x^2 - 5x - 3) = 108 / 7 Therefore, lim (x -> 3) (x^4 - 81) / (2x^2 - 5x - 3) = 108 / 7.
Hi sir, in 32:21 there is no need to change the question, all we have to do is rearrange we can take (x+1) as y and add +1 and - 1 to the denominator such that it would look as so, [(x+1)^5 -1]/[(x+1)-1] and after using the formula (x^n-a^n)/(x-a) = na^(n-1) and we would eventually get the answer as 5 [pls correct me if I'm wrong]
Sir at 17:57 u wrote that 0/0 is 0 , which is wrong ❌ since Enything divided by 0 is not defined till now... I don't think I'll get attention, but still m writing this for my self satisfaction 😂
53:56 sir answer is wrong, it asked "For what value does limit exist" pls see it and upload a shorts or something on it,giving correct answer, pls sirr
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53:46 Sir in this ques, we have to find the value at which limit exist But you have not found the values rather you solve it normally plz pay attention towards this ques But at the end your explanation are fabulous and amazing 😊😊
Bhai Har jagah exist karega limit except zero kyuki tum koi aur no. Lo let 1 to x→1+ ya x→1- dono me ek hi answer aaega ek hi value diya hai na Ise questions me bas intervals change jaha hote hai wahi pe check kiya jata hai
You are the teacher for making the future of today's children that are in 11 standard you are the teacher not for destroy the future of today's children
24:40 Sir prerajulisation means that it is a mental purification process that involves training a subject to lose all fears of the mind and body Farhan nitrate is Fh(NO3)2 Sir these words have meaning. In the movie they just show like this but in real they are words
Nhi abhi jo sir ne peeche slide mai 3rd wala cos ka formula lagaya tha 1-cosx/x = 0 woh put Kara hai yaha pe isliye yeh final answer hai aur 0/0 form nhi bani isme answer sirf 0 hai
There may be some calculative errors.. ofcourse we can correct it during practicing the question...But the simplicity with which sir taught the chapter .... Awesome..... Concepts CLEAR.....Great lecture 😊😊😊😊😊😊🎉❤😊😊😊
th-cam.com/video/pDa6IMoo6dE/w-d-xo.htmlsi=OJwFiEogOLM-oRqe
Link of derivative topic
Thanks sir
sir aap accha padhate ho, par bhout blind mistake bhe karte ho aap
kahan ki mistake@@pragya-l6d
@@pragya-l6d kaha he mistake 😅😅
Mujhe
mistake found in x⁴-81/2x²-5x-3
Sir in x+3
3+3 = 6 not 9
Haa bhai sahi bola
Yesss bro I also noticed this problem instantly
Hi bro
H the correct answer is 108/7 16:26
No it is 16:45
16:28 Sir, apne 18×9 kar diye he, par question me toh 18×6 hona chahiye
(x²+9) (x+3)
(3²+9) (3+3)
(9+9) (6) = 108
Toh uska answer *108/7* hona chahiye
yes sir he is right
Right bro
right brother
Correct
👍
16:26 Dear Ushank sir with respect
Sir,x+3=6 hoga so final answer will be 108/7 not 162/7 . Please pay attention
Thankyou Sir
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Thanks and plz share
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Scrolling comments for answer like this checking I am wrong 😂😂 or not
You teaching style is very nice 👍.VOTE for derivatives 😅
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At 16:29 Correct solution is given below lim (x -> 3) (x^4 - 81) / (2x^2 - 5x - 3)
1. Find the derivatives of the numerator and denominator:
f(x) = x^4 - 81
g(x) = 2x^2 - 5x - 3
f'(x) = 4x^3
g'(x) = 4x - 5
2. Evaluate the limit of the ratio of the derivatives:
lim (x -> 3) (f'(x) / g'(x)) = 108 / 7
3. If the limit of the ratio exists and is finite, then the original limit is the same:
lim (x -> 3) (x^4 - 81) / (2x^2 - 5x - 3) = 108 / 7
Therefore, lim (x -> 3) (x^4 - 81) / (2x^2 - 5x - 3) = 108 / 7.
both ways are correct
@@ConceptHelper no
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Kisne 11th class mai limits and derivatives nhi padha tha jo aab vapas aaya h 12th mai ye video dekhne😂😂
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Hi sir, in 32:21 there is no need to change the question, all we have to do is rearrange we can take (x+1) as y and add +1 and - 1 to the denominator such that it would look as so,
[(x+1)^5 -1]/[(x+1)-1] and after using the formula (x^n-a^n)/(x-a) = na^(n-1) and we would eventually get the answer as 5 [pls correct me if I'm wrong]
16:20 Sir 3+3=6 hoga and answer 108/7 ayega [KOI NI HOJATA HAI]
Correct ✅
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Sir you look like Faf-Du Plessis 😂
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Bhai kitna IPL dekhoge😂😂😂
lim
x tends to faf du plessis
Ha bhaiya sach mei ekdum faf du plesis leg rehe he sir
Sir at 17:57 u wrote that 0/0 is 0 , which is wrong ❌ since Enything divided by 0 is not defined till now...
