There is a much ezier way to this btw Man I will write it down Let the quetion be 1.45_8_(_x_,symbolises bar) Let 1.45_8_=X Therefore, 100X=145._8_ & 1000X= 1458._8_ Therefore, 1000x - 100x=145._8_ - 1458._8_ 900x=1313 x=1313/900 is the fraction *edit* I used a calculator and got the same answer
This is really helpful thx.
You're welcome!
Very helpful. Thank you
You are welcome Kalyani!
Thank you very much I understand how to convert 😘😘😘😘😘
You're very welcome!
This saved me tysm
You're welcome!
for personal reasons: 3:18
김subliminals bless your soul
Yes! thank you just what I needed
There is a much ezier way to this btw Man I will write it down
Let the quetion be 1.45_8_(_x_,symbolises bar)
Let 1.45_8_=X
Therefore, 100X=145._8_ &
1000X= 1458._8_
Therefore,
1000x - 100x=145._8_ - 1458._8_
900x=1313
x=1313/900 is the fraction
*edit* I used a calculator and got the same answer
You should have written the derivation for this man. It is pretty ez
What would happen with .2522222
227/900 Use the same process. What happens when the repeating number is bigger than the non repeating number?
Btw I'm proud of your type of maths teacher
Sorry by watching the doubtnut app ad. I'm going to get my answer from there