what u said is for (n/d) inc. there is a (n/(n+d)) dec from the other side. that's how u get 1/4 inc from N = 1/5 dec from 150 which is 30. 150-30=120.
@@duke7571 Previous number ko x assume kar lo. Ab x 25% se increase ho gaya haii so agar pehle x 100% hoga to abb wo 125% ho gaya haii. To ab equation banalo ki x ka 125%=150 So x= 150×100÷125 This will give 120
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Iss better if there is an increase of 1/4 we can directly reduce it by 1/5 (shortcut)
what u said is for (n/d) inc. there is a (n/(n+d)) dec from the other side. that's how u get 1/4 inc from N = 1/5 dec from 150 which is 30. 150-30=120.
Sorry sir but nothing can beat lord unitary method
Can u explain it?
Just take 150 =125% then you are required to find out 100% . So just use cross multiplication ( unitary method) @@duke7571
Real🗿
Are yar koi explain bhi kar do 😅
@@duke7571
Previous number ko x assume kar lo.
Ab x 25% se increase ho gaya haii so agar pehle x 100% hoga to abb wo 125% ho gaya haii.
To ab equation banalo ki x ka 125%=150
So x= 150×100÷125
This will give 120
Thank you Sir for trick
Thank you sir 😊
Just bring the 1.25 on rhs, and 150/1.25 will get you the same answer can be done on calculator in one sequence
Isse Acha product constancy table use Karo directly answer miljayga.
If 125% is 150
Then 100% is how much...
Cross multiplication..simple
Pin the comment..😎
Nice brother
Sir 5 kaise aaya
n =1
1+1/4 = 5/4