I don't think I'll get attention, but still m writing this for my self satisfaction 😂
Enything nahi anything hota h 🚬sir ko sikhane se phele khud toh seekhle 🤣
Exam se 1 ghanta pehle dekh raha hu 😂😂
Me too
To padh le comment kr raha hai😂😂
Waa bro
Video hi 1 ghante ki hai
53:56 sir answer is wrong, it asked "For what value does limit exist" pls see it and upload a shorts or something on it,giving correct answer, pls sirr
Es video ke mistakes
16:28
53:56
26:04
26:51 2(1+1)-1=3
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53:46 Sir in this ques, we have to find the value at which limit exist
But you have not found the values rather you solve it normally plz pay attention towards this ques
But at the end your explanation are fabulous and amazing 😊😊
Bhai Har jagah exist karega limit except zero kyuki tum koi aur no. Lo let 1 to x→1+ ya x→1- dono me ek hi answer aaega ek hi value diya hai na
Ise questions me bas intervals change jaha hote hai wahi pe check kiya jata hai
Bro's calculation is faster than any super car....!! Dyaaaaam...!! 😭🤌
Your teaching style is same as Ashu sir 😂
Ek question ka answer 108/7 correct tha toh aapne 162/7 nikala 😂😂😂😂😂
ha
🤣🤣
@@notopupgamer5141 another brilliant 😂
16:26 sir 3+3=6 not 9
Sir pls check the answer of the que x⁴-81/2x²-5x-3 the final ans is 108/7
yess mera bhi wahi aa raha hai
16:50 16:51 16:51 16:51 16:51
*At **17:57** 0/0 is undefined not 0*
2:00 class start
24:39🔥
34:00 mistake found
Answer is 5 and not 3/2.
If we reduce both equations we will get
x^5-1/x-1
= 5(1)^4
= 5 ans.
Same ans as in ncert
Bro Answer is 3/2 not 5
16:21 sir ans 18 ayega kyuki upar 3+3=6 hoga aap 9 likh diye ho galti se
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Bhai kisko ya nhi lagta hai ki ye Ashu sir ka judwa bhai hai
sir 16:21 pe 3+3 = 6 hoga
Han bhai
41:57
42:32 leaving a timestamp to start again after practice
16:26 mai (x+3) ha our x=3 so answer 6 hai 9 nahi sir ❤
16:16 mistake
Kis kis ko probability padhna hai to like karo❤
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Sir aapne formula me limx-->0 sinx/x=1 kraya😢 so jab question krenge toh usme lim ax--->0 aana chahiye na sir 23:29
Bhai x→0 hoga to directly ax→0 hoga
Bhai basic Formula hota hai 0×any no. = 0 aur yah a ek constant hi hai
At 49:51 there is two questions first the value of limit x - 0 and limit x-1
29:33 mtlb kaise bhi answer la Dena hai bs😐....rule left the chat✅
in 28:41 sir sin0=0 so cosc0 is not 0 rather it is undefined
You are the teacher for making the future of today's children that are in 11 standard you are the teacher not for destroy the future of today's children
24:40 Sir prerajulisation means that it is a mental purification process that involves training a subject to lose all fears of the mind and body
Farhan nitrate is Fh(NO3)2
Sir these words have meaning. In the movie they just show like this but in real they are words
💀💀 i dont know where you read this from but it is wrong. Those words does not exist in real life.
Ye faf du plessis jaise lagte h 😅
16:28 something went wrong
You are great sir ❤❤😊
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lim x -> 0 (xcos x - sin x)/(x ^ 2sin x)
Sir ye question solve kar dijiye please 🙏. without using L hospital rule
Sir 29:43 in the solution 1-cos x / x h Cos x b 1 hota h to 1-1 =0 and upon m x h to ye to 0/0 form hui na
yess
Formula
Nhi abhi jo sir ne peeche slide mai 3rd wala cos ka formula lagaya tha 1-cosx/x = 0 woh put Kara hai yaha pe isliye yeh final answer hai aur 0/0 form nhi bani isme answer sirf 0 hai
There may be some calculative errors.. ofcourse we can correct it during practicing the question...But the simplicity with which sir taught the chapter .... Awesome..... Concepts CLEAR.....Great lecture 😊😊😊😊😊😊🎉❤😊😊😊
18:53 sir ji tiranga ka colour bana dia👍🇮🇳
13:00 we can take x+or- (opposite singh of a) will be problem creator
16:24 I think Aapka Answer galat hai sir (x+3) so x=3 then 3+3=6 hoga na aapne 9 likha hai
19:23 yaad rkhoge toh achi baat hai nhi rkhoge toh bohot achi baat h
after watching all the videos on this topic now i got the best video for this topic and easy understandable tricks
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16:23 sir ans 108/7 hoga
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Cosec (0) = not defined sir ! Not zero 28:41
Can't believe there aren't any more comments saying this!
22:09 here another way is just to take a/b common then evaluate
Your teaching skills are toooooo good 💯
29:37 sir , ye question mein final ans 0/0 ki form mein hai toh aage toh solve karna padega na.aapne direct 0 answer likh Diya hai galti se
There is a identity na, limx tends to 0 1-cosx/x=0 that's why directly 0 has been written there..
16:21 108/7
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45:00
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42:01 For Personal Reference.
49:50 sir iss question may answer 3 and 6 hai
Thanks you sir❤ 17:24
Sir it's x+3 = 3+3 = 6 and answer is 108/7
Thanks for mentioning,,,I'm searching for it.....:))))
suggestion:- Never should distracted by someone ...😃
Lim x→0 [sinx (cotx - cosx)]/cos^3x
16:20 sir (3+3)=9
kbse hone laga 😅
53:25 Sir it was just a half part of that question😊😊
31:01 x->0 hoga sir
I am cooked 💀💀
16:26 yha par 6 hoga 9 nhi
Thank you sir
Sir mistake ho gayi 3+3=6 hota hai 9 nahi
28:01 Sir yahan aapne sinx ko x se divide kar diya or into kar diya lekin sin0 ki value toh 0 hi hoti hai.
40:18
26:17 pr 2common kaise aaya??? please reply