Thank you. I have watched 6 videos on this topic, and this is the first one that explained these concepts in a way I could understand. Much appreciated!
Yes because for the relation to be transitive you need (aRb ^ bRc) => aRc so the proposition is p => q so this is true if you hve q or not p and in R3 you don't p so the proposition is true therefore transitive.
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Thank you. I have watched 6 videos on this topic, and this is the first one that explained these concepts in a way I could understand. Much appreciated!
Big thanks. Much appreciated.
Thank you! It really helps a lot!
Thanks for the vid bro🙏🏾
What are some other math youtube channels you like?
I really like Aleph 0
Thanks a ton for doing this, but is R3 really transitive? I love your explaining and your good mood ^^. Thanks again.
Yes because for the relation to be transitive you need (aRb ^ bRc) => aRc so the proposition is p => q so this is true if you hve q or not p and in R3 you don't p so the proposition is true therefore transitive.
@@mkmc94 Thanks a lot, I appreciate your response. Very kind of you.
😘😘😘